similar to: R: rearranging data frame rows

Hi All, I have two data frames. The first contains data about a number of individuals, coded in the first column with a name, in an order I find convenient. The second contains different data about the same indivduals, in a different order. Both data frame have the individual names in the first column. I need to reorder the second data frame so the rows are rearranged in the same manner as

Hi All, I cannot upgrade r-base and r-recommended because the latest (latest as in it was not listed as 'upgradable' yesterday but today is) r-base-cose is 2.7.1-2hardy0 not hardy1: r-base: Depends: r-base-core (>=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed Depends: r-recommended (=2.7.2-1hardy1) but 2.7.1-2hardy0 is to be installed r-base-core: r-recommended:

Hi All, I would like to ask the following. I have an array of data in an objetct, let's say X. I need to use a for loop on the elements of one or more columns of X and I am having a debate with a colleague about the best memory management. I believe that if I do: col1 = X[,1] col2 = X[,2] ... colx = X[,x] and then for(i in whatever){ do something using col1[i], col2[i] ... colx[i] }

Hi All, just a quick (?) question while I wait my code runs... I'm comparing the identity of the lines of a dataframe, doing all possible pairwise comparisons. In doing so I use identical(), but that's by the way. I'm doing a (not so) quick and dirty check, and subsetting the data as data[row.numb,] and data[a different row,] I suspect the problem there is that I load into

Hi All, I have some data I need to write as a file from R to use in a different program. My data comes as a numeric matrix of n rows and 2 colums, I need to transform each row as a two rows 1 col output, and separate the output of each row with a blanck line. Foe instance I need to go from this: V2 V3 27 2032567 19 28 2035482 19 126 2472826 19 132 2473320 19 136 2035480 135

Hi there, I hope that's not been asked ad nauseam (but I could not find it in the archives...) but, if I put a CRAN mirror in my sources.list and I try to install the latest R version for 'testing' I get the warning that the packages cannot be autenticated. I tried to figure out how to get a GPG key from the mirror I'm using (the austrian one) in case that's the solution,

Hi All, I have the following problem: I have a vector x = rep(0,15) x[1:2] = 1 x [1] 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 I need to be able to call that vector 'x' so that if condition 'A' is true, only the first value is kept 'as is' and all the others are put to 0 if(A == T) function(x) with x returning 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 and if 'A' is false the

Hi All, I hate to do this (because I always found the R/Debian combo exceptional and I never had the time to ontribute --sorry about that--), BUT, the latest r-cran-vr for Etch (testing) is dpkg -l | grep r-cran-vr ii r-cran-vr 7.2.29-1 GNU R package accompanying the Venables and Ripley book on S and I get the following error if I try to load MASS

Hi All, I have a vector of data, a vector of bin breakpoints and I want to put my data in the bins and then extract fanciful informations like the mean value of each bin. I know I can write my own function, but I would have thought that R should have somewhere a function that took as arguments something like (data, breaks, what to do with the data in the bins). I surey could not find it

Hi All, I am trying to build a new R package to submit, but it's failing to create a tex manual: R CMD check Biodem * checking for working latex ... OK * using log directory '/home/greatsage/Fede/R-packages/temp/Biodem.Rcheck' * checking for file 'Biodem/DESCRIPTION' ... OK * checking if this is a source package ... OK * Installing *source* package 'Biodem' ... ** R

Hi All, is there a way of predicting memory usage? I need to build an array of 86000 by 2500 numbers (or I might create a list of 2 by 2500 arrays 43000 long). How much memory should I expect to use/need? Cheers, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44

Hi All, does anyone ever import old SPSS files in a sl3 format? read.spss('file.sl3') does not seem to work... it's not recognised as a supported SPSS format at all. Best, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44 (0)20 75943193 f.calboli

Hi All, can I have a plot where the symbol for the dots is smaller than pch =20 but bigger than pch = '.'? Best, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44 (0)20 75943193 f.calboli [.a.t] imperial.ac.uk f.calboli [.a.t] gmail.com

Hi All, just to check, is cran2deb available for Karmic Koala (ideally also for a amd_64)? Cheers, Fede -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St. Mary's Campus Norfolk Place, London W2 1PG Tel +44 (0)20 75941602 Fax +44 (0)20 75943193 f.calboli [.a.t] imperial.ac.uk f.calboli [.a.t] gmail.com

Hi All, I have the following problem: x = c(1,2) x [1] 1 2 as.matrix(x) [,1] [1,] 1 [2,] 2 BUT, if I add: y = c(3,4) as.matrix(rbind(x,y)) [,1] [,2] x 1 2 y 3 4 It does not transpose. Since I will need as.matrix() for a list of data that is in one or more lines, I need as.matrix to behave in a consisten fashions, so I get as.matrix(x, whatever) [,1] [,2] x 1

Hi All, is there an equivalent of the Unix command 'less' (or 'more'), so I can look at what's inside a data.frame or a matrix without having it printed out on console? I am using R on Debian Linux and Mac OS 10.4.5 Cheers, F -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place, London W2 1PG Tel +44

Hi everyone, I would like to find out when and where exactly I get the following warning in a piece of code I've written: Error in "[<-"(`*tmp*`, iseq, value = numeric(0)) : nothing to replace with The code is a for () loop performing a somewhat trivial calculation, modulated by a number of logical if(){} else(){} conditions, involving the creation of a number of

Hi All, I have a list of matrices: > x [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 > y [,1] [,2] [,3] [,4] [,5] [,6] [1,] 18 21 24 27 30 33 [2,] 19 22 25 28 31 34 [3,] 20 23 26 29 32 35 > z =list(x,y) I want to create a second list that is has a subset each matrix in the list subsetting so I get the 2nd and 3rd row of each (and

Hi All, I am (almost) successfully using apply() to apply a function recursively on a data matrix. The function is question is as.genotype() from the library 'genetics' apply(subset(chr1, names$breed == 'lab'),2,as.genotype,sep ="") Unfortuantely apply puts it's results into a matrix object rather than a data frame, tranforming my factors into numerics and

Hi All, is there a function in R that allows me to work with fractions without transforming them to floats (or whatever) in between? Something that would calculate something like: (1/2 + 1/8) * 1/2 = 5/16 without ever transforming to 0.5 and 0.125? Best, Federico -- Federico C. F. Calboli Department of Epidemiology and Public Health Imperial College, St Mary's Campus Norfolk Place,