similar to: Cannot get simple data.frame binding.

A stupid question but I just cannot see how to do this. I have a loop that does some calculations and puts the results in a vector for each iteration, but I cannot see how to get the data out of the loop in such a way that I can use it. I can print it but how do I get it into a set of vectors or what ever. Any help gratefully received. Thanks Example cata <- c( 3,5,6,8,0, NA) catb <-

I have a simple data base and I want to produce tables for each variable. I wrote a simple function fn1 <- function(x) {table(x)} where x is a matrix or data.frame. and used apply to produce a list of tables. Example below. How do I apply the colnames from the matrix or names from the data.frame to label the tables in the results in the list. I know that I can do this individually but

This is probably a simple problem but I don't see a solution. I have a data.frame with a number of columns where I would like 0 <- NA thus I have df1[,144:157] <- NA if df1[, 144: 157] ==0 and df1[, 190:198] <- NA if df1[, 190:198] ==0 but I cannot figure out a way do this. cata <- c( 1,1,6,1,1,NA) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) dogb <- c(2,4,6,8,10,

Dear R'sians, Would really appreciate if you could suggest a more efficient way to order the columns of a dataset. The column names of the dataset contain indices separated by a period. Following are examples of my code and the dataset. oC <- function(tg=x2) { lth <- length(grep("T",names(tg))) thix <-

I want to calculate the "scat" etc, values for each level of id, output a vector of these values that is a <- c(scat, sdog, srat, sbat ) and do an rbind on them. Each level of id has a different value of rate. So far it it looks to me like I can do this by a series of repeated subsets of Df butI would think that I should be able to do this with a function but I am not having

hi I plot a series of observation data every minutes in a day as the attachment below plot(wnd,type='l',lty=1,col='red',lwd=1,xlab=xxlab,ylab=yylab,ylim=YY) In the figure, the x-axis tickment is the number of data How can I change it fore example 1h 2h 3h 4h and so on ? -- TANG Jie Email: totangjie at gmail.com Tel: 0086-2154896104 Shanghai Typhoon Institute,China

Hi Dennis, SOLVED!!! My thanks to both you, John, and others who chimed in. Took a little more digging before finally working, but it is working! Here's a little more of what I did and the ultimate resolutions: I installed the reshape2 library from CRAN. Executed > (.packages()) [1] "reshape2" "stats" "graphics" "grDevices"

#I have a data set that looks like this. A bit more complicated actually with # three factor levels but these calculations need to be done on one factor at a #I then have a set of different rates that are applied #to it. #dataset cata <- c( 1,1,6,1,1,2) catb <- c( 1,2,3,4,5,6) doga <- c(3,5,3,6,4, 0) data1 <- data.frame(cata, catb, doga) rm(cata,catb,doga) data1 # start rates #

Where do I find a version of Samba that will work on Windows 2003? I would be happy to test a bata version of one was available. I need to connect new MAC G5's to a Windows 2003 server for file sharing and storage. Thank you for your help. Danny Martin Instructional Designer 912-353-5277

I think the new web page is wonderful. However, one thing annoyed me. Some programs on 'Other Software Which Supports Ogg Vorbis' page at Vorbis.com seems to be bit problematic. As far as I know, at least two of them have not updated their plug-ins for a while. 1. 'CD-DA X-Tractor' vorbenc-20001018.zip as 'Latest released version of vorb_enc.dll' 2. 'Media

HI Eliza, You could do this: set.seed(15) mat1<-matrix(sample(1:800,124*12,replace=TRUE),nrow=12) # smaller dataset #Your codes ?list1<-list() ?for(i in 1:ncol(mat1)){ ? list1[[i]]<-t(apply(mat1,1,function(x) x[i]-x)) ? list1} ?x<-list1?? x<-matrix(unlist(x),nrow=12) x<-abs(x) ?y<-colSums(x, na.rm=FALSE) z<-matrix(y,ncol=10) ?z<-as.dist(z) ?z ?# ?? 1?? 2?? 3?? 4?? 5??

I am trying to call a funtion within another function and I clearly am misunderstanding what I should do. Below is a simple example. I know lstfun works on its own but I cannot seem to figure out how to get it to work within ukn. Basically I need to create the variable "nts". I have probably missed something simple in the Intro or FAQ. Any help would be much appreciated. EXAMPLE

undefined method `stringify_keys'' for [["Craved"], ["Whole Sale"]]:Array I did this earler in the script how come now it''s yealling? <% catas = Category.find(:all, :order=> "name").map {|u| [u.name]} -%> <p><label for="item_cata">Catagory:</label><br/> <%= select ''item'',

https://bugzilla.samba.org/show_bug.cgi?id=8177 Summary: Problems with big sparsed files Product: rsync Version: 3.0.8 Platform: x64 OS/Version: Linux Status: NEW Severity: normal Priority: P5 Component: core AssignedTo: wayned at samba.org ReportedBy: joluinfante at gmail.com

how can i draw the graph in R?

Dear useRs, I have a matrix with 38 columns and 365 rows. what i want to do is the following..... 1. subtracting from each column, first itself and then all the remaining columns. More precisely, from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column.

Hi R users, I have a time series variable that is only available at a monthly level for 1 years that I need to decompose to a weekly time series level - can anyone recommend a R function that I can use to decompose this series? eg. if month1 = 1200 I would to decompose so that the sum of the weeks for month1 equals 1200, etc.. Many thanks in advance for any help. -- View this message in

Hi all, I'm kinda new in R programming and I need some help preparing a database to run logistic regression. I have data in a tuple form: *id cat val* 1 A 2 1 C 4 3 B 1 5 A 2 6 A 3 6 B 5 6 C 2 8 B 5 8 D 2 9 D 3 and would like to have it like: *id catA catB catC catD* 1 2 0 4 0 3 0 1 0 0 5 2 0 0 0 6 3

Hi, May be this helps: ?tb[1,]%*%(((val-rep(meansb79[1,],5))^2)/6) #??????? [,1] #[1,] 1.47619 tryvarb<-c(1,2,3,4,4,4,4) ?var(tryvarb) #[1] 1.47619 tb[2,]%*%(((val-rep(meansb79[2,],5))^2)/6) #???????? [,1] #[1,] 1.904762 sapply(seq_len(nrow(tb)),function(i) tb[i,]%*%(((val-rep(meansb79[i,],5))^2/6))) # [1] 1.4761905 1.9047619 1.9047619 1.9047619 1.9047619 2.2857143 1.9047619 # [8] 1.9047619

Dear list, I was curious how to subtract a vector from matrix? Say, I have mat <- matrix(1:40, nrow=20, ncol=2) x <-c(1,2) I want, x-mat[1,] and x-mat[2,], and so on... Basically, subtract column elements of x against column elements in mat. But x-mat won't do it. Thanks, Mike [[alternative HTML version deleted]]