similar to: help:coerce lmer.coef to matrix

Dear all, When I coerce a vector into a multi dimensional array, I would like R to start filling the array along the last dimension, then the 2nd last etc. Let's jump straight into an example. x <- 1 : 24 y <- array(dim=c(2,2,6)) I would like to have: y[1,1,1] = 1 y[1,1,2] = 2 ... y[1,1,6] = 6 y[1,2,1] = 7 y[1,2,2] = 8 ... y[2,1,1] = 13 ... y[2,2,1] = 19 if I do y<- array(x,

thigmophobe.labels() fails with error when supplied with an array resulting from tapply (example below). The error originates in thigmophobe() I know the help page says 'numeric vector' but it would be kind of nice if it worked with numeric things of class array too. I think it would need no more than a couple of as.numeric() calls in thigmophobe itself, or (simpler but slightly less

I'm trying to use trace() on an S4 coerce method, but get the error Error in bindingIsLocked(what, whereM) : no binding for "coerce" What am I doing wrong? Example code follows. (I've googled the R mailing lists for "trace coerce" and "trace bindingisLocked" without finding anything relevant. Perhaps I should re-define the method in terms of an

Hi, While checking the package I am getting all the time the following complain about the function: Undocumented S4 methods: generic coerce and siglist matrix,Massvector I have not defined the function nowhere in the R files. My gues is that this has something to do with the following definition of the setAs function. setAs("matrix","Massvector" ,def=

I'd very much appreciate guidance on this. A user reported that the as.double() coercion used inside the .C() call for a function in my package (specifically, randomForest:::predict.randomForest()) is taking up significant amount of time when called repeatedly, and Removing some of these reduced run time by 30-40% in some cases. These arguments are components of the fitted model (thus do

Greetings - In trying to do a multiple correspondence analysis, I need to coerce a data frame such that each of its columns will be a factor. Can someone offer advice on how to make this happen? I've tried this: > logic.resources.f.df<-apply(logics.resources.df, 2, factor) but: > is.factor(logic.resources.f.df$interests) [1] FALSE I've also tried individually, >

Thanks to Brian Ripley for suggesting, to my previous post about a problem with merge, that I trace through merge.data.frame. I did so with my test case and all seemed to be well until I got to: if (all.x) for (i in seq(along = y)) is.na(y[[i]]) <- (lxy + 1):(lxy + nxx) I believe that this code sets observations in y (which has been expanded to be the

Greetings fellow humans, I am attempting to export a text file after using the MatchIt package to match control with treatment subjects. I attempted to write.table and used the following syntax: "write.table(social,"shaka.txt",sep=" ",quote=FALSE,row.names=FALSE,col.names= FALSE)" But received the following error message: "Error in

Hello R-users, In a loop, if a function, such as "nls", gives an error, is it possible to coerce R to continue proceeding the next command with the same loop? Thanks so much for your advice! Hanna Lu [[alternative HTML version deleted]]

I have a data.frame containing survey data that is already organized like a table: > foo Excellent Very Good Good Fair Poor Very Poor Question 1 8 7 3 0 0 0 Question 2 5 5 7 1 0 0 Question 3 7 10 1 0 0 0 > class(foo) [1] "data.frame" > I would like to make a barchart

Hi, I am wanting to look at frequent item sets using the arules package. I need to transform my data into a "transactions" object. The data I read in from a file has 2 columns, an ID and an item. How do I convert data like this into a transactions object? I've tried class? transactions but it only confuses me. My data is like this.... basketID item 1 bread 1 cheese 1 milk 2

The problem seems that ":" always coerces to integer, but should not.. 9.9:12 ## R: [1] 9 10 11 ## S-plus 3.4: [1] 9.9 10.9 11.9 ## and many more examples.... -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-devel mailing list -- Read http://www.ci.tuwien.ac.at/~hornik/R/R-FAQ.html Send "info", "help", or

Hello Suppose I have a matrix mat=(1:16,2) [,1] [,2] [,3] [,4] [1,] 1 5 9 13 [2,] 2 6 10 14 [3,] 3 7 11 15 [4,] 4 8 12 16 there is a vector end=c(2,3,1,3) #coerce the 1st 2 numbers of the 1st column to a vector [1] 1 2 #coerce the 1st 3 numbers of the 2nd column and append it to the previous vector [1] 1 2 5 6 7 #coerce the 1st number of

Hi all, I think this might be an easy one but I cannot think of a way to do this other than what I am currently attempting. I simply want to sort my data frame's rownames by a defined vector so that the plots I generate from that vector are in the desired order Consider the test data below: #Create test data DataToPlot.. <- data.frame("Location1" =

Dear all, I am really new to R, and I have problem here. I searched around, but did not get a solution. I have a numetrix matrix (20 by 25) saved in .csv. I read it as >sx<-read.csv("sx.csv",header=F) Then I try to convert it to numeric using >sx<-as.numeric(sx) Error: (list) object cannot be coerced to type 'double' The class of sx is "data.frame". I

Hi, I am working with a friend on a master's project. Our laboratory does a lot of statistical analysis using the R stats package and we also have a lot of under-utilised nvidia cards sitting in the back of our networked linux machines. Our idea is to coerce the linux nvidia driver to run some of our statistical analysis for us. Our first thought was to specifically code up a version of

-----BEGIN PGP SIGNED MESSAGE----- Hash: SHA1 I have a rectangular matrix of size 920 by 85. I'd like to coerce it into a square matrix such that all row/col names are present in the new matrix and the additional values are zero. As an example: A B C D A 1 2 3 4 E 5 6 7 8 F 9 10 11 12 Would be coerced to: A B C D E F A 1 2 3 4 5 9 B 2 0 0 0 6 10 C 3 0 0

Using a formula converted with as.formula with lme leads to an error message. Same works ok with lm, and with lme and a fixed formula. # demonstrates problems with lme and as.formula demo<-data.frame(x=1:20,y=(1:20)+rnorm(20),subj=as.factor(rep(1:2,10))) demo.lm1<-lme(y~x,data=demo,random=~1|subj) print(summary(demo.lm1)) newframe<-data.frame(x=1:5,subj=rep(1,5))

why? > rle Run Length Encoding lengths: int [1:1650061] 2 2 8 2 4 5 6 3 26 46 ... values : chr [1:1650061] "4bbf9e94cbceb70c BG bg" "4fbbf2c67e0fb867 SK sk" ... > as.data.frame(rle) Error in as.data.frame.default(vertices.rle) : cannot coerce class '"rle"' into a data.frame it seems that rle.df <-

I have just noticed that quite a few columns of a data frame that I am working on are numeric factors. For summary() purposes I want them to be vectors. I tried, for example > indx <- c(1:18,21:37,40,41) > i <- 0 > i <- i+1 > summary(as.vector(sflows1[indx[i]])) Length Class Mode min.pkt.sz 3000 factor numeric but this does not give the five-number