similar to: a list with row.names = c(NA, 1000)

Hi R users Having both a faster CPU and more memory will boost computing power. I was wondering if only adding more memory (1GB -> 2GB) will significantly reduce R computation time? Taka, _________________________________________________________________ Get FREE company branded e-mail accounts and business Web site from Microsoft Office Live

Dear R-users >prob <- c(0.5,0.4,0.3,0.1,0.0) >cal <- prob * log(prob,base=2) >cal [1] -0.5000000 -0.5287712 -0.5210897 -0.3321928 NaN Is there any way to change NaN to zero ? I did come up with this by applying Ripley's relpy to my previous question cal <-prob*log(pmax(prob,0.00000001),base=2) Any suggestion ? Thank you Taka

Hi R-users I have a data set. There are 10 products and the numbers of people who ranked the products. The format of the data set is productID rank1 rank2 rank3 rank4 rank5 rank6 rank7 rank8 rank9 rank10 ------------------------------------------------------------------------------------------------------- 1 10 2 3 3 6 4 2 5

Hi R users I like to generate some strings (a character vector) in a special way like If i have 5 variables "002.001", "003.001", "003.002", "004.001", "004.002", "004.003", "005.001", "005.002", "005.003", "005.004" so the created string vector's elements are "002.001",

Hi R users I have two variables (X and Y) X <- rnorm(100,.7,.5) Y <- rnorm (100,.3,.1) I like to know whether 1 is between each pair of X and Y or not. Thanks TM

Dear R-users I have four simple linear models, which are all in the form of a*X+b The estimated parameter vectors are a <- c(1,2,3,4) b <- c(4,3,2,1) My goal is to draw a plot where x-axis is X (range from -100 to 100) and y-axis is the sum of all four linear models X <- seq(-100,100, length=10000) plot(X, sum of the four linear functions) I started with a function for summing

Dear R-users I have 5 dependent variables (y1 to y5) and one independent variable (x) and 3 conditioning variables (m, n, and 0). Each of the conditioning variables has 2 levels. I created 2*4 panel plots. xyplot(y1+y2+y3+y4+y5 ~ x | m*n*o,layout = c(4,2)) I would like to reorder the 8 panels. I tried to use index.cond (e.g., index.cond = list(c(1,3,2,4,5,7,6,8)) but it didn't work out.

Hi R user I need to read in some values from a computer program output. I can't change the output format because the developer of the program doesn't allow to change the format of output. There are two formats. First one looks like this if I have 10 variables, ------------------------------------------------------------------------------------------------------ [ 1]

Hi R users Here is what I got with help from Petr Pikal (Thanks Petr Pikal). I modified Petr Pikal's code to a little to meet my purpose. I created a function to generate a matrix generate.matrix<-function(n.variable) { mat<-matrix(0,n.variable,(n.variable/2)/5+1) #matrix of zeroes dd<-dim(mat) # actual dimensions mat[1:(dd[1]/2),1]<-1 #put 1 in first half of first column

Hi R users - I got an error message when reading in a saved file (a list structure) >dget("REPLICATION001") Error in attributes(.Data) <- c(attributes(.Data), attrib) : row names must be 'character' or 'integer', not 'double' I don't need row names and didn't even specify row names when I saved the file. What do I need to do for reading

Hi R users I have a simple question to ask x <- c("a","b","c") x [1] "a" "b" "c" I like to have "abc" instead of having "a" "b" "c" I tried to use paste and other functions related to character. Is there any function (command) that enable me to combine elements of a character vector into

Hi R users I wrote a function that generates some character strings. generate.index<-function(n.item){ for (i in 1:n.item) { for (j in ((i+1):n.item)) { cat("i",formatC(i,digits=2,flag="0"),".",formatC(j,digits=2,flag="0"),"\n",sep="") } } } I

Dear R-users I wrote a small program for assigning a membership Here is my script sample.size <- 60 x <- rnorm(sample.size, 0, 1) y <- rnorm(sample.size, 0, 1) x.mean <- mean(x) y.mean <- mean(y) membership <- numeric(sample.size) for (i in 1:sample.size) { if ((x[i] < x.mean) && (y[i] < y.mean)) { membership[i]

Dear R users, I would like to extract df and Mean Sq values. I tried several things (e.g., str(model1), names(model1)) but I can't find a way to extract these values. I also tried to search using RSiteSearch. Any help will be appreciated. Thanks Taka, model1<-aov(dv~iv.1*iv.2*iv.3) summary(model1) Df Sum Sq Mean Sq iv.1 1 3.200 3.200

Hi R users I like to generate a certain type of matrix. If there are 10 variables, the matrix will have nrow=10, ncol=((10/2))/5+1. so the resulting matrix's dimension 10 by 2. If there are 50 variables the dimension of the resulting matrix will be 50 by 6. The arrangement of elements of this matrix is important to me and I can't figure out how to arrange elements. If I have 20

HI R users I have one question for using DOS command through "system" I like to delete a file that is located at C:\Program Files\DOSPROGRAM\input.dat I can use a DOS command "del" on Dos prompt like this C:\Documents and Settings> del "C:\Program Files\DOSPROGRAM\input.dat" to delete input.dat file. When I try to do the same thing on R using "system"

Hi R users I am trying to get cross-tabulation tables using tables. All variables used are binary ones (0 and 1). Each time I constructed cross-tabluation table using a different variable pair (e.g., variable 1 and variable 2, variable 1 and variable 3 etc) In doing so, I ran into some problems i.V2 i.V1 1 0 17 1 33 For variable 2 (i.V2) there was no one belonging to ZERO

Hi R users I like to extract (or collect) a numeric element with a name from a list. Is there any way to extract just a numeric element without the name attached to the element. For example, >mylist Mantel-Haenszel chi-squared test with continuity correction data: table(mydata[, x]) Mantel-Haenszel X-squared = 8.3832, df = 1, p-value = 0.003787 alternative hypothesis: true

Dear R-users, I am looking for a way to scan a directory and then make a string vector consisting of the file names in the directory. For example, under c:\temp\ there are 4 files a.txt, b.txt, c.txt, and d.txt I would like to have a string vector c("a.txt","b.txt","c.txt","d.txt") How do I do that? Thanks Taka,

Hi R users This looks a simple question Is there any difference between between rnorm(1000,0,1) and running rnorm(500,0,1) twice in terms of outcome ? TM