similar to: How to interrupt running computation?

I'd like to convert a two-dimensional function f(x,y) to a matrix m, so that m[x,y] = f [x,y]. How can I achieve this? Thanks, Lothar

I thought some of you might be amused by this. In my non-work time, I'm an avid weaver and teacher of weaving. I'm working on a project involving creating many detailed weaving patterns, so I wrote R code to automate it. Details here: http://stringpage.com/blog/?p=822 If the overlap between R users and avid tablet weavers turns out to be >> 1, I'll polish it up and turn it

Hi Arnold, thanks for your assistance. I solved the issue right now by changing prefix = Shared/%%u/ to prefix = Shared/%%n/ This omits the @mydomain.de part which holds the dot causing the trouble. Why this became a problem due to the update I wouldn't know. Regards Lothar Am 22.07.2019 um 10:49 schrieb Arnold Opio Oree: > Hi Lothar, > > I haven't yet had the opportunity to

Hi, Can R read in .xyz files? If so, what is the package, thanks -- Shane [[alternative HTML version deleted]]

Yep, that did it, thanks a lot, "-k yes" wasn't good enough. There now was another error, though: ERROR(<type 'exceptions.AttributeError'>): uncaught exception - 'module' object has no attribute 'drs_utils' The solution offered and working is inserting ? import samba ? import samba.getopt as options ? import ldb +import samba.drs_utils ? from ldb

Here is my problem, 100 decision trees were built(similar to random forest) and I want to replace some of them by new trees. How can I define a tree array including 100 trees, i.e. t[100], and every t[n] is an "C5.0" object, such that when a new tree comes, i can do n<-10 t[n]<-C5.0(...) -- View this message in context:

I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,

Hi, I would like to access a local mysql database. In python using the sqlite3 library it is quite straightforward. I just have to pass the path to the sqlite-file; sqlite3.connect('.../xy.sqlite') Is there something similar in R (or specifically in the RMySQL package)? It seems like I have to use the MySQL function in the RMySQL package in order to ... "initializes a MySQL

hi R-users: I want to draw three plot into one figure by layout and the script has been shown below. But I find R does not show the xlab and ylab information completely as shown the figure attached. How can I midify the script.? thank you . xxlab<-paste(cpmd," (",ro,"%)",sep=" ") yylab<-paste(rfmd," (",co,"%)",sep=" ")

Am 11.08.2020 um 16:02 schrieb Rowland penny via samba: > On 11/08/2020 14:54, Lothar Schilling via samba wrote: >> Yep, that did it, thanks a lot, "-k yes" wasn't good enough. There now >> was another error, though: >> >> ERROR(<type 'exceptions.AttributeError'>): uncaught exception - 'module' >> object has no attribute

I still need the output to match my requiremnt in my original post. With decision rules "clusters" and probability attached to them. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message

Hello, I am trying to create directories with R. I would like R to create directories because it is platform independent. I tried using file() and searching in "R Data Import/Export" but I did not succeed. I think it must be some function since exists the unlink to remove directories (and files). Pau

Since you only have 3 predictors, each categorical with a small number of categories, you can use expand.grid to make a data.frame containing all possible combinations and give that the predict method for your model to get all possible predictions. Something like the following untested code. newdata <- expand.grid( Humidity = levels(Humidity), #(High, Medium,Low)

Dear All, I'd like to write a little application in java wich should pass some commands and data to R and displays the results (tables and charts) in a java frame. First I wanted to work with Omegahat's SJava but had lots of issues already at the installation. Then I heard some rumors that SJava generally is not a very active project and runs rather buggy (that's true?). So my

Hello! I have a data.frame which looks like: Name - Value A - 400 A - 300 B - 200 B - 350 C - 500 C - 350 D - 450 D - 600 E - 700 E - 750 F - 630 F - 650 I want to add another column where all A,B should get an index 1, all C,D an index of 2 and all E,F an index of 3 so that the data.frame looks like: ID - Name - Value 1 - A - 400 1 - A - 300 1 - B - 200 1 - B - 350 2 - C - 500 2 - C - 350 2

Hello, I would appreciate if someone could help me resolve the following: 1. df1[!is.na( X1 | X2 | X3 | X4 | X5),][,1:5] # This does not work 2. Is these message harmful? The following object(s) are masked from 'df1 (position 3)': X1, X2, X3, X4, X5 Thanks, Pradip Muhuri #Reproducible Example set.seed(5) df1<-data.frame(matrix(sample(c(1:10,NA),100,replace=TRUE),ncol=5))

Hi, You're mixing base plot and ggplot2 grid graphics, which as you've discovered doesn't work. Here's av strategy that does: https://cran.r-project.org/web/packages/egg/vignettes/Ecosystem.html This vignette has a good overview, well as info specific to that package. Sarah On Wed, May 30, 2018 at 4:43 AM greg holly <mak.hholly at gmail.com> wrote: > Hi all; >

Hi everybody, after an update this morning to dovecot 2.3.7 we cannot connect to our shared mailboxes anymore. The error message as issued in Thunderbird: "Character not allowed in mailbox name '.'" I didn't change anything about the configuration. Output of dovecot -n: [...] namespace { ? list = children ? location = maildir:%%h:INDEX=%h/shared/%%u ? prefix = Shared/%%u/

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at