similar to: log returns (was: Re: help with table partition)

Hi, I have a test_table where the dim is 62220 by 73 (row by col) I would like to partition the rows into 170 equal parts (170 tables where each is of dim 366 by 73), and rearrange them horizontally. The source codes I have: for (i in 1:170) { c = cbind(c,test_table[(367*i+1):(367*(i+1)),2:73]); } Unfortunately, using for loop and cbind for a table of this size

Hemant's problem is that the indicators are not distributed uniformly. With a uniform distribution, categorization gives a reasonably optimal separation of cases. One approach would be to drop categorization and calculate the overall score as the mean of the standardized indicator scores. Whether this is an option I do not know. I did offer an "eyeball" set of breaks in a previous

hello, I'm confused what you guys are talking about. i just want to set ideal threshold values for my RFM scores which can be done using Quantiles but i don't want to use quantiles because my data is not normally distributed so it will lead to wrong ranges of breaks. to fix this problem I'm looking for an approach which can define the ideal range to breaks to categorize RFM scores into

> On Oct 13, 2017, at 2:51 AM, PIKAL Petr <petr.pikal at precheza.cz> wrote: > > Hi > > You expect us to solve your problem but you ignore advice already recieved. > > Your data are unreadable, use dput(yourdata) instead. see ?dput > >> test<-read.table("clipboard", heade=T) > Error in scan(file = file, what = what, sep = sep, quote = quote,

Hi R users Here is what I got with help from Petr Pikal (Thanks Petr Pikal). I modified Petr Pikal's code to a little to meet my purpose. I created a function to generate a matrix generate.matrix<-function(n.variable) { mat<-matrix(0,n.variable,(n.variable/2)/5+1) #matrix of zeroes dd<-dim(mat) # actual dimensions mat[1:(dd[1]/2),1]<-1 #put 1 in first half of first column

Hi scale_colour_gradient(?red?, ?blue?) should do the trick. Actually I found it by Google ggplot colour http://www.cookbook-r.com/Graphs/Colors_(ggplot2)/ http://www.sthda.com/english/wiki/ggplot2-colors-how-to-change-colors-automatically-and-manually#gradient-colors-for-scatter-plots question. So you could find it too and probably far more quickly then myself as I have also other duties. Cheers

>From: =?ISO646-US?Q?Gunther_H=3Fning?= <gunther.hoening at ukmainz.de> >Date: 2006/09/18 Mon AM 06:26:25 CDT >To: 'Petr Pikal' <petr.pikal at precheza.cz> >Cc: r-help at stat.math.ethz.ch >Subject: Re: [R] Question on apply() with more information... I think you want something like below but it probably needs some fixing up because i don't recall the syntax

Hi It is preferable to echo your posts to r-help, you usually get more answers and some definitelly superb to mine. It is also better to start a new mail if your question has nothing to do with original subject "Maura E Monville" <maura.monville at gmail.com> napsal dne 01.10.2007 17:44:43: > Unluckily I do not have the privilege of practising with R all day > long. I

Hi You expect us to solve your problem but you ignore advice already recieved. Your data are unreadable, use dput(yourdata) instead. see ?dput > test<-read.table("clipboard", heade=T) Error in scan(file = file, what = what, sep = sep, quote = quote, dec = dec, : line 115 did not have 6 elements What is ?ideal interval? can you define it? Should it be such to provide eqal

------- Forwarded message follows ------- From: Petr Pikal <petr.pikal at precheza.cz> To: Henrik Parn <henrik.parn at bio.ntnu.no> Subject: Re: [R] paired t-test. Need to rearrange data? Date sent: Tue, 08 Aug 2006 16:13:47 +0200 Hi Uff, it takes me a bit headache but this shall do it ?unstack ?table ?t new.list<-unstack(test.data,y~id)

CC to R-help From: PIKAL Petr Sent: Friday, July 28, 2017 2:20 PM To: 'li xiaomei' <lixiaomei0921 at gmail.com> Cc: r-help at r-project.org Subject: RE: [R] Fail to install package in R Hi You should keep conversation within the list, others could bring better answers. I still do not see any error message. I found this answer to seemingly same question.

Petr, there was a thinko in your response. tmp <- data.frame(m=factor(letters[1:4]), n=1:4) tmp tmp$m <- factor(tmp$m, levels=c("c","b","a","d")) ## right tmp[order(tmp$m),] tmp <- data.frame(m=factor(letters[1:4]), n=1:4) levels(tmp$m) <- c("c","b","a","d") ## wrong tmp[order(tmp$m),] changing levels

Thanks to Andy Liaw and prof.Ripley for their comments. I finally managed my function set work without need for proper installation. However I must try it sometimes. I got tools from http://www.murdoch-sutherland.com/Rtools/tools.zip but I did not install Pearl yet. I tried make pkg-fun which resulted in sequence of errors which I corrected according what I was told by screen and

Hi Petr and Richard; Thanks for your responses and supports. I just faced a different problem. I have the following R codes and work well. p <- ggplot(a, aes(x=Phenotypes, y=Metabolites, size=abs(Beta), colour=factor(sign(Beta)))) + theme(axis.text=element_text(size = 5)) p1<-p+geom_point() p2<-p1+theme(panel.grid.major = element_blank(), panel.grid.minor = element_blank(),

Hi Put fill outside aes p+geom_ribbon(aes(ymin = slope_1*x + intercept_1 - 1/w[2], ymax = slope_1*x + intercept_1 + 1/w[2]), fill = "blue", alpha=0.1) The "hole" is because you have two levels of data (red and blue). To get rid of this you should put new data in ribbon call. Something like newdat <- trainset newdat$z <- factor(0) p+geom_ribbon(data=newdat, aes(ymin =

BTW. I checked help page of contour and maybe it could mention a note about akima package or interp function. Petr ------- Forwarded message follows ------- From: Petr Pikal <petr.pikal at precheza.cz> To: "Abhinav Verma" <abhinav1205 at gmail.com>, r-help at stat.math.ethz.ch Subject: Re: [R] Reading xyz data from a file and plotting a

Hi keep your emails to R help, I do not offer private consultance and others could have different opinion how to solve your problem. Did you even try my suggestion? If not, why not? If yes in what respect it does not comply with your expectations. Cheers Petr From: niharika singhal [mailto:niharikasinghal1990 at gmail.com] Sent: Tuesday, October 10, 2017 2:34 PM To: PIKAL Petr <petr.pikal at

Hi When you load external file to R, character variables are converted to factors by default and alphabetically sorted. I have limited connection to internet, so I cannot find the answer, you could try it yourself. Maybe you could try not to convert vector with names to factor, which, for plotting issue is not different from factor coding. See ?read.table for details However I am not sure if it

Hi Others can have better insight in your question so i tis preferable to post your mails to the Rhelp list too. I hope your datafile is all numeric. If not after t(datafile) can be character. AFAIK your pvalue is not propagated to aov function. Based on artificial data your construction arrives to result, which in this case tells you that there is almost no difference in those 5 groups.. m

My mistake sir. I was literally engrossed in my stupid logic, and while doing so, overlooked the simple and very effective solution you had offered. Sorry once again sir and will certainly try to be very careful in future. Thanks again and have a great weekend sir. Regards Amelia --- On Fri, 7/1/11, Petr PIKAL <petr.pikal@precheza.cz> wrote: From: Petr PIKAL