similar to: data frame search

Displaying 20 results from an estimated 11000 matches similar to: "data frame search"

2010 Oct 13
5
Regular expression to find value between brackets
Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",
2007 Mar 01
4
How to read in this data format?
Hi, I recieved an ascii file, containing following information: $$ Experiment Number: $$ Associated Data: FUNCTION 1 Scan 1 Retention Time 0.017 399.8112 184 399.8742 0 399.9372 152 .... Scan 2 Retention Time 0.021 399.8112 181 399.8742 1 399.9372 153 ..... I would like to import this data in R into a dataframe, where there is a column time, the first numbers as column names, and the
2010 Jul 15
3
Access web content from within R
Hi, I have to search in an online db for registered manufacturers of raw materials. Can I use R for the following: I have a list with monograph numbers eg: l <- c(198, 731,355) Now I want to make a dataframe, containing the monograph number and the information listed under COS: Certificate holder, certificate number, Status, Type Is this possible with R? kind regards Bart -- View this
2024 Aug 18
2
allequal diff
Dear Ivan Thanks a lot for this very nice example. Is it true that all.equal just compares y values? Based on this help here I think so and the value I got is the difference for the y-values. https://www.statology.org/all-equal-function-r/ However, here I see x and y testing? https://www.rdocumentation.org/packages/base/versions/3.6.2/topics/all.equal I am actually interested in the x values
2024 Aug 16
1
allequal diff
? Fri, 16 Aug 2024 11:32:58 +0200 <sibylle.stoeckli at gmx.ch> ?????: > # values and mask r1 > r1 <- getValues(r1) > mask1 <- is.na(r1) > # Do the same for r2 > r2 <- getValues(r2_resampled) > mask2 <- is.na(r2) > > # Combine the masks > all.equal(r1[!(mask1 & mask2)], r2[!(mask1 & mask2)]) Let's consider a more tangible example: # The
2024 Aug 16
1
allequal diff
Cool thanks # values and mask r1 r1 <- getValues(r1) mask1 <- is.na(r1) # Do the same for r2 r2 <- getValues(r2_resampled) mask2 <- is.na(r2) # Combine the masks all.equal(r1[!(mask1 & mask2)], r2[!(mask1 & mask2)]) output > all.equal(r1[!(mask1 & mask2)], r2[!(mask1 & mask2)]) [1] "'is.NA' value mismatch: 389 in current 56989152 in target"
2013 Jan 24
4
sorting/grouping/classification problem?
Hi, I'm a database admin for a database which manage chromatographic results of products during stability studies. I use R for the reporting of the results in MS Word through R2wd. But now I think I need your help: suppose we have the following data frame: ID rrt Mnd Result 1 0.45 0 0.10 1 0.48 0 0.30 1 1.24 0 0.50 2 0.45 3 0.20 2 0.48 3 0.60 2 1.22 3 0.40 3
2007 May 09
1
Fitting model with response and day bias
Hi, I'm trying to fit a model which has a response bias, but also a day to day bias. If I try to simulate the data, I don't get the right values with optim, and also I can't use the function to give a prediction interval. My simulated data are: DF <- as.data.frame(cbind(x=rep(1:10,2),dag=rep(1:2,each=10))) bias <- c(-0.2,0.5) DF$y <- ((DF$x-0.1) * 5)+2 +
2024 Aug 18
2
allequal diff
"Is it true that all.equal just compares y values?" The following may be a bit more than you may have wanted, but I hope it is nevertheless useful. The first place you should go to for questions like this is the Help system, not here, i.e. ?all.equal When you do this, you will find that all.equal() is a so-called S3 generic function, which, among other things, means that it works
2005 Dec 18
1
Fit non-lineair 3D Data
Hi, I have a problem with fitting a model: I made a dataframe with this data: a <- 1:3 b <- 1:3 c <- c(3, 2, 3, 2, 1, 2, 3, 2, 3) df <- expand.grid(a,b) df$result <- c names(df) <- c("A","B", "result") Although I can make a graph of the data: require(lattice) wireframe(result~A*B, data=df) I can't get a model to
2007 Feb 10
4
Near function?
