Displaying 20 results from an estimated 4000 matches similar to: "how to create data.frame with dynamic count of values"
2010 Nov 22
2
how to loop through variables in R?
After importing a table with "M" variables and "N" records, I'd like to
calculate chi-square statistics, say, between N1, N2; N1, N3, ..., N1, Ni,
and then N2, N3, ... N2, Ni, ..., Ni-1, Ni. Two loops should be ok but the
manual & online help don't show a systematic way to do so but instead show
hard-code examples so users have to type in the names themselves one
2017 Jun 06
4
integrating 2 lists and a data frame in R
Dear Bert,
thank you for your response. here it is the piece of R code : given 3 data
frames below ---
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"),
2011 Apr 01
1
filled contour plot with contour lines
I'm stumped, can anyone find my error in this sequence.
for(j in 1:(varsize[4]-1))
temp <- get.var.ncdf(nc=input,
varid="p_foraging",c(1,1,j),c(varsize[1],varsize[2],1))
filled.contour(x, y, temp, color = terrain.colors,
plot.title = title(main = paste("Everglades Wood Stork
Foraging Potential \nYear", (2000+j)),
xlab =
2017 Jun 06
0
integrating 2 lists and a data frame in R
Hi Bogdan,
Kinda messy, but:
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))
2017 Jun 06
2
integrating 2 lists and a data frame in R
> On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote:
>
> Hi Bogdan,
> Kinda messy, but:
>
> N <- data.frame(N=c("n1","n2","n3","n4"))
> M <- data.frame(M=c("m1","m2","m3","m4","m5"))
> C <-
2008 Jul 09
1
netCDF to TIFF
Greetings R users!
I am working with the ENSEMBLE climate data (10 min resolution daily
temperatures images for all of Europe 1950-2006). The data comes
packaged in a single netCDF file. I would like to read the data in and
export a subset (2002-2006) as geotiffs (one image per day). So far, I
can successfully read in the data and view the images within an R
display window. However, I have yet to
2010 Dec 29
2
How to create an array of lists of multiple components?
Hi,
how can I create an array of lists of three components?
This approach does not work:
n1 <- 2
n2 <- 4
n3 <- 5
res <- array(rep(vector("list",3), n1*n2*n3), dim = c(n1,n2,n3))
res[1,1,1] # is not a list with three components...
The goal is that res[1,1,1] is a list with three components. Also, appending the
components didn't work. For example, I tried:
component
2010 Jul 05
2
Function to compute the multinomial beta function?
Dear R-users,
Is there an R function to compute the multinomial beta function? That is, the normalizing constant that arises in a Dirichlet distribution. For example, with three parameters the beta function is Beta(n1,n2,n2) = Gamma(n1)*Gamma(n2)*Gamma(n3)/Gamma(n1+n2+n3)
Thanks in advance for any assisstance.
Regards,
Greg
[[alternative HTML version deleted]]
2007 Apr 11
2
sem is not "taking" the model
A strange problem with sem:
I downloaded the sem library and then, I specified my simple measurement model (below). I highlighted it and ran it. It ran, but it did NOT tell me "22 lines read". And nothing works after that - it looks like it runs, but it does not produce anything...
Did I make a mistake somewhere in the model? (notice, TIME has only 1 indicator - t1, and I fixed t1's
2010 Jan 13
4
a question about deleting rows
I have a file like this:
id n1 n2 n3 n4 n5 n6
1 3 4 7 8 10 2
2 4 1 2 4 3 10
3 7 0 0 0 0 8
4 10 1 0 0 2 3
5 11 1 0 0 0 5
what I want to do is: only if n2=0 and n3=0 and n4=0 and n5=0 then delete
the row. how can I do that?
thank you,
karena
--
View this message
2017 Jun 06
0
integrating 2 lists and a data frame in R
Thank you David. Using xtabs operation simplifies the code very much, many
thanks ;)
On Tue, Jun 6, 2017 at 7:44 AM, David Winsemius <dwinsemius at comcast.net>
wrote:
>
> > On Jun 6, 2017, at 4:01 AM, Jim Lemon <drjimlemon at gmail.com> wrote:
> >
> > Hi Bogdan,
> > Kinda messy, but:
> >
> > N <-
2012 Feb 25
5
which is the fastest way to make data.frame out of a three-dimensional array?
foo <- rnorm(30*34*12)
dim(foo) <- c(30, 34, 12)
I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame.
