similar to: more of a statistics/display question

Dear R mailing list members, ? I am trying to find a way to assign samples into groups depending on their mathematical distribution in a computational way (that is, looped many times). My input is by row, a series of 34 samples per row with n rows. The goal would be to compute the distribution of row n and assign for that row n the samples into bins that would match the distribution of the given

Hin-Tak Leung wrote: > Peter Dalgaard wrote: >> brechbuehler at gmail.com wrote: >>> Full_Name: Christian Brechbuehler >>> Version: 2.4.1, 2.5.1, OS: Ubuntu GNU/Linux >>> Submission from: (NULL) (24.61.47.236) >>> >>> > <snipped> >>> Example (start R without DISPLAY from bash): >>> % DISPLAY=3D R >>> >

Hin-Tak Leung wrote: > Peter Dalgaard wrote: > <snipped> >> You need x11() with a valid display to trigger the bug: >> >> [pd at titmouse2 BUILD]$ ssh -Y 192.168.1.10 >> pd at 192.168.1.10's password: >> Last login: Sat Oct 27 02:40:16 2007 from 192.168.1.11 >> [pd at janus ~]$ echo $DISPLAY >> localhost:10.0 >> [pd at janus ~]$

I am estimating a multinomial model with two quantitative predictors, X1 and X2, and 3 responses. The responses are called neutral, positive and negative with neutral being the baseline. There are actually many models being estimated because I estimate the model over time and also for various parameter sets but that's not important. When I estimate a model, since neutral is the baseline

Dear fellow R users, Keywords: Kruskal-Wallis, Post-Hoc, pair-wise comparisons, Nemenyi-Damico-Wolfe-Dunn test, coin package, oneway_test I am using the "oneway_test" function in the R package "coin" and I am obtaining results which I cannot believe are accurate. I do not wish to waste anyone's time and so if the following problem is rather trivial, I apologize, however I

Hi R community I have a little problem, and I tried to solve it by myself but I couldn't. I building an if loop, and I want to check a value inside an interval. This would be the case: pvalue=0,2999 if(pvalue>0.05 or pvalue<0.1) as you can see I would like to check in that if loop if my pvalue is inside of that interval(from 0.05 to 0.1), and I tried these options: if(pvalue>0.05

On Mon, 2005-10-24 at 17:14 +0100, Hin-Tak Leung wrote: > Peter Dalgaard wrote: > > hin-tak.leung at cimr.cam.ac.uk writes: > > > > > >>Full_Name: Hin-Tak Leung > >>Version: R 2.2.0 > >>OS: x86 linux > >>Submission from: (NULL) (131.111.126.242) > >> > >> > >>Rgnome depends libglade 0.x and libxml 1.x . >

Hi all: I have a question about multi-comparison. The data is in the attachment. My purpose: Compare the predicted means of the 3 methods(a,b,c) pairwisely. I have 3 ideas: #idea1 result_aov<-aov(y~ method + x1 + x2) TukeyHSD(result_aov) diff lwr upr p adj b-a 0.845 0.5861098 1.1038902 0.0000001 c-a 0.790 0.5311098 1.0488902 0.0000002 c-b -0.055 -0.3138902

I have created a list of tables with the same columns but different number of row. Example (actual list has ~200 elements): > temp1<- data.frame(ID=c("Herb","Shrub"),stat=c(4,5),pvalue=c(.03,.04)) > temp2<- data.frame(ID=c("Herb","Shrub", > "Tree"),stat=c(12,15,13),pvalue=c(.2,0.4,.3)) > L<-list(a=temp1,b=temp2) > L $a

On Mon, Jan 19, 2015 at 1:00 PM, Felipe Balbi <balbi at kernel.org> wrote: > I just thought that such a small patch which causes no visible change to > SVN users and allow for git users to build R would be acceptable, but if > it isn't, that's fine too. Felipe --- It would appear that you are unaware that you are walking a minefield of entrenched positions and personality