Hi, I have an integer which is extracted from a dataframe, which is sorted by another column of the dataframe. Now I would like to remove some elements of the integer, which are near to others by their value. For example: integer: c(1,20,2,21) should be c(1,20). I tried to write a function, but for some reason, somethings won't work x <- 1:20 near <- function(x,th) { nr <-
2024 Aug 16
1
allequal diff
? Fri, 16 Aug 2024 10:35:35 +0200 <sibylle.stoeckli at gmx.ch> ?????: > what do you mean by use is.na() in getValues(). So I need to call > getValues a second time? Not necessarily, but it's one of the options. I was thinking along the lines of: values1 <- getValues(r1) mask1 <- is.na(values1) # Do the same for r2 # Combine the masks all.equal(values1[!combined_mask],
2024 Aug 18
1
allequal diff
?? The OP's original problem is that the all.equal method for raster objects (raster:::all.equal.raster), which is a wrapper around the compareRaster() function, compares a bunch of different properties of rasters (extent, resolution, values, etc.) and only returns a single overall logical (TRUE/FALSE) value. OP wanted to see the magnitude of the difference (as you could get for more
2009 Mar 06
1
Extract dates from dataframe
Hi, I have the following dataframe: ID Dates 1 16-07-01 06-10-95 2 24/01/02 06-10-95 3 16/01/02 16/08/94 12/01/91 And I would like to extract the dates, but couple the ID's to the right dates, eg: ID Dates 1 16-07-01 1 06-10-95 2 24-01-02 2 .... I have no clue about how to get started, looks something for the
2008 Nov 24
3
count the cumulative for each subject
I have a data set like the following: subject visit x1 1 1 0.5 1 2 1.2 1 3 0.7 2 1 0.4 2 2 0.6 2 3 1.0 ..... where x1 is the interval between the two visits. Now I want to calculate the cumulative intervals since the beinging, for example subject visit x1 cum 1 1 0.5 0.5 1 2 1.2 0.5+1.2 1 3 0.7 0.5+1.2+0.7 2 1 0.4 0.4 2 2 0.6 0.4+0.6 2 3 1.0 0.4+0.6+1.0 ..... is there an easy to generate the
2024 Aug 18
1
allequal diff
Ah...I see. Perhaps, then, the maintainer should be contacted, as the desired functionality seems similar to that provided in other all.equal methods. I realize that this may often not elicit a (prompt) response. -- Bert On Sun, Aug 18, 2024 at 11:50?AM Ben Bolker <bbolker at gmail.com> wrote: > > The OP's original problem is that the all.equal method for raster >
2007 Aug 23
4
Calculating diameters of cirkels in a picture.
Hi, Maybe this is more a programming questions than a specific R-project question, but maybe there is someone who can point me in the right direction. I have a picture of cirkels which I took with a digital camera. Now I want to use the diameter of the cirkels on the picture for analysis in R. I can use pixmap to import the picture, but how do I find the outside cirkels and calculate the
2000 Aug 24
2
hosts allow/deny question
Hi all, I would like to do something like this at Samba level: hosts allow = subnet1/mask1 subnet2/mask2 etc hosts deny = * But this doesn't seem to work (machine that are not in subnet1 and not in subnet2 still have access) I think the * is not understood by Samba, I tried ALL, this didn't work either. I'm gonna check the samba source code but if I could get an expert answer
2006 Jun 10
1
Maximum likelihood estimation of Regression parameters
Hi, I want to use Maximum likelihood to estimate the parameters from my regression line. I have purchased the book "Applied linear statistical models" from Neter, Kutner, nachtsheim & Wasserman, and in one of the first chapters, they use maximum likelihood to estimate the parameters. Now I want to tried it for my self, but couldn't find the right function. In the book, they give
2005 Nov 04
1
t test on data frame
Hi, I have constructed a dataframe as follows: Oil <- rep(c("Oil1","Oil2","Oil3"),8) Comp <- rep(rep(c("C1","C2"),c(4,4)),3) Mth <- rep(c("M1","M1","M2","M2"),6) Meas <- rep(c(1,2),12) Result <- rnorm(24,mean=100, sd=5) df <- data.frame(Oil, Comp, Mth, Meas, Result) The same compound