similar to: Unique rows

I am trying to make a box plot and overlay it with a scatter plot from another data.frame. I was able to successfully create the boxplot, but when i tried using points(x~y...) the dots did not show up. example code aa<-(300,300,300,300,600,600,600,600,900,900,900,900) bb<-(13,12,14,11,56,44,34,75,22.,34,22,98,59,55,56) cc<-(13,12,14,11,56,44,34,75,22.,34,22,98,59,55,56)

Hello all, I am working with a 1000x1000 matrix, and I would like to return a 1000x1000 matrix that tells me which value in the matrix is greater than a theshold value (1 or 0 indicator). i have tried mat2<-as.matrix(as.numeric(mat1>0.25)) but that returns a 1:100000 matrix. I have also tried for loops, but they are grossly inefficient. THanks for all your help in advance. Lanre

Hello, aa<-c(1,1,2,2,3,3,4,4,5,5,6,6) bb<-c(56,56,33,33,53,53,20,20,63,63,9,9) cc<-data.frame(aa,bb) uniquedf <- unique(cc) View(uniquedf) Why does the column "row.names" appear in the new dataframe and how do I get rid of it. "uniquedf$row.names <- NULL" does not seem to work. For what I'm doing this is a useless column and can cause confusion and/or

Hello R users, I am a fairly new R user, however, one of the problems I am having is the use of applying if-, and-, then-, else- statements in R against datasets & dataframe. Rtips mentions it, but without simple examples I am not quite sure what my syntax should look like. I am particularly interested in syntax that can be used with the transform function. for example if foo[,1] ==

Hello I am fitting a Cox PH model using the function coxph(). Does anyone know how to obtain the estimate of the covariance matrix under the null hypothesis. The function coxph.detail() does not seem to be useful for this purpose. Thanks, KD. [[alternative HTML version deleted]]

Hello, I have two rows which are almost identical but miss different values at different locations. I would like to merge these two rows so that the missing values are replaced by the element in the same column on the other row making one row. If both rows contain a NA, NA remains in the output. 1 2 3 4 5 Row1 AA AG GG NA NA Row2 NA AG GG AA NA The

Dear list, I have two functions created in the same environment, fun1 and fun2. fun2 is called by fun1, but fun2 should use an object which is created in fun1 fun1 <- function(x) { ifelse(somecondition, bb <- "o", bb <- "*") ## mymatrix is created, then myresult <- apply(mymatrix, 1, fun2) } fun2 <- function(idx) { if (bb == "o) { #

Dear all, I like to extract row names & column names from the named matrix...... like...... a<-matrix(1:6,2) ro<-c("aa","bb") co<-c("dd","ee","ff") dimnames(a)<-list(ro,co) a > dd ee ff aa 1 3 5 bb 2 4 6 from the above matrix "a" I like to extract rownames separately like

Dear mailing list I have a data that have 20,000 rows and 20 columns. Io wonted to extract the 10th row only. Example the 10th, 20th, 30th 40th…..20000 th. can you please help me how do I do that.Than kyou. Example is below. Inpute: AG GG GG AG CC CC CC CC CT CC CT CT GG GG GG GG CC CC CC CC GG GG GG GG CC CC CC CC GG CG CG GG GG GG GG GG *CC CC CC CC* AA AG AG AA AA AA AA AA GG AG AG GG GG AG AG

I have a question, which very easy to solve, but I can't find a solution. I want to convert a data frame to matrix. Here my toy example: > L3 <- c(1:3) > L10 <- c(1:6) > d <- data.frame(cbind(x=c(10,20), y=L10), fac=sample(L3, + 6, repl=TRUE)) > d x y fac 1 10 1 1 2 20 2 1 3 10 3 1 4 20 4 3 5 10 5 2 6 20 6 2 > is.data.frame(d) [1] TRUE > sapply(d,

When I try to unlist a very large list, R is killed without any other warning: A<-as.list(as.data.frame(matrix(1:21639744,nrow=3578,ncol=6048))) with AA<-unlist(A) or AA<-c(A,recursive=TRUE) I get a R terminado (killed) and the end of the session. I think I'll need to get more RAM (now 1Gb, any other solutions welcomed) to be able to do this but, shouldn't I get a more gentle

Hi everyone, I have a vector of strings, each string made up by different number of words. I want to get a new vector which has only the first word of each string in the first vector. I came up with this: str <- c('aaa bbb', 'cc', 'd eee aa', 'mmm o n') str1 <- rep(1, length(str)) for (i in 1:length(str)) { str1[i] <- strsplit(str, "

Hello! Assuming I have a vector, such as v <- c(1,2,1,2,3,3,1) This vector has three unique elements: 1, 2, and 3. > unique(v) [1] 1 2 3 If I shuffle this vector of unique elements, I get something like this: > sample(unique(v)) [1] 3 2 1 In the vector v I started with, I would now like to replace each element in unique(v) with the corresponding element (i.e. the element with the

How do a plot several columns of a matrix at once in a single plot versus a single x-variable? The default plot.matrix or plot.dataframe commands plot each column versus each other column in several sub-plots. I want to plot each column versus a single other vector (x) as several lines or points in one plot. I can do it by hand: get the range of all variables (i.e. columns of the matrix or

Hello, I have a data frame with a factor column, which uniquely identifies the observations in the data frame and it looks like this: sample1_condition1_place1 sample2_condition1_place1 sample3_condition1_place1 . . . sample3_condition3_place3 I want to turn it into three separate factor columns "sample", "condition" and "place". This is what I did so far: #

Dear R-helpers: thank your for your attention. i am a newer to R and i am doing some protein category classification based on the amino acid sequence.while i have some question urgent. 1. any packages for analysis amino acid sequence 2. given two sequences "AAA" and "BBB",how can i combine them into "AAABBB" 3. based on "AAABBB",how can i get some

I'd like to remove duplicated rows within a matrix, with missing data being treated as wildcards. For example > x <- matrix((1:3), 5, 3) > x[4,2] = NA > x[3,3] = NA > x [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3 [3,] 3 2 NA [4,] 1 NA 2 [5,] 2 1 3 I would like to obtain [,1] [,2] [,3] [1,] 1 3 2 [2,] 2 1 3

Hi I would appreciate if anyone could help me with an elegant solution of the following: I have a matrix that contain a small number of -Inf values. How can form a new matrix from the old one that excludes all the rows with -Inf values ? Thank you. Jacob Dept of Statistics University of Johannesburg South Africa [[alternative HTML version deleted]]

Hello First, thanks for the help for an earlier question about error handling! I have problem filtering a dataset. I'm trying to filter the data in the y columns based on the values in the x column, e.g.: x y1 y2 yn 1.0 1 NA 3 2.0 1 NA 11 2.0 2 NA NA 3.0

hi all hopefully some one can help. assume that i imported the following data into R (say the data frame is called a) x1 x2 x3 1 NA 3 1 2 NA 1 2 3 3 NA 6 4 5 9 7 5 6 7 8 9 NA 7 9 How can i construct a new data frame that only contains those rows that does not contain the NA's? is these a quick way? ie x1 x2 x3 1 2 3 4 5 9 7 5 6 7 8 9 in this example we can simple use