similar to: missing value

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Hi. Please, how can I put together 2 or more lines at the same scatterplot ? Example: measures of protein intake (quantitative) of 4 children over 30 days, by day. How to plot all children at same graphic: Protein X Time ? Is there any command like "overlay" ? Thank you, Mauricio

Please, how to fill the area under the curve? x <- c(1:10) y <- c(rnorm(10)) plot(x,y) lines(x,y) Thanks, Mauricio Cardeal

Hi Does anyone know where is the package: npmc (Nonparametric Multiple Comparisons). I found the reference on R Site Search, but not the package itself on CRAN as suggested. Thanks Mauricio

Hi everyone ! Could you please help me with this problem ? I??ve trying to write a code that assign to a variable the content from another, but all I??ve got is a message error. For example: if (age <=10) {group == 1} else if (age > 10 & age <= 20) {group == 2} else {group == 3} Syntax error Or if (age <=10) {group == 1} else (age > 10 & age <= 20) {group == 2}

Hi all, I'm trying to use lapply on a list with the following command: out<-lapply(mylist,myfun,par1=p,par2=d) (1) where myfun<-function(x,par1,par1) {.....} (2) now this function is in fact a wrapper for some Fortran code I have written so I think this might be the problem. When I call lapply() as in (1) I get the following message: Error in get(x,

Hello. I asked before and it was great, cause as a beginner I learned a lot. But, if I have this in R (1 and 2 are codes for sex): > sex<-c(1,2,2,1,1,2,2,2) > sex [1] 1 2 2 1 1 2 2 2 I´d like to obtain the proportion according to sex.So I type: > prop.table(sex) [1] 0.07692308 0.15384615 0.15384615 0.07692308 0.07692308 0.15384615 0.15384615 [8] 0.15384615 The result is OK, but I

Dear friends, suppose i have two datasets: A and B A: id<-1:6 x<-c(1,2,3,4,5,6) y<-c(2,4,6,8,3,2) xy<-data.frame(id,x,y) B m<-c(1,1,3,3,5,5) n<-c(2,2,6,6,3,3) mn<-data.frame(m,n) Now, i want to perfomr two tasks: 1. get a subset of B,no duplicate values,: C: m n 1 2 3 6 5 3 2.Extract the values in A on the conditions that x=m and y=n the results should be: id x y 1 1 2 3

Here is an example of the data.frame that I have, df<-data.frame("case"=rep(1:5,each=9),"id"=rep(1:9,times=5),"x"=round(runif(length(rep(1:5,each=9))))) "case" represents the cases, "id" the persons, and "x" is the binary state. I would like to know in how many cases any two persons a. both have "1", b. the first has

Please, I??d like to store this sample matrix as a new object. How can I do this ? pulse <- c(67, 67, 68, 68, 68, 69, 69, 69, 69, 69, 70, 70, 70, 70, 71, 71, 72, 72, 73, 74) m <- NULL x <- 0 for (i in 1:5) { x <- sample(pulse,3) m <- mean(x) cat(x,m,"\n") } Thanks, Mauricio

Is it possible to make disappear the id numbers from scatter.dudi (mc analysis) ? a <- as.factor(c(1, 2, 3, 2, 1)) b <- as.factor(c(3, 2, 3, 1, 1)) x <- as.factor(c(1, 2, 2, 1, 3)) y <- as.factor(c(2, 2, 3, 1, 1)) dat <- data.frame(a=a, b=b,x=x,y=y) summary(dat) dat require(ade4) dat.acm <- dudi.acm(dat, scann = FALSE, nf = 2) scatter.dudi(dat.acm) Thank you very much !

Hi R guru coders I wrote a bit of code to add a new column onto a "topTable" dataframe. That is a list of genes processed using the limma package. I used a for loop but I kept feeling there was a better way using a more vector oriented approach. I looked at several commands such as "apply", "by" etc but could not find a good way to do it. I have this feeling there

Hi, I've a matrix in 20*11 order. There are 11 variables, i.e 11 columns and each variable have 20 row data. Now i want to calculate covariance between any variable with others taking 4 rows at a time, so that there will be 5 blocks. How can i do this using any R-function? If i want to do it in any 'loop' function? Thanks a lot, SB.

I tried your code, but it's giving the following error.. Error in match.fun(FUN) : argument "FUN" is missing, with no default

Hi All, I have a (331*12) matrix. I wan t to braek it into 28 parts each window having 12 rows, so that each matrix become (12*12) matrix. How can i do this. Thanks, Sumanta. --------------------------------- Send instant messages to your online friends - NOW [[alternative HTML version deleted]]

Hi - I'm trying to avoid using a 'for' loop due to inefficiency and instead use a function (and ultimately tapply as I'm working on a matrix) but I can't figure out how to get 'function' to take the variables as anything other than vectors for example aa<-0 x<-1:4 test.fun<-function(x) {aa<-(x*x +aa) return(aa)} test.fun(1:4) This code

Hi, I try to get the variable labels of a SPSS data file into R but don't find this mentioned in the help file for foreign. Is there another way to get them ? BTW: An SPSS variable name is like: VAR001, whereas the variable label might be 'Identification no.' Thanks in advance, F. Thomas -- .......................................... Dr. Frank Thomas FTR Internet Research 93110

Ok I guess it's time to ask. So I want to plot my data. It's my data from a frequency table, "temp". My formula is just a Gaussian eq. I have done the nls function to get my parameters and now I want to do the whole plot (...) and then lines(..) This is what I have done. > temp bin x 1 -4.0 0 2 -3.9 0 3 -3.8 0 4 -3.7 0 5 -3.6 0 6 -3.5 0 .... and so

Dear All, Is there a better way to include NA's of a factor in the output of table() than using as.character()? Admittedly, I do not understand the help page for table concerning the exclude argument applied to factors. I tried in different ways, but could not get NA to be included in the table, if not using as.character() (see example). Greetings, Heinz ## example fcv <-

Hi, I have a table of observed counts for various genetic markers. Instead of doing Fisher's exact test for each marker one at a time and recording the P value manually, is there a script to go through the whole list and generate the P value column automatically? An example of my data: Counts_CHB and Counts_AA are the observed counts for one allele. 2N_CHB and 2N_AA are the total number