Displaying 20 results from an estimated 10000 matches similar to: "lme for time series prediction"
2006 May 16
5
Interrater and intrarater variability (intraclass correlation coefficients)
Hello!
I want to calculate the intra- and interrater reliability of my study. The design is very simple, 5 raters rated a diagnostic score 3 times for 19 patients.
Are there methods/funtions in R? I only found packages to calculate interrater variability and intraclass correlation coefficients for matrices of n*m (n subjects, m raters) - I have n subjects, m raters and r repetitions.
Can
2006 Jun 06
1
spatial corStruct in lme
Hi,
I'm fitting a relatively simple growth model to some forest plot data. Two
species of trees were planted in different mixtures in 10 (nearly-adjacent)
plots and measured on four occasions over 10 years. The model is
constructed in terms of the diameter increments (per year; DI) in the 3
intervals, in which DI is modelled as a function of mid-interval D and DSQ.
The details of the
2006 Nov 09
1
Variance Functions in lme
Using the weight argument with a variance function in lme (nlme), you
can allow for heteroscedasticity of the within-group error. Is there a
way to do this for the other variance components? For example, suppose
you had subjects, days nested within subjects, and visits nested within
days within subjects (a fully nested two-way design) and you had, say
men and women subjects. Could you allow for
2006 Aug 31
1
differnce between lme and proc mixed
Hey,
I was using lme and proc mixed in SAS to run a empirical bayesian model.
I used the same method for both lme and proc mixed (the default REML).
I got very similar, but not identical results. I am just wondering if anyone knows what the differneces may be between proc mixed and lme.
Any thoughts would be appreciated!
Thanks,
Liz
2006 May 30
1
Query: lme output
Dear R-Users
I have a problem accessing some values in the output from the summary of an lme fit.
I fit the model below:
ggg <- lme (ST~ -1 + as.factor(endp):Z.sas + as.factor(endp), data=dat4a,
random=~-1 + as.factor(endp) + as.factor(endp):Z.sas|as.factor(trials),
correlation = corSymm(form=~1|as.factor(trials)/as.factor(id)), weights=varIdent(form=~1|endp))
hh
2006 Jun 05
1
Extracting Variance components
I can ask my question using and example from Chapter 1 of Pinheiro & Bates.
> # 1.4 An Analysis of Covariance Model
>
> OrthoFem <- Orthodont[ Orthodont$Sex == "Female", ]
> fm1OrthF <-
+ lme( distance ~ age, data = OrthoFem, random = ~ 1 | Subject )
> summary( fm1OrthF )
Linear mixed-effects model fit by REML
Data: OrthoFem
AIC BIC
2006 May 16
2
query: lme
Dear R Users
I have difficulties accessing the variance components for an lme fit when the variance covariance matrix of the random effects is not positive definite.
Can anyone inform me on how to get by this ?
Thanks in advance
Pryseley
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2006 Feb 19
3
Changing predictor order in lm()
Dear community,
can anyone provide a snippet of code to force the lm() to fit a model with
terms in the formula in an arbitrary order? I am interested in something
like:
lm(y ~ A * B + C, data=data)
where the interaction of A and B should be in the formula before C. My
goal is to simplify my presentation of models using the anova() statement.
I have found that this should be possible using
2006 Mar 07
1
Three level linear mixed models
Hello R-users
Is it possible to fit a three level linear mixed effect model in R?
If anyone has an idea or sample code, i will appreciate it very much if i can receive it.
I am reading the book by Pinheiro and Bates but have not come across that yet!
Kind regards
Pryseley
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2007 Apr 09
1
testing differences between slope differences with lme
hello
i have a mixed effect model which gives slope and intercept terms for 6
groups (diagnosis (3 levels) by risk group(2 levels)). the fixed part of
the model is --
brain volume ~ Diagnosis + Risk Group + (Risk Group * age : Diagnosis) - 1
thus allowing risk group age/slope terms to vary within diagnosis and
omitting a nonsignificant diagnosis by risk group intercept (age was
centered)
2006 Nov 14
2
Repeated measures by lme and aov give different results
I am analyzing data from an experiment with two factors: Carbon (+/-)
and O3 (+/-), with 4 replicates of each treatment, and 4 harvests over a
year. The treatments are assigned in a block design to individual
Rings.
I have approaches this as a repeated measures design. Fixed factors
are Carbon, O3 and Harvest, with Ring assigned as a random variable. I
have performed repeated measures analysis
2005 Nov 09
2
Sort a dataframe
Dear All,
How can I sort a data frame (using one of the column)?
Thanks for your support.
Regards.
Abd. Rahman Kassim (PhD)
Head Forest Ecology Branch
Forest Management & Ecology Program
Forestry and Conservation Division
Forest Research Institute Malaysia
Kepong 52109
Selangor, Malaysia
*****************************************
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For any
2006 May 24
1
problem-nlme
Hi,
I have great problems with my work in R.
I look for to model the growth of fish.
I have "Longitudinal data", a serie of repeated
measures for each individual.
Using the corresponding packages "nlme" in R.
I treat to fit to the data different growth functions,
wich were entered by me.
Unfortunately for no it was arrived at the
convergence, several error messages appeared.
I
2006 Feb 10
1
Splitting printed output in Sweave
Dear R community,
I'm trying to figure out if there is any way to split the printed output
of some commands, for example summary.lme, so that I can intersperse
comments in Sweave. I don't mind running the command numerous times and
masking various portions of the output, or saving the output as an object
and printing it, but I can't figure out how to do either. Does anyone
have any
2006 Sep 12
1
Can't run nlme with nested structure
Hello!
So, my problem is following. I have bird offspring growth data and I'd
like to model individual growth curves (aim is to study asymptotes and
inflection points) with nlme according to Pinheiro & Bates 2000: first using
nlsList to generate individual curves and then nlme to study the
parameters and fixed effects. The data is structured to two levels. I
have broods and
2006 Jan 30
2
How to add two different axis to one plot?
Hi all,
I need to put two different axis to one plot. On the top of the plot, I need
to put one axis, with increments from left side to the right side; then at
the bottom of the same plot, I need to put another axis, with increments
from right side to the left side and showing a different unit. How do I do
that?
By the way, is there a "hold" command for plotting?
If I first plot a
2008 May 09
1
lme() with two random effects
Hi all,
I have collected response time data from 178 participants ('sub') for
each combination of 4 within-Ss factors ('con','int','tone','cue').
Additionally, I have recorded the gender of each participant, so this
forms a between-Ss factor ('gender'). Normally this would be analyzed
using aov:
2007 Oct 22
2
Repeated Measures/Linear Mixed Effects function
I have three columns of data, Xc, Trt and fish. This was a repeated
measures design with 6 measurements taken from each of 5 fish. Xc is the
actual measurement, Trt is the treatment, and fish is the fish number. Data
can be seen below (hopefully it is in the column format). I would like to
look for differences between treatments in a repeated measures format. I
used the following code
2007 Nov 10
2
interpreting an LME regression result...
Any help would be most appreciated. (Don't make me get down on my
hands and knees and beg for help, cause I'll do it!!) My boss has me
learning R and doing nested regression with the report due Mon (Friday
night statistics...fun. ). Anyway, here's my problem:
In a regression equation not accounting for the fact that people are
nested in families, the result for Z variable is VERY
2005 Oct 13
6
shell scripts in R
Hi,
How can I execute some scripts from within R.
I have a large data file which I process (for instance with gawk, but not
only) before performing some statistics.
I would like to do this in R, so that I do not have to save many data files
and then making analysis on them (which proved to be unefficient)
Thank you
Marco Grazzi