similar to: Help on variable ranking

> Dear R experts, >I am sorry for my inability. >I have the following dataset: > Qtot Itot >1 73 684 >2 64 451 >3 71 378 >4 65 284 >5 47 179 >6 31 117 >7 19 69 > >Now I need to perform Monte Carlo Pertutation test underlaying the following condition. > > >Condition > >In order to choose randomly (5000 times) for the Qtot

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Using platform x86_64-pc-linux-gnu arch x86_64 os linux-gnu system x86_64, linux-gnu status major 2 minor 13.0 year 2011 month 04

I have a setup of asterisk 1.6 in one box and asteirsk 1.4 in another. I can send recieve faxes from both boxes fine to and from pstn. But the faxing between 1.6 and 1.4 extensions does fail. Any ideas please ? -- Thank You Amit Nepal

Dear R Users! I&#39;m new in R! I&#39;ve got a data.frame. For example:a<-data.frame(cbind( 0:1, 1:10)) X1 X2 1 0 1 2 1 2 3 0 3 4 1 4 5 0 5 6 1 6 7 0 7 8 1 8 9 0 9 10 1 10 Firstly i want to create combinations from X2, for example:combn(a$X2,2) It&#39;s ok, butsecondly I would like to get combinations from those X2 numbers only , where X1= 0. Could

Dear all I am trying to learn R I was trying to calculate standard deviation here are the commands and outputs in R > sd(Ht_cm[type=='SD'])[1] 3.283605> sd(Ht_cm[from_treeline=='above'])[1] 16.83289> sd(Ht_cm[type=='SD'][from_treeline=='above'])[1] NA> the problem is that, i could not understand why the third command could not give any result.

Dear R-users, I have a dataset as like below, and I want to subtotal the values of rice,wheat and maize by year for each fid. fid      year     rice     wheat      maize ------------------------------------------------ 1        1995      5        NA           NA 1        1995      NA        3           NA 1        1995      NA       NA           2 1        1996      4        NA           NA 1  

Dear all I was trying to put a title for my plot, but i got this result, > x11(width=10,height=5,title="seedling");par(mfrow=c(1,2))Error in x11(width = 10, height = 5, title = "seedling") : unused argument(s) (title = "seedling")> The title is not taking How can i give a title for the plot (where in need to make 2 plots within a window of x11() ) thanking

Dear all, I have tried a lot of things to make broadvoice work with asterisk , but I failed each time. Please suggest a good service providers that I can use with asterisk for outbound and inbound calls. -- With regards, Vicky Shrestha System Director WorldLink Communications Jawalakhel , Kathmandu, Nepal

Hello R-users,   The below is a snippet of my data:   fid crop year value 5_1_1 SWHE 1995 171 5_1_1 SWHE 1997 696 5_1_1 BARL 1996 114 5_1_1 BARL 1997 344 5_2_2 SWHE 1995 120 5_2_2 SWHE 1996 511 5_2_2 BARL 1996 239 5_2_2 BARL 1997 349   Here, I want to create dummy variables with the names of the content of a column 'crop' in a way

Dear All, Hans Borchers and I have been trying to compute "exact" derivatives in R using the idea of complex-step derivatives that Hans has proposed. This is a really, really cool idea. It gives "exact" derivatives with only a minimal effort (same as that involved in computing first-order forward-difference derivative). Unfortunately, we cannot implement this in R as the

Hello, Having a boolean *.weekend?* on the Date class would be a good feature. It will basically do this: saturday? || sunday? Makes the code cleaner and easier to read. -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Core" group. To unsubscribe from this group and stop receiving emails from it, send an email to

Dear R help, I'm having some trouble with model formulas for the ols function in the rms package. I want to have two variables represented as restricted cubic splines, and also include an interaction as a product of linear terms, but I get an error message. library(rms) d <- data.frame(x1 = rnorm(50), x2 = rnorm(50), y = rnorm(50)) ols(y ~ rcs(x1,3) + rcs(x2,3) + x1*x2, data=d) Error in

Hi all I'm doing some things with a colleague comparing different sorts of models. My colleague has fitted a number of glms in Genstat (which I have never used), while the glm I have been using is only available for R. He has a spreadsheet of fitted means from each of his models obtained from using the Genstat "predict" function. For example, suppose we fit the model of the type

Sirs, I am a newbe jumping to advance routing and traffic control. I work for one of the leading isp in kingdom of Nepal. My goal is to do bandwidth management for our lease line customer so that they could use their allocated bandwidth only. Bgp and ospf is implemented as a routing protocol. All routers are cisco routers. There are about 16 routers some are with highly danced ports. No Linux box

hi, i am having callerid problems with *. i have the callerid from my telco and it shows up in my normal phone when i connect it directly to the line but if i connect the same phone thru * server the callerid is not shown. i am using X101p and tdm400p. i have everything defined in my zapata.conf well and fine. i finally came to conclusion that this might have happened due to the registration of

dear all i am trying to perform t-test (t.test) in R here i am putting the commands and answer i got > t.test(Ht_cm[from_treeline=='above'][type=='SD'],Ht_cm[from_treeline=='below'][type=='SD']) Welch Two Sample t-test data: Ht_cm[from_treeline == "above"][type == "SD"] and Ht_cm[from_treeline == "below"][type ==

Greetings. I've written a convenience function for multicollinearity diagnosis. I'd like to report to the user the formula that is used in a regression. I get output like this: > mcDiagnose(m1) [1] "The following auxiliary models are being estimated and returned in a list:" [1] "`x1` ~ ." formula(fmla)() [1] "`x2` ~ ." I'd like to fill in the period

Hi, I would like to fit my data with a 4th order polynomial. Now I have only 5 data point, I should have a polynomial that exactly pass the five point Then I would like to compute the "fitted" or "predict" value with a relatively large x dataset. How can I do it? BTW, I thought the model "prodfn" should pass by (0,0), but I just wonder why the const is

Consider the code: x <- seq(0,1,0.2) y <- seq(0,1,0.01) cbind(match(y,x),y) which, surprisingly, doesn't show a match at 0.6! (It gives correct matches at 0, 0.2, 0.4, 0.8 and 1, though) In addition, x[4]==y[61] yields FALSE. (but x[5]==y[81], the one for 0.8, yields TRUE) Is this a consequence of machine error or something else? Could this be overcome? (It works correctly when