similar to: Adding elements of matrices of different dimensions

Hi there, I have a question, which I thought is very easy to solve, but somehow I can't find a solution. Probably someone could help me quickly? Here it is: I have two matrices: a [,1] [,2] [,3] [1,] 1 4 9 [2,] 2 6 10 [3,] 3 6 11 [4,] 4 8 12 b [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 Now I want to find

Hi, I have: a <- matrix(c(0,1,0,1),nrow=2) b <- matrix(c(1,1,1,0,0,0),nrow=3) c <- 1 d <- c(1,0,1) And I would like to join them in an object 'thing' so that I can access a, b, c, or d through an index in a for loop. For example: thing[4] would return [1] 1 0 1 Note however, that I have many of these 'thing' components. So many that a command like thing

Hello, I have got two matrices with different length. The matrices have 3 columuns. The first two are coordinates. The third is a measurement. Now I want to get a subtraction between every single value of the third column (between matrix1 and matrix2), but only if the two first coordinates in matrix1 and matrix2 are the same. I tried "FUN=?" in aggregate and ave, but I don't know

Hi all, My question is not really urgent. I can write a loop and solve the problem. But I know that I'll be in a similar situation many more times so it would be useful to find out the answer Is there a fast way to perform linear fit to all the columns of a matrix? (or in the one dimension of a multi-dimensional array.) I'm talking about many single linear fits, not about a multiple fit.

Hi R-users, How do I calculate a number of NA's in a row of every second column in my data frame? As a starting point: dfr <- data.frame(sapply(x, function(x) sample(0:x, 6, replace = TRUE))) dfr[dfr==0] <- NA So, I would like to count the number of NA in row one, two, three etc. of columns X1, X3, X5 etc. Thanks in advance Lauri [[alternative HTML version deleted]]

Thanks Dimitris!!! That's much clearer now. Still have a lot of work to do this weekend to understand every bit but your code will prove very useful. Cheers, Aziz -----Original Message----- From: Dimitrios Rizopoulos [mailto:Dimitris.Rizopoulos at med.kuleuven.be] Sent: May 12, 2006 4:35 PM To: Chaouch, Aziz Subject: RE: [R] Maximum likelihood estimate of bivariate

Dear R Users, I want to test the dimensions of an incoming vector, matrix or array safely and succinctly. Specifically I want to check if the unknown object has exactly 2 dimensions with a specified number of rows and columns. I thought that the following would work: > obj=matrix(1,nrow=3,ncol=5) > identical( dim( obj) , c(3,5) ) [1] FALSE But it doesn't because c(3,5) is numeric

hi: I have matrix with dimensions(200 X 20,000). I have another file, a tab-delim file where first column variables are row names and second column variables are column names. For instance: > tmat Apple Orange Mango Grape Star A 0 0 0 0 0 O 0 0 0 0 0 M 0 0 0 0 0 G 0 0 0 0 0 S 0 0 0 0 0

Dear R-users For a given matrix of dimension, say (n,p), I'd like to extract for every column those elements that are bigger than twice the interquartile range of the corresponding column. Can I get these elements without using a loop? Thank you for your help Frank [[alternative HTML version deleted]]

I have some matrices stored as elements in a list that I am working with. On example is provided below as TP[[18]] > TP[[18]] level2 level1 1 2 3 4 1 79 0 0 0 2 0 0 0 0 3 0 0 0 0 4 0 0 0 0 Now, using prop.table on this gives > prop.table(TP[[18]],1) level2 level1 1 2 3 4 1 1 0 0 0 2 3

Hi R, I have a list of matrices. I need to get the sum of all the matrices in the list. Example: a=b=c=d=matrix(1:4,2,2) l=list(a,b,c,d) I need: > a+b+c+d [,1] [,2] [1,] 4 12 [2,] 8 16 Something like do.call("+",l) is not working...why is this? I may not be knowing the number of matrices in the list... Thanks, Shubha This e-mail

Hello, it might be a very simple question but I cannot find the solution (I tried a || b, any(a,b)... but none works). My problem is: I have two vectors, a <- c(TRUE,FALSE,FALSE) b <- c(TRUE,FALSE,TRUE) and I would like to obtain a vector that indicates if it is TRUE in any of the two vectors. Hence, the desired output would be: TRUE, FALSE, TRUE Thank you in advance, Federico

Hi all. I have a numerical function f(x), with x being a vector of generic size (say k=4), and I wanna take the numerically computed gradient, using deriv or numericDeriv (or something else). My difficulties here are that in deriv and numericDeric the function is passed as an expression, and one have to pass the list of variables involved as a char vector... So, it's a pure R programming

Thanks a lot to Demitris for a prompt answer some minutes ago on another tread (see below). To avoid excess mails on the list, I move onto next question: I have another small plotting problem that confuses me. I want to plot results from a field trial series, using the numbers of the trials as symbols in the plot. pch = as.character(trial_no) works fine, but truncates the trial number to the

Dear R-devels, I'd like to create a plot method for a class of objects that passes the '...' argument to both plot() and legend(), e.g., x <- list(data = rnorm(1000)) class(x) <- "foo" plot.foo <- function(x, legend = FALSE, cx = "topright", cy = NULL, ...){ dx <- sort(x$data) plot(dx, dnorm(dx), type = "l", ...) if (legend)

I have a vector that has 1,974 elements and each element is one of the following (B, F, N, Y). How do I recreate that vector accept in the place of N put 0 and in the place of B, F or Y put a 1? Thanks, Jacob [[alternative HTML version deleted]]

Hello all Is There a fuction that return a index of a element in vector? like this semantic example: vector = c( 100, 200, 300 ) getINDEX( vector, value = 200 ) Thanks in advance for your attention. Cleber Borges

Hi R users I have a simple question to ask x <- c("a","b","c") x [1] "a" "b" "c" I like to have "abc" instead of having "a" "b" "c" I tried to use paste and other functions related to character. Is there any function (command) that enable me to combine elements of a character vector into

Dear R-community, I have got a list of vectors and would like to extract the first two elements of each vector to a new list. My list is of the style: my.list = list(c("a", "b", "c"), c("d", "e"), c("f", "g", "h", "i"), ...) #I want: new.list = list(c("a", "b"), c("d",

Hi R, I have a matrix, > x1=matrix(NA,6,6,dimnames=list(letters[1:6],LETTERS[1:6])) > x1 A B C D E F a NA NA NA NA NA NA b NA NA NA NA NA NA c NA NA NA NA NA NA d NA NA NA NA NA NA e NA NA NA NA NA NA f NA NA NA NA NA NA > x2=matrix(rpois(9,1),3,3,dimnames=list(c("b","a","f"),c("D","E","F"))) > x2