similar to: date.mdy in date package

The date library contains a function date.mdy that converts a number D to the date (month,date,year as a list) at D days after 1 Jan 1960. This a convention that fits in with SASs. The logic would be that the result was the date at D days after 1 Jan 1960 00:00:00 (which is a POINT in time as opposed to a date which is an interval), so that any D with 2<=D<3 was rounded to 3 Jan 1960 and

Colleagues I want to download the package "date" from CRAN <http://cran.r- project.org/> to get the R-scripts (for version 1.2.0) *** date/INDEX *** as.date Coerce Data to Dates date.ddmmmyy Format a Julian date date.mdy Convert from Julian Dates to Month, Day, and Year date.mmddyy Format a Julian date date.mmddyyyy Format a Julian date date.object Date Objects mdy.date

Hi everyone, I am trying to use the function as.date() from the "dates" package in R 2.10.0 to convert a character date to a Julian date, as follows: > as.date("02-MAY-01", order="mdy") # convert May 2, 2001 to a Julian date [1] 2May1 However, when trying to convert a character date from the year 2000 to a Julian date, I get an <NA> instead of the desired

Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]

I have a problem with some functions handling dates, in packages 'date' and 'survival' (they seem to be identical). For instance, from the documentation, -------------------- mdy.date {survival} R Documentation Convert to Julian Dates Description Given a month, day, and year, returns the number of days since January 1, 1960. Usage mdy.date(month, day, year, nineteen = TRUE,

Hi, I'm trying to use the date library and I think I'm getting an incorrect warning when I make a plot with plot.date(). For example: > library(date) > x <- as.date(1:100) > y <- 1:100 > plot(x, y, log = "y") Warning message: parameter "log" couldn't be set in high-level plot() function The problem appears to be in the last line of plot.date()

I have a zooreg object and I want to be able to generate a value for seasons and 11-day composites paste it onto my zoo data frame, along with year, month and days. Right now I have the following to work from: eg. dat.zoo.mdy <- with(month.day.year(time(dat.zoo)), cbind(dat.zoo, year, month, day, quarter = (month - 1) %/% 3 + 1, dow = as.numeric(format(time(dat.zoo), "%w")))) For

I'm having problems using the date library with notched boxplots. I have separate month, day, and year columns and would like to plot the columns as a date against other variables. I have used the mdy.date(month,day,year) command before with plot(), but it doesn't seem to work with boxplot(). Instead of the dates along the x-axis, I get a list of numbers. Maybe I have the code wrong?

Hi, I'm trying to convert a vector containing dates in character format ("dd/mm/yy"): mdy.date (from date package) seems to be able to do that, but it returns to me a vector containing julian dates... but negative! for example: 16/12/03 is converted into -20470 it is because R recognizes year ../03 as 1903, instead of 2003, but how can I do to solve this problem? (of course, I

Dear friends. As promised ver 1.01 solved the former problem and now dates plot OK in windows. But. In the following code, "cex.axis"=0.5 works OK but "xaxp"=c(14620,14680,4) has seemingly no effect. The limits for xaxp was found from the default plot and inspecting par(). I need to put the date marks at specific points. Could I suppress them altogether and make a new xaxis

HI all, My I am trying to convert character date (mm/dd/yy) to YYYY-mm-dd date format in one of the columns of my data file. The first few lines of the data file looks like as follow head(Atest,10);dim(Atest) ddate 1 19/08/21 2 30/04/18 3 28/08/21 4 11/10/21 5 07/09/21 6 15/08/21 7 03/09/21 8 23/07/18 9 17/08/20 10 23/09/20 [1] 1270076 1 I am using the following

It seems that you have load the "survival" package date.mdy is a function from this one. In this function the "origin" of the time is the first day of 1970 in the base package the origin is the first day of 1960 it's very curious... Benjamin Esterni France From: "Vegard Andersen" <vegard.andersen@ism.uit.no> Subject: [R] Date conversion problem using

Hi, I have a set of irregular time series and i want to produce a simple plot, with dates on x axis and attribute value of y axis. This is simple enough but my x axis is divided automatically by ticks every 5 years. I would like to have a tick every year at January 1st. I am not sure how i can do that - i end up with something very close to what i want, but it is clunky and not very correct. I

I have a data from with 3 numeric variables, and wish to create a Date object. The old "date" library had a function mdy.date to do this. I've chased all of the See Also sections I can find for the Date class, and didn't find anything comparable. Yes, I can use as.Date(paste(data$year+1900, data$month, data$day), sep='/')) but it seems odd pack something together that

Dear R users, I have a column with dates (character) in a data frame: 12-Jan-01 11-Jan-01 10-Jan-01 9-Jan-01 8-Jan-01 5-Jan-01 and I need to convert them to (Julian) dates so that I can sort the whole data frame by date. I thought it would be very simple, but after checking the documentation and the list I still don't have something that works. 1. as.Date returns the error below. What am I

xyplot doesn't seem to want to label my x-axis with dates but instead puts the day-number for each date. begdate is the number of days since January 1, 1960 and was initially created by library(date) ... polls$begdate<-mdy.date(begmm,begdd,begyy) I create a new dataframe (pollstack) which includes begdate. In the process begdate seems to lose its date attribute so I redo it as: >

I never understood that why is the value returned by as.date function in the library(survival) never matches with the description given in the help file: Following is the extract from ?as.date Description: Converts any of the following character forms to a Julian date: 8/31/56, 8-31-1956, 31 8 56, 083156, 31Aug56, or August 31 1956. Usage: as.date(x, order = "mdy", ...)

The date library was written 20 or so years ago. It was a very good first effort, but the newer Date library has superior functionality in nearly every way. The date library is still available, for legacy projects such as yours, but I do not advise it for new work. To answer your specific questions: 1. What you have is a real bug. The underlying C routine that scans through the text returns

Hi, I wonder if anybody could help me in converting this easy SAS program into R. (I'm still trying to do that!) PROC IMPORT OUT= WORK.CHLA_italian DATAFILE= "C:\Documents and Settings\carleal\My Documents\REBECCA\stat\sas\All&nutrients.xls" DBMS=EXCEL2000 REPLACE; GETNAMES=YES; RUN; data chla_italian; set chla_italian;

Hi all, I want to make all possible combination from dataset below: V1 <- c(0,1,2) V2 <- c(0,1) V3 <- c(0,1) V4 <- c(0,1) V5 <- c(0,1) V6 <- c(0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20) V7 <- c(0,1,2,3,4,5,6) V8 <- c(0,1) V9 <- c(0,1) V10 <- c(0,1) V11 <- c(0,1) V12 <- c(0,1) V13 <- c(0,1) V14