similar to: struggling to plot subgroups

Displaying 20 results from an estimated 3000 matches similar to: "struggling to plot subgroups"

2006 Oct 31
2
plotting multiple groups (newbie Q)
Hi Folks, After loading a data set, I run the following: > kSum <- orderBy(~group,(summaryBy(DP_Level~F2 +group,data=kdata,FUN=c(mean,sd),na.rm=T))) kSum looks like this: > kSum F2 group DP_Level.mean DP_Level.sd 1 1.0 N -1.55186475 11.022245 4 2.0 N -2.48013300 10.624583 7 3.0 N -12.47671250 11.104792 10 4.0 N -13.72430950 12.000779 13
2007 Feb 14
1
symbols hidden in polar.plot
Hi Folks, Here is my attempt at a simple polar plot. > pos <- seq(0,360,by=5) > tspk <- rep(c(1,0,1),c(13,47,13)) > require(plotrix) > polar.plot(tspk,pos,rp.type="s",point.symbols=17,point.col="green4") I only see half the symbols, the other half of each symbol is hidden under the circular grid. In fact if I change rp.type="r", I see the
2018 May 30
2
Filtering using multiple rows in dplyr
Hi Folks, I have just started using dplyr and could use some help getting unstuck. It could well be that dplyr is not the package to be using, but let me just pose the question and seek your advice. Here is my basic data frame. head(h) subject ageGrp ear hearingGrp sex freq L2 Ldp Phidp NF SNR 1 HALAF032 A L A F 2 0 -23.54459 55.56005 -43.08282
2008 Nov 30
1
help: unbalanced repeated measures
Hi folks, I am trying to figure out how run a repeated measures ANOVA on the following data set. subject trial frequency dplvl 1 FSI052A A 1 NA 2 FSI052B B 1 NA 3 FSI053A A 1 NA 4 FSI055A A 1 NA 5 FSI055B B 1 NA 6 FSI057A A 1 NA 7 FSI057B B 1 NA 8 FSI058A A 1 NA 9
2007 Jan 26
1
plotting results from tapply
Hi, there I'm trying to plot what is returned from a call to tapply, and can't figure out how to do it. My guess is that it has something to do with the inclusion of row names when you ask for the values you're interested in, but if anyone has any ideas on how to get it to work, that would be stellar. Here's some example code: y1<-rnorm(40, 2) x1<-rep(1:2, each=20)
2003 Jul 22
4
greek in main title
Hello, I have written a function that demonstrates the CLT by generating samples following the exponential distribution, calculating the means, plotting the histogram, and drawing the limiting normal curve as an overlay. I have the title of each histogram state the sample size and rate (1/theta) for the exponential (the output is actually 4 histograms), but I can't get the greek letter theta
2008 Oct 05
1
Sample mean in R
I am having issues with the following: (muhat = 1/n^2(sum of all the xi's) ) essentially if xbar = the sample mean, muhat = sample mean but square the n. Question: Use R to run a Monte Carlo simulation which compares the finite-sample performance of xbar and muhat. Specifically generate 1000 samples n=30 from a standard normal distribution. For each sample calculate xbar and muhat. I have
2007 Jul 25
3
Constructing bar charts with standard error bars
I am new to R. I want to graph group data using a "Traditional Bar Chart with Standard Error Bar", like the kind shown here: http://samiam.colorado.edu/~mcclella/ftep/twoGroups/twoGroupGraphs.html Is there a simple way to do this? So far, I have only figured out how to plot the bars using barplot. testdata <- scan(, list(group=0,xbar=0,se=0)) 400 0.36038 0.02154 200 0.35927
2013 Feb 08
2
qcc package
Greets, My data looks like: > p3.18 s xbar subgroup 1 0.84 12.2 1 2 1.64 11.2 2 3 2.07 10.6 3 4 2.49 12.2 4 5 0.84 11.2 5 ... Using the command > qcc(p3.18$xbar,type="xbar",sizes=5,center=mean(p3.18$xbar),std.dev=mean(p3.18$s)/0.94,title="X-bar Chart for Paper Sheet Length Data") I get the x-bar chart I expect. However,
2007 Dec 30
1
Histogram with different colors for different portions
Dear Rusers, I would like to color different sections of a histogram different colors. I have an example that was done by "brute force" given below. Has anyone implemented something like this in general? If not, any suggestions/pointers on how to write a general function to do so would be most appreciated. Alan-
2011 Mar 03
3
Probabilities greather than 1 in HIST
Dear all, I am a newbie in R and could not find help on this problem. I am trying to plot an histogram with probabilities in the y axis. This is the code I am using: #TLC uniform n=30 mi=1; mx=6 nrep=1000 xbar=rep(0,nrep) for (i in 1:nrep) {xbar[i]=mean(runif(n,min=mi,max=mx))} hist(xbar,prob=TRUE,breaks="Sturges",xlim=c(1,6),main=paste("n =",n), xlab="Média",
2008 Sep 02
2
qcc help
Hi Gents, I need to get the control limits from qcc function. As follows: qcc(MDI, type = "xbar.one") Call: qcc(data = MDI, type = "xbar.one") xbar.one chart for MDI Summary of group statistics: Min. 1st Qu. Median Mean 3rd Qu. Max. 0.3266 0.4249 0.4371 0.4333 0.4451 0.4858 Group sample size: 1 Number of groups: 383 Center
2017 Jul 08
2
CRAN I-MR / Xbar-R / Xbar-S control chart package ?
