similar to: writing function with ,... )

Hi to all I would to determinate whether bits is a binary code and I would to find out the which bit is set to 1 bits <-"00110110" I found to detect whether there are only numbers all.digits(bits) but is there any function to detect whether there are only 0 and 1 in the string And how could I get the f.e the third "bit" from the right hand side With regards Carmen

Hi to all, I have some problems to get the times-scale to the x-axis the times are coming from an excel sheet f. e [1] "0:01:00" "0:02:00" "0:03:00" "0:04:00" "0:05:00" "0:06:00" "0:07:00" [8] "0:08:00" "0:09:00" "0:10:00" "0:11:00" "0:12:00" "0:13:00"

Hello r-group I have a question to the ks.test. I would expect different values for less and greater between data1 and data2. Does anybody could explain my point of misunderstanding the function? data1<-c(8,12,43,70) data2<- c(70,43,12,8) ks.test(data1,"pnorm") ks.test(data1,"pnorm",alternative ="less") #expected < 0.001

Hi to all, maybe the last question was not clear enough. I did not found any hints how to decide whether it should use lower.tail or not. As it is an extra R-feature ( written in http://finzi.psych.upenn.edu/R/Rhelp02a/archive/66250.html ) I do not find anything about it in any statistical books of me. Regards Carmen

Hi to all, I found in the R-help archive how to calculate the p-value for a gee result: http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html but there are two questions (I am afraid they are basic questions ...) 1. why is the result multiplicated with 2 2. how could I decide between lower.tail =TRUE and FALSE: example:

Dear all, I'd like tweaking the ... arguments that one user can pass in my function for fitting a model. More precisely, my objective function is (really) problematic to optimize using the "optim" function. Consequently, I'd like to add in the "control" argument of the latter function a "ndeps = rep(something, #par)" and/or "parscale =

This is was something like a request for your comments, thoughts on the topic... Many of you will know that the "..." (aka \dots) argument is very useful for passing ``further graphical parameters'', but can be a pain when itself is passed to too many plotting functions inside your own function. An artificial example being myplot <- function(x,y, ...) { plot(0:1, 0:1,

Hi all, I have the folloing data table %%%%%%%%%%%%%%%%%% Type BATCH RESPONSE SHORT A 22 SHORT A 3 SHORT A 16 SHORT A 14 SHORT A 8 SHORT A 27 SHORT A 11 SHORT A 17 SHORT B 12 SHORT B 17 SHORT B 11 SHORT B 10 SHORT B 16 SHORT B 18 SHORT B 15 SHORT B 13 SHORT B 9 SHORT B 20 SHORT C 4 SHORT C 16 SHORT C 32 SHORT C 11 SHORT C 9 SHORT C 25 SHORT C 27 SHORT C 12 SHORT C 26 SHORT C 7 SHORT C 14 LONG A

Hi R-helpers, I have a character string, for example: "lm(y ~ X2 + X3 + X4)" from which I would like to strip off the leading and trailing quotation marks resulting in this: lm(y ~ X2 + X3 + X4) I have tried using gsub() but I can't figure out how to specify the quotation mark using a regular expression. Alternatively, I would like a function that lets me delete the leading

Hi every one. I have a exponential function (3 fitting parameters) that I would like to use to produce data (6 series) without having to use a loop. Here wl = seq(300,500,1) k1 = c(1.2e-6, 4.9e-6, 9.6e-6, 2.7e-10, 6.7e-8, 7.44e-6) k2 = c(726, 352, 128, 5232, 1538, 128) k3 = c(-176, -224, -257, 88.7, -111, -256) stations = c('R5d', 'R5a', 'R9', '108',

before I start, two notes. I alredy sent this mail to the other mailing list, but no answer has came back. also, I'm not subscribed to this list, so please cc me the answers. now, to business. I have a problem but I don't know exactly what. Or why, better. The scheme is like this: I don't have a direct connection to the inet, except for ssh to certain range of ip's at a

Greetings R-ians: I know what doesn?t work but I don?t know why, nor how to remedy things. I have a character string containing "." which I want to replace with " " gsub(".", " ", file.label) replaces the every character with a blank. However gsub(".xls", " ", file.label) replaces ".xls" with a blank as expected. It appears

Dear r-list folks, I have a problem which has been bugging me for a while now and I was hoping someone out there might be able to help. If I have a user-defined function with an indeterminate number of arguments, using the well-known "..." construct, how can I get the function to return the names of the items which were the arguments of the function as part of the function's

i was wondering how a blog db has grown by about 15 mb in a week or two. it turns out its the sessions table.. so ive tried this: class ApplicationController.. session :off end class AccountController session :only, :login end and now, its impossible to login, and nothing ever appears in the session table. is this the right approach? i dont want to weed out the sessions with cron, i just

I may be being dopey, I surely am, but I'm baffled by this. I've been working, on and off for a few days in R version 2.13.0 (2011-04-13) i386-pc-mingw32/i386 (32-bit) working it through ESS. I've got a dataframe created a couple of days back, during the session: > dim(AllDat) [1] 27270 94 I came back this morning and misremembered my variables and thought I had a variable

Hi, I have a data frame like this: ScoreDoseSex 2.81Dose1M 1.81Dose1M 1.22Dose1M 0.81Dose1M 0.49Dose1M 0.22Dose1M 0.00Dose1M -0.19Dose1M -0.17Dose1F -0.32Dose1F -0.46Dose1F -0.58Dose1F -0.70Dose1F -0.81Dose1F -0.91Dose1F -1.00Dose1F -1.77Dose2M -1.85Dose2M -1.93Dose2M -2.00Dose2M -2.07Dose2M -2.14Dose2M -2.20Dose2M -2.26Dose2M -2.32Dose2F -2.38Dose2F -2.17Dose2F -2.49Dose2F -2.54Dose2F

Hello, I have setup a centos server running 5.5 and I have a problem with the FTP settings. Currently I have two FTP accounts based on that server, they lead to: /home/bella /home/carmen Currently the FPT accounts starts in the home directory when they are logged in. But they are able to see all directories on the server. What can I do to make sure they cant come out of there home directory?

I can't seem to find the command to find the least squares regression line for my bivariate data set. Can you please help? ~Carmen

Hi to everybody! I´m just a beginner in R, and I´m trying to replace values in a distance matrix with a concret condition: replace all values (elements) lower than 4.5 with value=18. I´ve tried this, but it doesn´t work... Dxy would be my 117 x 117 euclidean distance matrix M18 and M4.5 would be 117 x 117 matrices: M18<-matrix(rep(18,13689),nrow=117)

Hello: I have set up samba PDC using samba 3.0.11. When I use the usrmgr.exe tool on NT4 machine to add user to the domain, it prompts and says: "The following error occurred changeing properties of the user mary: fail find the group" (The error msg actually appears as Chinese in my computer, I just translate the error message). Then I check with the samba log file and it said: group