Hi, people. I was a bit intrigued by the message quoted below. Indeed, if pt() is given a matrix, it returns a matrix. Should this feature be documented? ?pt speaks about "a vector of quantiles", and says nothing about the type of what it returns. The same might presumably apply to other distribution-related functions. ----- Forwarded message from Martyn Plummer <plummer at

Using maildir++ with LDA and POP/IMAP we have been seeing intermittant maildirsize corruption. Where an operation will be prepended by a handful of ASCI null characters ^@^@. Eg: # cat maildirsize 5120000S -46895 -1 93359 1 60576 1 2858 1 49547 1 -206340 -4 94603 1 84785 1 54463 1 82486 1 97104 1 ^@^@^@^@^@^@^@^@40488 1 73397 1 83662 1 24668 1 42673 1 12081 1 -713606 -12 The instances of this

Full_Name: David Sterling Version: 2.4.0 OS: OS X Submission from: (NULL) (64.81.102.199) lillie.test() dies without grace producing the error message: 'Error in if (pvalue > 0.1) { : missing value where TRUE/FALSE needed' when passed a vector of identical values. Examples: > lillie.test(c(0,0,0,0,0,0,0,0,0,0)) Error in if (pvalue > 0.1) { : missing value where TRUE/FALSE

Hi again, I've got few very good options from the list and since they were not posted to the list, I will provide a summary. Thank you very much to all who answered and I hope this summary will benefit others interested in solving similar problems like that. Yasir Kaheil re-wrote my original code in a more streamlined way: pr<-array(0,c(dim(x)[2],dim(x)[2])); for (i in 1:dim(x)[2]) for

At work after updating to R 2.5 I get an error using epitab from package epitools, when at home (R 2.4) I get no error. Could someone help me? Thanks Pietro Bulian Servizio di Onco-Ematologia Clinico-Sperimentale I.R.C.C.S. Centro di Riferimento Oncologico Via Franco Gallini 2 33081 Aviano (PN) - Italy phone: +39 0434 659 412 fax: +39 0434 659 409 e-mail: pbulian at cro.it (at work)

I am trying to assign values to a vector (pvalue). Similar code works in C but not in R. What am I doing wrong? r <- pvalue <- 0 for(i in (1:(k-1))){ for(j in (i+1):k){ r <- r+1 tstat <- (means[i]-means[j])/rms pvalue[r] <- 2*(1-pt(abs(tstat),df)) } } Thank you. Peter B. -- Peter B. Mandeville mandevip at deimos.tc.uaslp.mx Jefe del

Dear All, I am trying to combine dependent p-values in R. May you please help me with this? For independent pvalue combination, one of the popular way is fisher's method which I found the R code here (http://r.789695.n4.nabble.com/fisher-s-posthock-test-or-fisher-s-combination-test-td2195964.html#a2305025): fisher.comb <- function (pvalues) { df=length(pvalues)

https://bugs.freedesktop.org/show_bug.cgi?id=87771 Bug ID: 87771 Summary: X freezes after login Product: xorg Version: 7.7 (2012.06) Hardware: x86-64 (AMD64) OS: Linux (All) Status: NEW Severity: normal Priority: medium Component: Driver/nouveau Assignee: nouveau at

> From: Hin-Tak Leung > > Izmirlian, Grant (NIH/NCI) wrote: > <snipped> > > The only interesting feature is that the tree structure has been > > implemented in C. Its a neater way to carry stuff around and I am > > guessing would make future implementation easier. > > > > Because of its inherent redundancy from the users standpoint, it > >

Dear All, I am using wilcox.test to test two samples, data_a and data_b, earch sample has 3 replicates, suppose data_a and data_b are 20*3 matrix. Then I used the following to test the null hypothesis (they are from same distribution.): wilcox.test(x=data_a, y=data_b, alternative="g") I got pvalue = 1.90806170863311e-09. When I switched data_a and data_b by doing the following: