similar to: two relatively simple questions

Displaying 20 results from an estimated 10000 matches similar to: "two relatively simple questions"

2007 Apr 13
1
how to control which version of a package library() installs?
library() seems to remember the location of a package when I give it a lib.loc, and then use that version thereafter, even if I don't supply lib.loc again. Is there any way I can load different versions of a package in one R session? -- I don't seem to able to simply detach the package and then load a different version from a different library location. $ R [...startup info...] >
2000 Aug 04
2
running non-base functions
Having loaded R for windows, I cannot run fnctions that aren't in the base folder. Typing searchpaths() tells me that only the base folder is in the search path. How can the path be modified to include other folders? Thanks, Ely rabin at brandeis.edu -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read
2006 Nov 12
7
I think a simple question
I have index ( of a vector ) values of say tempin<-c(1 31 61 91 121 all the way upto 1411) What I want is a function that takes in a number say, x = 5, and gives me an new vector of tempout<-1 6 31 36 91 96 121 126 .......... 1411 1416 This can't be so hard but I can't get it and I've honestly tried. Obviously, tempin + 5 gives me the missing values but I
2015 Jan 26
2
speedbump in library
>>>>> Winston Chang <winstonchang1 at gmail.com> >>>>> on Fri, 23 Jan 2015 10:15:53 -0600 writes: > I think you can simplify a little by replacing this: > pkg %in% loadedNamespaces() > with this: > .getNamespace(pkg) almost: It would be !is.null(.getNamespace(pkg)) > Whereas getNamespace(pkg) will load the
2015 Jan 08
4
unloadNamespace
In the documentation the closed thing I see to an explanation of this is that ?detach says "Unloading some namespaces has undesirable side effects" Can anyone explain why unloading tseries will load zoo? I don't think this behavior is specific to tseries, it's just an example. I realize one would not usually unload something that is not loaded, but I would expect it to do
2015 Jan 22
3
speedbump in library
Hi all, Profiling turned up a bit of a speedbump in the library function. I submitted a patch to the R bug tracker as bug 16168 and I've also included it below. The alternate code is simpler and easier to read/maintain, I believe. Any thoughts on other ways to write this? Index: src/library/base/R/library.R =================================================================== ---
2015 Jan 26
2
speedbump in library
>>>>> Michael Lawrence <lawrence.michael at gene.com> >>>>> on Mon, 26 Jan 2015 05:12:55 -0800 writes: > A isNamespaceLoaded() function would be a useful thing to > have in general if we are interested in readable code. An > efficient implementation would be just a bonus. Good point (readability), and thank you for the support! Note
2007 Mar 26
4
a very small query
Hi All what is the command to give me the listing of the loaded packages. I mean which are active and not the listing of all the installed packages as given by library() thanks in advance -gaurav ============================================================================================ DISCLAIMER AND CONFIDENTIALITY CAUTION:\ \ This message and ...{{dropped}}
2006 May 15
1
simple .bat question but i can't find out where to post. my apologies for posting a non R question
----- Original Message ----- From: MARK LEEDS To: r-help-request@stat.math.ethz.ch Sent: Sunday, May 14, 2006 9:49 PM Subject: simple .bat question but i can't find out where to post. my apologiesfor posting a non R question I have what I think is a simple .bat question but i can't figure out where to post it ( i spent 6 hours looking through tutorials on batch commands but i
2005 Feb 09
4
subset
Dear all, I am trying to extract rows from a data.frame based on the rowSums != 0. I want to preserve rownames in the first column in the subset. Does anyone know how to extract all species that don't have rowSums equal to zero? Here it is: # dataset x <- data.frame( species=c("sp.1","sp.2","sp.3","sp.4"), site1=c(2,3,0,0), site2=c(0,0,0,0),
2006 Nov 15
2
??: Re:??: Re: Need help in waveslim package: imodwt and universal.thresh.modwt
Airon, I don't think you have to find an English computer 'cause the following must work in your Chinese one :-) Let me explain. First of all, change your lines to xdata <- ckhdat$Adj..Close[1:1447] #names(ckhdwt.la8) <- c("w1", "w2", "w3", "w4", "w5","w6", "v6") note the # sign, i.e., DO NOT change the names
2006 Nov 12
2
Need help in waveslim package: imodwt and universal.thresh.modwt
Hi: I have encountered problems with imodwt and universal.thresh.modwt and cannot find any reference in R Search. Hope someone can give me some ideas: Starting with modwt.la8 <- modwt(xdata, "la8", n.level=6) <-- this seems to work fine (1) ydata <- imodwt(modwt.la8) will always give ydata as numeric(0) (no values) instead of being a time series data with
2006 May 16
2
Large database help
Hello all. I have a large .txt file whose variables are fixed-columns, ie, variable V1 goes from columns 1 to 7, V2 from 8 to 23 etc. This is a 60GB file with 90 variables and 60 million observations. I'm working with a Pentium 4, 1GB RAM, Windows XP Pro. I tried the following code just to see if I could work with 2 variables but it seems not possible: R : Copyright 2005, The R Foundation
2008 Feb 23
3
exprs function download
Hi, I am supposed to use exprs as a function. Where can i download exprs function? I tried searching at bioconductor and seach engine but no luck. Is it located in one of the library in R? thanks. C -- View this message in context: http://www.nabble.com/exprs-function-download-tp15654560p15654560.html Sent from the R help mailing list archive at Nabble.com.
2006 Nov 14
1
??: Re: Need help in waveslim package: imodwt and universal.thresh.modwt
Airon, I used R2.4.0 on a Windows XP (SP2) (not Chinese :-)) and it still works: > data = read.csv("u:/airon.csv") > xdata = data$Adj..Close > modwt.la8 = modwt(xdata, "la8", n.level=6) > summary(modwt.la8) Length Class Mode d1 1467 -none- numeric d2 1467 -none- numeric d3 1467 -none- numeric d4 1467 -none- numeric d5 1467 -none- numeric d6 1467
2007 Mar 22
3
Noice words...
Hi I use acts_as_ferret on an app that is in Danish and English. In Danish english words like "and" and "under" has meaning. Is it possible to make ferret search for these words? As it is now a seach for "under" returns nothing even-though I know the word is present in the index. Cheers Mattias
2020 Jul 19
6
Speed-up/Cache loadNamespace()
Dear all, in our current setting we have our packages stored on a (rather slow) network drive and need to invoke short R scripts (using RScript) in a timely manner. Most of the script's runtime is spent with package loading using library() (or loadNamespace to be precise). Is there a way to cache the package namespaces as listed in loadedNamespaces() and load them into memory before the
2009 Jun 10
1
searchpaths
May I use "searchpaths()" with arguments partially matching file names that are found in different directories ? My question is whether this is th R function equivalent of Linux "find" or Windows "search". Both O.S. calls are given a starting point so that they search all diectories from then downwards looking for files whose names match the searching criteria.
2007 Oct 11
6
confusion with R syntax
I just noticed something by accident with R syntax that I'm sure is correct but I don't understand it. If I have a simple numeric vector x and I subscript it, it seems that I can then subscript a second time with TRUE or FALSE, sort of like a 2 dimensional array in C. Does someone know if this is documented somewhere Because it's neat but I never knew it existed. To me it seems like a
2010 Jul 07
3
How do I test against a simple null that two regressions coefficients are equal?
Hi there, I run two regressions: y = a1 + b1 * x + e1 y = a2 + b2 * z + e2 I want to test against the null hypothesis: b1 = b2. How do I design the test? I think I can add two equations together and divide both sides by 2: y = 0.5*(a1+a2) + 0.5*b1 * x + 0.5*b2 * z + e3, where e3 = 0.5*(e1 + e2). or just y = a3 + 0.5*b1 * x + 0.5*b2 * z + e3 If I run this new regression, I can test against