similar to: underscores

http://www.ncbi.nlm.nih.gov/pubmed/21418051 for the full reference. I don't have an electronic copy, but I do have that issue of Biometrics in my office. I'll have a copy sent over. Terry On 07/10/2012 04:08 PM, r-help-request at r-project.org wrote: > Send R-help mailing list submissions to > r-help at r-project.org > > To subscribe or unsubscribe via the World Wide

Since you only have 3 predictors, each categorical with a small number of categories, you can use expand.grid to make a data.frame containing all possible combinations and give that the predict method for your model to get all possible predictions. Something like the following untested code. newdata <- expand.grid( Humidity = levels(Humidity), #(High, Medium,Low)

That does clarify for me that you're missing a step: I didn't clearly follow your description at first. corrplot expects a correlation matrix, not your original data. You need to use cor() first. That's pretty clear in the documentation. See for instance the examples: data(mtcars) M <- cor(mtcars) corrplot(M) Sarah On Sat, Mar 17, 2018 at 12:00 PM Shivi Bhatia <shivipmp82 at

I still need the output to match my requiremnt in my original post. With decision rules "clusters" and probability attached to them. The examples are sort of similar. You just provided links to general info about trees. Sent from my Verizon, Samsung Galaxy smartphone<div> </div><div> </div><!-- originalMessage --><div>-------- Original message

? data=read.table("http://statcourse.com/research/boston.csv", , sep=",", header = TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) Please: Show me the tree. Mark -------- Original Message -------- Subject: Re: [R] help with rpart From: "Stephen Milborrow" <[1]milbo at sonic.net>

? data=read.table("http://statcourse.com/research/boston.csv", , sep=",", header = TRUE) ? library(rpart) ? fit=rpart (MV~ CRIM+ZN+INDUS+CHAS+NOX+RM+AGE+DIS+RAD+TAX+ PT+B+LSTAT) predict(fit,data[4,]) plot only reveals part of the tree in contrast to the results on obtains with CART or C5 -------- Original Message -------- Subject: Re: [R] help with rpart From: Sarah

I need the output to have groups and the probability any given record in that group then has of being in the response class. Just like my email in the beginning i need the output that looks like if A and if B and if C then %77 it will be D. The examples you provided are just simply not similar. They are different and would take interpretation to get what i need. On Apr 14, 2016 1:26 AM,

While looking at someone's question on this list led me to the mclust package, and from there to its license. Excerpts: Except for strict academic use, use of MCLUST (by itself or through other packages) requires payment of an annual license fee and completion of a license agreement found at the following URL: http://depts.washington.edu/ventures/UW_Technology/Express_Licenses/mclust.php 1.

Hi Manuel, I've taken the liberty of adding the r-help list back to this email, even though you sent your reply just to me, so that others may contribute. On Fri, Mar 9, 2012 at 6:27 PM, Manuel Sp?nola <mspinola10 at gmail.com> wrote: > Thank you Sarah, > > I am thinking more on?habitat mapping and landscape metrics. Then you've probably seen the adehabitat* and SDMTools

On Tue, Jun 19, 2012 at 1:11 PM, Saima Bashir <saimabashir11 at yahoo.com> wrote: > Hi Sarah, > > I have installed and loaded them into R but get same error. > > I am using four equations, cross-section data, version R i386 2.15.0. That is by no means all the information I requested in my original reply, or all that is requested in the posting guide. Nobody can help you

Thanks for the messages. What I probably should have explained is that I have a data.frame "file" with variables named "A", "B", etc.. I wanted to use paste () to pull the names "file$A", "file$B", etc. and stick them in table() and so get an output of table(file$A). For the record, someone read my thinking and sent the following solution which

The real weird thing is I wrote "weird" and it comes out "wired"... The background is that I did a lot of sparse matrices calculations. Therefore need some indices tweaks, e.g subtract a block from a big matrix. Then I just create an indicies matrix and use it directly as a vector since a matrix is just a vector with dimensions attributed in R. I know I can convert them to a

Folks: I consider my reply below rather clumsy: One has to keep track of index numbers other than that which is inserted and must separately change column names. Is there as "essentially better" way to do this, either via base R or via an R package. I leave it to you to define "essentially better." Thanks. Cheers, Bert On Mon, Aug 1, 2011 at 10:17 AM, Bert Gunter

Hello to all, I still have this doubt. I'd like to colour the different labels of my dendrogram each one with a different colour. How can I do? I guess I could do using *edgetext* and then *t.col* or* lab.col* but I don't know how to add edgetext to my dendrogram. Can you help me please? Example: require(graphics); require(utils) hc <- hclust(dist(USArrests), "ave") (dend1

Hi Sarah, Thank you for your help. I tried using CR1<-as.matrix(CR1) but gives error Error in corrplot(CR1, method = "circle") : The matrix is not in [-1, 1]!. I am using a corrplot library. Please find the reproducible example: dput(head(CR1,10)) structure(c(26L, 46L, 39L, 38L, 47L, 59L, 56L, 61L, 43L, 60L, 78L, 63L, 2L, 58L, 8L, 1L, 1L, 9L, 11L, 2L, 1037500L, 46747L, 346300L,

Thank you Sarah and Mike for your explanations. My final objective is to produce maps (png image or any kind of extension I can import in LaTeX) where rainfall data are interpolated, using the Inverse Distance method or Kriging. My input file (pointfile.csv in the reported example) reports the station code, lat and long of the meteorological station and the rainfall value (which might be the

Also, > aggregate(cbind(OD, ODnorm) ~ Time + Target + Conc, data = df, FUN = "mean") Time Target Conc OD ODnorm 1 1 BACT 1 765.3333 108.33333 2 1 BACT 2 745.3333 88.33333 3 1 BACT 3 675.0000 18.00000 (You might wish for "cbind(OD,ODnorm) ~ . - Well", but aggregate.formula is not smart enough for that.) -pd > On 24 Oct 2023, at

From: Martin Maechler <maechler at stat.math.ethz.ch> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii Content-Transfer-Encoding: 7bit Message-ID: <17739.46076.735981.117358 at stat.math.ethz.ch> Date: Fri, 3 Nov 2006 22:26:20 +0100 To: Barry Rowlingson <B.Rowlingson at lancaster.ac.uk> Cc: Sarah Goslee <sarah.goslee at gmail.com>, r-help at

Sarah's solutions are good, and here's another, even more basic: tmp1 <- unique(dat1$B) tmp2 <- seq_along(tmp1) dat1$C <- tmp2[ match( dat1$B, tmp1) ] > dat1 N B C 1 1 29_log 1 2 2 29_log 1 3 3 29_log 1 4 4 27_cat 2 5 5 27_cat 2 6 6 1_log 3 7 7 1_log 3 8 8 1_log 3 9 9 1_log 3 10 10 1_log 3 11 11 3_cat 4 12 12 3_cat 4 As a single line

Thank you Sarah.I'm glad it was a quick fix: On Fri, Feb 5, 2010 at 8:50 AM, Sarah Goslee <> wrote: > You're not only removing a row of data, you are invoking the default > behavior of subset, which is to collapse the subsetted result to the > smallest possible type, which in this case is a vector. Vectors have > no rows, and thus no row names. > > You need the