similar to: advanced plotting

Displaying 20 results from an estimated 300 matches similar to: "advanced plotting"

2011 Jan 05
4
Converting Fortran or C++ etc to R
I'm going to try my hand at converting some Fortran programs to R. Does anyone know of any good articles giving hints at such tasks? I will post a selective summary of my gleanings. Cheers, Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz
2006 Dec 18
5
Replacing values
Hi all, I have to recode some values in a dataset. for example changing all zeros to "." or 999 would be also ok. does anybody know how to do this? thanks in advance. lars -- View this message in context: http://www.nabble.com/-R--Replacing-values-tf2841687.html#a7934402 Sent from the R help mailing list archive at Nabble.com.
2006 Nov 08
2
chisq test with for loop
Hi all. i am desperating. i need a matrix of p.values from an chi square test. i had it already work but than my computer collapsed when taking the whole data set 800x260 into account. i am sure it looked like this but it doesn't work now. can anybody help me? thanks in advance. x=read.table("C:\...) d=ncols(x) z<=matrix(0,d,d) for(i in 1:d) for(j in 1:d)
2002 Jan 09
2
Passing a password from a program to ssh
Hi all Probably this question was asked before, but I didn't find anything in the FAQ or in the archives. I've written an programm that connects to a SSH server and communicate over the SSH protocol with a SSH subsystem. SSH now shows a prompt where the password should be typed in. If an error occurs (protocol error or so) the programm must reconnect to the server and reestablish
2009 Feb 10
1
OT: did the wildfires affect tolstoy.newcastle.edu.au?
Just jumping to conclusions since the site is down as I type (7PM EST). What's the news from that part of Australia -- thus showing my complete ignorance of DownUnder geography.
2008 Mar 06
14
FXS channel banks
Greetings list, I've been asked to provide a system for 200 extensions, most of which will be existing analogue POTS handsets, not IP handsets. I've not really had any experience with large channel banks in the past (since most of our deployments are strictly IP-only to the desk), so I'm at a loss as to which ones are worth looking at. If anyone's had experience using channel
2006 Jan 05
2
Splitting the list
I've changed the heading because this really is another thread. I think it inevitable that there will, in the course of time, be other lists that are devoted, in some shape or form, to the concerns of practitioners (at all levels) who are using R. One development I'd not like to see is fracture along application area lines, allowing those who are comfortable in coteries whose
2008 Mar 05
1
Newbie dialplan: dial 0 for outside line
I just managed to put in a TE410 card in an Asterisk box to work with OnRamp 20(E1 downunder). I am able to dial in but was not able to dial out. Can anyone offer me some advice please? In my extensions.conf, I just put in: [default] ... exten => 0,1,Dial(Zap/g1) and I get this on the console when I dialled 0. -- Executing [0 at default:1] Dial("SIP/5166-b76004f8",
2009 May 10
2
Unintended loading of package:datasets
The dataset package is being loaded apparently by one of the packages that I am using. The loading of the datasets takes a long time and I would like to eliminate it. I thought the datasets were effectively examples so don't understand why they would be required at all. 1) How can I determine what is causing the datasets to be loaded? 2) How can I stop them from doing so? I am using the
2006 Dec 25
1
Higher Dimensional Matrices
Hi all. I want to calculate partial correlations while controlling for one or more variables. That works already fine when I control for example just for x[,1] and x[,2] that gives me one single correlation matrix and i have to to it for x [,1]...x[,10]. That would give me out 10 matrices. Controlling for 2 Variables 100 matrices. how can I run a loop to get f.e the 10 or 100 matrices at once?
2005 May 18
102
I quit.
It is with regret that I announce that Shorewall development and support is officially ended. Sean''s post has finally driven it home to me that in the long term, trying to support a project like Shorewall is impossible for a person of my personality and age. Sean -- please believe that this isn''t about you or your post -- your post was just the proverbial straw on this old
2007 May 01
0
[Fwd: Re: [R-downunder] Beware unclass(factor)] (PR#9641)
It really is unclear what is claimed to be a bug here. But see https://stat.ethz.ch/pipermail/r-devel/2007-May/045592.html for why the bug is not in R: your old and new data do not match. Your fit is to a category. [The problem with the web interface to R-bugs was reported last week: it is being worked on.] On Mon, 30 Apr 2007, r.darnell at uq.edu.au wrote: > This is a multi-part
2004 May 12
0
Asterisk Downunder (Australia & New Zealand)
It seems that there is considerable interest in Asterisk in both Australia and New Zealand. I am trying to gauge how much interest there would be in a get together for Asterisk users & developers downunder. I suggest you get back to me OFF list, so we don't flood the list. Just let me know if a) you think it is a good idea b) when would be a good time (a wide window would be
2006 Feb 10
0
Rails workshop downunder
If there''s any budding Sydney developers that are just starting out with Rails and would like a head start, or if you have some friends you''d like to "enlighten", the first Rails workshop in Australia is being run alongside WebDU on March 1 in Sydney. It''s a half-day event for A$365 and though it''s open to anybody (not just WebDU delegates)
2007 Mar 20
0
[R-downunder] las with stripchart
Hi Ross - I believe I was wrong in thinking that passing via the ... list to stripchart() was ever allowed. Here are patches: Add ... to the argument list Add, at the beginning of the function: pars <- list(...) There are two calls to axis(). Modify these to: axis(1, at = at, labels = names(groups), las=pars$las) axis(2, at = at, labels = names(groups), las=pars$las) Also
2002 Oct 28
4
MS Access and RAID
Hi, We have been having a few problems with a M$ Access DB held on a Samba server Samba version: samba-2.2.4-2N1 We have rebuilt a new server, and transferred the database over to the new box, along with word/excel docs etc. Everything is working fine, except the access database, which is running very very slowly (can be over a minute to open a record). Details are a little sketchy, but it
2006 Aug 30
0
multiple sid's one uid
Howdy all, Does anyone have any good advice for trying to serve to windows clients in a two domain enviroment? There is the possiblilty of users connecting with the same username and password from two different domains. As the accounts are generated from an ldap server, the identical usernames in the two domains share a single uid. Point being since the samba server is in one domain, it
2003 Oct 16
5
Voicemail File permissions
I'm working on an application that monitors, displays and manipulates voice mail messages for individual clients, with an option to click and play in a windows interface. The problem is that I need to create a Samba share that is accessible by the Windows file system object and I don't want to give the share root access. What I need is for the voice mail files to be created with a
2013 Feb 21
3
Ask for help: find corresponding elements between matrix
Dear R experts, I have two matrix (seq & mat) & I want to retrieve in a new matrix all the numbers from mat that =1 (corresponding to the same row/ column position) in seq, or all the numbers in mat that =-1 in seq. - Replace all the numbers with NA if it's not 1/-1 in seq. There are some "NA"s in seq. seq=matrix(c(1,-1,0,1,1,-1,0,0,-1,1,1,NA),3,4)
2006 Mar 01
1
a strange problem with integrate()
Dear all, I am stuck on the following problem with integrate(). I have been out of luck using RSiteSearch().. My function is g2<-function(b,theta,xi,yi,sigma2){ xi<-cbind(1,xi) eta<-drop(xi%*%theta) num<-exp((eta + rep(b,length(eta)))*yi) den<- 1 + exp(eta + rep(b,length(eta))) result=(num/den)*exp((-b^2)/sigma2)/sqrt(2*pi*sigma2)