Hi, I've had a quick look through the package list, and unless I've missed something, I can't seem to find anything that will do I-MR / Xbar-R / Xbar-S control charts ? Assuming there is something out there, can anyone point me in the right direction ? Thanks ! TIm
2007 Apr 28
1
pacf
Hi, I wanted to understand exactly how acf and pacf works, so I tried to calculate ac and pac manually. For ac, I used the standard acf formula: acf(k) = sum(X(t)-Xbar)(X(t-k)-Xbar))/sum(X(t)-Xbar)^2. But for pac, I could not figure out how to calculate it by hand. I understand that in both R and EVIEWS, it is done using the Durbin-Levinson algorithm by the computer. However, I don't
2010 Mar 12
2
Return one value, print another
Dear R users, I am stuck trying to figure out how to make a function return one value and print another.? Here is an example function: ################## eg <- function(x, digits=4) { xbar <- mean(x) sdx <- sd(x) value <- list(xbar, sdx) names(value) <- c("Mean of X", "SD of X") return(value)} ################## My current "solution" has been to
2010 May 05
4
P values
How do u calculated p values for a z test.. so far i ve done this A = read.table("cw3_data.txt") xbar = mean(A) s = 1 n = 20 mu = 0 z.test = (xbar-mu)/(s/sqrt(n)) p.value = pnorm(abs(z.test)) error = qnorm(0.99)*s/sqrt(n) left = xbar - error right = xbar + error and have got values off of it...but the values for p dont match up with other sites that i have used to check it
2002 May 11
2
Bug on Mac version of lm()?
Dear Mac users, Hi, as you might have probably read the thread of "[R] Rsquared in summary(lm)" on May 10, it seems that Mac version of lm() seem to be working incorrectly. I enclose the script to produce the result both for lm() and manual calculation for a simple regression. Could you run the script and report with the version of R, so I don't have to go through every builds
2014 Sep 08
3
problema con los cambios de marcas temporales en el eje X
Muchísimas gracias Carlos, de verdad que te agradezco la ayuda, pero no es lo que voy buscando. Quiero colocar en el eje de abscisas la secuencia temporal de los meses, es decir, agosto septiembre, octubre, etc? pero no las fechas de las toma de datos, sino que aparezca la marca de un mes, y la siguiente marca sea la del siguiente mes, etc?, y además que las muestras estén separadas de acuerdo con
2017 Jul 08
0
CRAN I-MR / Xbar-R / Xbar-S control chart package ?
Hello, I have no experience with I-MR charts but a google search found package qcc. Maybe it's what you're looking for. Hope this helps, Rui Barradas Em 08-07-2017 09:07, Tim Smith escreveu: > Hi, > > I've had a quick look through the package list, and unless I've missed > something, I can't seem to find anything that will do I-MR / Xbar-R / > Xbar-S control
2005 Feb 04
1
QCC and PlotMath question
For some reason, using the qcc package, I'm unable to use the plotmath notation in the title. Can anyone see what I'm doing wrong? library(qcc) a <- rnorm(100) qcc(a,type="xbar.one",title=expression(bar(X)),ylab=expression(CFU/ft^3) ) This seems to not let the expression be evaluated, so I tried: