similar to: Treatment for Unequal Column Lengths?

Hello, I?ve tried several times to learn R, but have never gotten past a particular gate. My data are organized by column in Excel, with column headers in the first row. The columns are of unequal lengths. I export them as CSV, then import the CSV file into R. I wish to summarize the data by column. R inserts NA for missing values, then refuses to operate on columns with NA. R is importing

I am using levelplot() from lattice with grids that have unequal cell sizes. This means that the boundary between two cells is not always half-way between nodes, as levelplot() assumes. The result is that some cell sizes are rendered incorrectly, which can be painfully obvious if using relatively large cells. Is there any work-around? I am using the conditioning capability of lattice and

Hello, I have a dataset with multiple entries in one field separated by "/" characters. (The true dataset has long names, 20-odd variables, and hundreds of observations.) v1 v2 1 A L 2 A/B M 3 C N 4 D/E/F O 5 A P 6 C L What I would like is to have a dataset that looks like this instead: > my.df v1 v2 1 A L 2 A M 3 B M 4 C N 5 D O 6 E O

If I have two vectors X<-1:10 Y<-1:5 When I combine them using cbind, the shorter one is repeated and both are made of the same length. Is there a methods that does this without duplicating the shorter one. I want to use this to store the data back to a file. Thanks ../Murli [[alternative HTML version deleted]]

Hello- I have run an ANOVA on 4 treatments with unequal sample sizes (n=9,7,10 and 10). I want to determine where my sig. differences are between treatments using a Bonferroni test, and have run the code: pairwise.t.test(Wk16, Treatment, p.adf="bonf") I receive an error message stating that my arguments are of unequal length: Error in tapply(x, g, mean, na.rm = TRUE) :

I'am trying to develop some code if R, which would correspond to what I did in SAS. The data look like: Treatment Replicate group1 GSI Control A 1 0.81301 Control B 1 1.06061 Control C 1 1.26350 Control D 1 0.93284 Low A 2 0.79359 Low B

Hi Everyone, I'm new to programming R and have accomplished my goal, but feel that there is probably a more efficient way of coding this. I'd appreciate any guidance that a more advanced programmer can provide. My goal -- I would like to find the length of the longest word in a string containing many words separated by spaces. How I did it -- I was able to find the length of the

Well fellow R users, I throw myself on your mercy. Help me, the unworthy, satisfy my employer, the ungrateful. My feeble ramblings follow... I've searched R-Help, the R Website and done a GOOGLE without success for a one way ANOVA procedure to analyse data that are both non-normal in nature and which exhibit unequal variances and unequal sample sizes across the 4 treatment levels. My

I have numerous objects, each containing continuous data representing the same variable, movement rate, yet each having a different number of rows. e.g. d1<-as.matrix(rnorm(5)) d2<-as.matrix(rnorm(3)) d3<-as.matrix(rnorm(6)) How can I merge these three columns side-by-side in order to create a table regardless of the difference in length? I wish to analyze the output in a spreadsheet

I'm a newbie for R lang. And I recently came across the "Recycling Rule" when adding two vectors of unequal length. I learned from this tutor [ http://www.r-tutor.com/r-introduction/vector/vector-arithmetics ] that: """""" If two vectors are of unequal length, the shorter one will be recycled in order to match the longer vector. For example, the

Without recycling you would get: u <- c(10, 20, 30) u + 1 #[1] 11 20 30 which would be pretty inconvenient. (Note that the recycling rule has to make a special case for when one argument has length zero - the output then has length zero as well.) Bill Dunlap TIBCO Software wdunlap tibco.com On Tue, Dec 12, 2017 at 9:41 PM, Maingo via R-help <r-help at r-project.org> wrote:

Hi All-- I have generated several 2 column data frames with variable length. The data frames have the same column names and variable types. I was trying to aggregate over the 2nd column for all the date frames, but could not figure out how. I thought i could make them all of equal length then combine them in 1 data frame where i can use aggregate, the formula version Or to put them in a list and

Thank you Pikal and Bert. My apology for posting parts of my previous email in HTML. Bert's suggestion will work but i am wondering if there is an alternative especially in the case where the data frames are big; that is the difference in lengths among them is large. Below is a list of sample date frames and desired result. EK

Hi Your example is rather confusing - partly because HTML formating, partly because weird coding. You probably could concatenate your data frames e.g. by rbind or merge and after that you could try to aggregate them somehow. I could construct example data.frames myself but most probably they would be different from yours and also the result would not be necessary the same as you expect. You

Then you need to rethink your data structure. Use a list instead of a data frame. The components of a list can have different lengths, and the "apply" family of functions (lapply(), etc.) can operate on them. Consult any good R tutorial for details. Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it."

Hi, How to rbind these vectors from a list?: > l <- list(a = c(1, 2), b = c(1, 2, 3)) > l $a [1] 1 2 $b [1] 1 2 3 > do.call(rbind, l) [,1] [,2] [,3] a 1 2 1 b 1 2 3 Warning message: In function (..., deparse.level = 1) : number of columns of result is not a multiple of vector length (arg 1) > -J

I'm a bit of an amateur R programmer. I can do simple R scenarios but my handle on complex grammatical issues isn't steady. I have 12 CSV files that I've read into dataframes. Each has 8 columns and over 2000000 rows. Each dataframe has data associated by time component and a date component in the format of: X.DATE and then X.TIME X.DATE is in the format of MMDDYYYY and X.TIME is

Hello , I am having some difficulty reading a CSV file of unequal record length in R . The data has 26 columns and do not have header and is generated from a R syntax - write.table(schat,"schat.csv", sep=",", col.names=FALSE, append = TRUE) 1.0,1.0,0.0,0.1,0.1,0.1,0.2,0.2,0.3,0.3,0.4,0.4,0.5,0.6,0.7,0.8,0.9,1.0,1.2,1.5,1.9,2.7,,,,

Classification: UNCLASSIFIED Caveats: NONE Thanks for your quick response. The program you mentioned below available from R is based on number of runs (up or down) not based on a longest length of runs of same events. To be more specific, for example, from a series, HHTHTTTTHHH, the number of runs are 5, and the longest length of runs of the same events is 4. I'll check for the website you

Hello, I have some patient data for my masters thesis with three groups (n=16, 19 & 20) I have completed compiling the results of 7 tests, for which one of these tests the variances are unequal. I wish to perform an ANOVA between the three groups but for the one test with unequal variance (<0.001 by both bartlett and levene's test) I am not sure what to do. I thought i would run