similar to: counties in different colours using map()

Dear all, I would like to get the order of the values in a vector. I have tried rank(), order() and searched the archive, though without success. Here is an example of a try x= c(20,30,50,40,60,10) cbind(sort.list(x),x) x [1,] 6 20 [2,] 1 30 [3,] 2 50 [4,] 4 40 [5,] 3 60 [6,] 5 10 but I was hoping to get this: x [1,] 2 20 [2,] 3 30 [3,] 5 50 [4,] 4 40 [5,] 6 60 [6,] 1 10 I'm

Dear all, Does anyone know of a function that calculates the area of the outer polygon constructed from a data frame with co-ordinates? For example, library(splancs) test = rbind(c(0,0), c(10,0),c(10,10),c(0,20)) plot(test) areapl(test) [1] 150 This is OK, but I want the same area to be returned (150) when adding yet another co-ordinate in the middle of the polygon: test = rbind(c(0,0),

Dear all, I try to first link data in a data.frame() to a (polygon) read.shape() object and then to plot a polygon map showing the data in the data.frame. The first linking is called "link" in ArcView and "relate" in ArcMap. I use the code shown below, though without success. Help with this would be greatly appreciated. Thanks! Tord require(maptools) # Read shape file

Dear all, I'm new to matrix operations in R. I couln't find a solution to the following problem among earlier help mails or in An introd to R, I guess because the question is really basic. I want to extract all above the diagonal, i.e. from 1 2 3 4 1 0 26 49 49 2 26 0 44 40 3 49 44 0 21 4 49 40 21 0 I want 26 49 44 49 40 21 Thanks in advance! Sincerely, Tord

Dear all, A question related to the following has been asked on R-help before, but I could not find any answer to it. Input will be much appreciated. I got an unexpected sign of the "slope" parameter associated with a covariate (diam) using zeroinfl(). It led me to compare the estimates given by zeroinfl() and hurdle(): The (significant) negative estimate here is surprising, given

Dear all, I want my PhD thesis which I hand in tomorrow to look even nicer: Does polymap in the splancs library not allow horizontal plotting of y-labels? I have tried polymap(studyarea, xlab = "x (m)", ylab = "y (m)", las = 1) but it doesn't change the labels? Mayby some function in library(spatstat) support las? Thanks! Sincerely, Tord

Dear all, I get an error message when I use polr() in MASS. These are my data: skugg grupp frekv 4 1 gr3 0 5 2 gr3 3 6 3 gr3 6 10 1 gr5 1 11 2 gr5 12 12 3 gr5 1 > > summary(polr(skugg ~ grupp, weights=frekv, data= skugg.cpy1.dat)) Error in optim(start, fmin, gmin, method = "BFGS", hessian = Hess, ...) :

Dear all, As part of a larger function, I am randomly removing rows from a data frame. The number of removed rows is determmined by a Poisson distribution with a low mean. Sometimes, the random number is 0, and that's when the problem starts: My data frame: > temp occ x y dbh age 801 0 2977.196 3090.225 6 36.0 802 0 2951.892 3083.769 8 40.6 803 0 2919.111

Dear all, For the past three hours I have tried simplify a data frame. I would be really happy if someone could help solving this, I'm sure simple, problem. I want to "aggregate" the data frame: ObjektID BalteNummer Baltessegment S.13 S.13.1 S.13.1.2 S.13 S.13.1 S.13.1.3 S.13 S.13.2 S.13.2.1 S.13 S.13.2 S.13.2.2 S.13 S.13.2 S.13.2.3 S.13 S.13.3 S.13.3.6 S.13 S.13.3 S.13.3.7

Dear all, Is it possible to somshow plot text as italic AND bold. I tried font=c(2,3) in text(), but it doesn't work. It seems like the latter value is used. Thanks in advance! Sincerely, Tord ----------------------------------------------------------------------- Tord Sn?ll Avd. f v?xtekologi, Evolutionsbiologiskt centrum, Uppsala universitet Dept. of Plant Ecology, Evolutionary Biology

Dear all, I try to rearrange my ref. database (now in Excel!! :( ) for importing it into a reference manager program (RIS format). My file basically look like this [3,4]-matrix: rbind(c("a", "b", "c", "d"), c("e", "f", "g", "h"), c("i", "j", "k", "l")) [,1] [,2] [,3]

Dear all, Last autumn there was some discussion on the list of the warning Warning message: fitted probabilities numerically 0 or 1 occurred in: (if (is.empty.model(mt)) glm.fit.null else glm.fit)(x = X, y = Y, when fitting binomial GLMs with many 0 and few 1. Parts of replies: "You should be able to tell which coefficients are infinite -- the coefficients and their standard errors will

To whom it may concern, I get the following message when I run my function: Warning message: multi-argument returns are deprecated in: return(call.fn, repl, time, from, to, last.year, occup.m, ant.occ.m, > version platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 8.0

Dear all, I have divided two vectors: Np.occup97.98<- as.data.frame(cbind(site = levels(sums$site), Np.occup97.98 = sums$Ant.Nptrad97.98/Ant.trad$Ant.trad97.98)) > Np.occup97.98 site Np.occup97.98 1 erken97 0.342592592592593 2 erken98 0.333333333333333 3 rormyran 0.48471615720524 4 valkror 0.286026200873362 However, at a later stage of the analysis I want >

Dear all, I would like to use the values in vegaggr.BLMCMR02$colony str(vegaggr.BLMCMR02) `data.frame': 1678 obs. of 3 variables: $ vegtype : Factor w/ 27 levels "2010","2020",..: 3 4 5 19 4 5 19 5 $ colony : Factor w/ 406 levels "0","1","10","100",..: 1 1 1 1 2 2 2 $ Totvegproparea: num 0.00055 0.03956 0.95705

Dear all, I am taking a course in GLM given by a devoted SAS user. He has given us a homework where a mixed GLM with a logistic link and binomially distributed observations should be fitted. I know of the library nlme for mixed effect models but as I understand it, one cannot choose between different links and distributions in the functions provided there. I have so far managed very well with

Dear all, I have a tree data matrix. For some trees I lack info about tree species, but I want to set them to be spruce. For some reason the tree species names on the remaining (non-NA) rows are changed into numbers (that I do not recognise). I guess that ifelse is not the correct function to use, but I have not found any better one in my searches. Thanks in advance! Sincerely, Tord >

Dear all, I try to plot a logstic regression model as follows: Valkror<- read.table("Valkror.txt", header=T) np.bark<- glm(Npinc~bark, family=binomial, data=Valkror) plot.formula(np.bark$fitted.values~ Valkror$bark) The above looks nice but I want to connect the points with a line so I try: plot.formula(np.bark$fitted.values~ Valkror$bark, type="b") but it gives a

Dear all, I think that what I want is an as.data.frame.table-object, but see error message below. I have a data frame with one tree per row, diaclass tells if it is a small, mid or large tree > cpy.tradart[1:5, ] ObjektID diaclass 1 AX.Grb.1 bigdia 2 AX.Grb.1 middia 3 AX.Grb.1 middia 4 AX.Grb.1 smalldia 5 AX.Grb.1 middia > I want a data frame telling no of trees per diameter

Dear all, I have discovered that there are many things that I used to do in my GIS which are easily done directly in R, for example calculating interpoint distances using geoR and pick out points inside a polygon using splancs. I now wonder, is there a function to create a line object like a watercourse and then calculate the distances between many points in space and this line? I couldn't