I know how this can be done in a very slow way using for loops, like this:
x <- rep(seq(from = 1, to = 30), 34)
y <- as.vector(sapply(1:34, function(x) {rep(x, 30)}))
month <- as.vector(sapply(1:12,
2017 Jun 06
1
integrating 2 lists and a data frame in R
Simple matrix indexing suffices without any fancier functionality.
## First convert M and N to character vectors -- which they should
have been in the first place!
M <- sort(as.character(M[,1]))
N <- sort(as.character(N[,1]))
## This could be a one-liner, but I'll split it up for clarity.
res <-matrix(NA, length(M),length(N),dimnames = list(M,N))
res[as.matrix(C[,2:1])] <-
2012 Jun 04
1
simulation of modified bartlett's test
Hi, I run this code to get the power of the test for modified bartlett's
test..but I'm not really sure that my coding is right..
#normal distribution unequal variance
asim<-5000
pv<-rep(NA,asim)
for(i in 1:asim)
{print(i)
set.seed(i)
n1<-20
n2<-20
n3<-20
mu<-0
sd1<-sqrt(25)
sd2<-sqrt(50)
sd3<-sqrt(100)
g1<-rnorm(n1,mu,sd1)
g2<-rnorm(n2,mu,sd2)
2011 Jul 27
3
Reorganize(stack data) a dataframe inducing names
Dear Contributors,
thanks for collaboration.
I am trying to reorganize data frame, that looks like this:
n1.Index Date PX_LAST n2.Index Date.1 PX_LAST.1
n3.Index Date.2 PX_LAST.2
1 NA 04/02/07 1.34 NA 04/02/07 1.36
NA 04/02/07 1.33
2 NA 04/09/07 1.34 NA 04/09/07
2017 Jun 06
1
integrating 2 lists and a data frame in R
Here's another approach:
N <- data.frame(N=c("n1","n2","n3","n4"))
M <- data.frame(M=c("m1","m2","m3","m4","m5"))
C <- data.frame(n=c("n1","n2","n3"), m=c("m1","m1","m3"), I=c(100,300,400))
# Rebuild the factors using M and N
C$m <-
2008 Dec 10
3
AFR healing problem after returning one node.
I've got configuration which in simple includes combination of afrs and
unify - servers exports n[1-3]-brick[12] and n[1-3]-ns and client got
cluster configuration:
volume afr-ns
type cluster/afr
subvolumes n1-ns n2-ns n3-ns
option data-self-heal on
option metadata-self-heal on
option entry-self-heal on
end-volume
volume afr1
type cluster/afr
subvolumes n1-brick2
2011 Sep 14
1
ruby to solve a physics question
I am trying to solve one of my graduate level physics problems with
ruby...
Here is what I have so far...
a6=0.0
for n1 in -10..10
for n2 in -10..10
for n3 in -10..10
if n1!=0 and n2!=0 and n3!=0
p=Math.sqrt(n1**2+n2**2+n3**2+n1*n2/1.414+n1*n3/1.41+n2*n3/1.414)
a6+=(1/p)**6
end
end
end
end
puts a6
What I''ve got here is a 10x10x10 face-centered
2020 May 04
2
"Earlyclobber" but for a subset of the inputs
Hi all,
I'm working on a target whose registers have equal-sized subregisters and
all of those subregisters can be named (or the other way round: registers
can be grouped into super registers).
So for instance we've got 16 registers W (as in wide) W0..W15 and 32
registers N (as in narrow) N0..N31. This way, W0 is made by grouping N0 and
N1, W1 is N2 and N3, W2 is N4 and N5, ..., W15 is
2017 Jun 06
2
integrating 2 lists and a data frame in R
Dear all,
please could you advise on the R code I could use in order to do the
following operation :
a. -- I have 2 lists of "genome coordinates" : a list is composed by
numbers that represent genome coordinates;
let's say list N :
n1
n2
n3
n4
and a list M:
m1
m2
m3
m4
m5
2 -- and a data frame C, where for some pairs of coordinates (n,m) from the
lists above, we have a