Displaying 20 results from an estimated 1000 matches similar to: "Maximum likelihood estimate of bivariate vonmises-weibull distribution"
2006 May 12
3
Maximum likelihood estimate of bivariate vonmises-weibulldistribution
Thanks Dimitris!!! That's much clearer now. Still have a lot of work to
do this weekend to understand every bit but your code will prove very
useful.
Cheers,
Aziz
-----Original Message-----
From: Dimitrios Rizopoulos [mailto:Dimitris.Rizopoulos at med.kuleuven.be]
Sent: May 12, 2006 4:35 PM
To: Chaouch, Aziz
Subject: RE: [R] Maximum likelihood estimate of bivariate
2009 Aug 12
1
MCMC sampling question
Hello,
Consider MCMC sampling with metropolis / metropolis hastings proposals
and a density function with a given valid parameter space. How are MCMC
proposals performed if the parameter could be located at the very
extreme of the parameter space, or even 'beyond that' ? Example to
express it and my very nontechnical 'beyond that': The von Mises
distribution is a circular
2006 Mar 03
1
[as.POSIXlt]: Incorrect conversion only for some specific date/time (PR#8654)
Full_Name: Aziz Chaouch
Version: 2.2.1
OS: XP/2000
Submission from: (NULL) (132.156.89.240)
Hi,
I'm not sure this is a "bug" but here is the problem:
I'm using the function as.POSIXlt to convert character strings into time
objects. I'm using date format as "YYYY/M/D HH:MM" such as as.POSIXlt("1999/6/7
13:30"). Most of the time, this works fine. However
2008 Jun 28
1
How to estimate the parameters in a bivariate weibull distribution?
Hi,Dear all R experts,
As far as I know, fitdistr() is only to estimate the parameters in univariate distributions. I have a set of data (x,y) and I assume it follows a bivariate weibull distribution. Could someone tell me a function in R that is suitable for parameter estimation in multivariate cases? Thanks in advance!
Cheers,
YAN
2006 Oct 06
0
Bivariate Weibull distribution -- Copula
"Jenny Stadt" <jennystadt at yahoo.ca> asked:
>
> I am struggling in a bivariate Weibull distribution although I
> searched R-Site-Help and found suggestion with Copula. Seems the
> maximum likelihood estimate is beyond what I can understand.
>
> My case is: given two known marginal distribution (both are Weibull),
> and the correlation between them. How can I
2009 Feb 16
1
How to add direction of time to plot.circular()
Dear r-helpers,
I want to show that time is flowing CCW in the following:
require(circular)
len <- 8
labl <- as.character(c(0, 1, 1, 1, 0, 0, 1, 0))
r <- circular(2*pi* (rep(c(1, 3, 6), each = 200)/len + rnorm(600, 0,
0.025)))
r.dens <- density(r, bw = 25, adjust = 4, kernel = 'vonmises')
plot(r, shrink = 2.5, axes = FALSE, ticks = FALSE, pch = 1, col =
2009 Apr 30
1
finite mixture model (2-component Weibull): plotting Weibull components?
Dear Knowledgeable R Community Members,
Please excuse my ignorance, I apologize in advance if this is an easy question, but I am a bit stumped and could use a little guidance.
I have a finite mixture modeling problem -- for example, a 2-component Weibull mixture -- where the components have a large overlap, and
I am trying to adapt the "mclust" package which concern to normal
2006 May 25
1
Computing a reliability index of a statistic with missing data
Hi All,
I'd like to compute a kind of reliability index (RI) that would in a
sense stand as a measure of reliability of a statistic (histogram etc)
computed on a time serie with missing values. The final goal is that:
RI=1 for a perfect reliability
RI=0 for a total unreliability (no data at all as an extreme case...)
The percentage of missing data is one indication: the more missing data,
2006 Oct 27
0
VGAM package released on CRAN
Dear useRs,
upon request, the VGAM package (currently version 0.7-1) has been
officially released on CRAN (the package has been at my website
http://www.stat.auckland.ac.nz/~yee/VGAM for a number of years now).
VGAM implements a general framework for several classes of
regression models using iteratively reweighted least squares
(IRLS). The key ideas are Fisher scoring, generalized linear
and
2012 May 03
6
Hosting application on private network.
Hi,
I have a Ruby on Rails application. I am able to run it in my local
system using Apache2 server. I would like to host my application so that
all the systems in the private network 192.168.3.0/24 should be able to
access the web-application. My system private-ip is 192.168.3.57.
Please help me what all configurations do I need to do.
Thank you
Ajit
--
Posted via
2007 Aug 15
1
Problem Connecting to Oracle with R from Windows XP
Hello,
I installed RGui 2.5.1 and package DBI on Windows XP and tried to connect to Oracle database which is on a Linux server. When I tried to use dbDriver("Oracle"), I got an error as follows:
> drv <- dbDriver("Oracle")
Error in do.call(as.character(drvName), list(...)) :
could not find function "Oracle"
>
Could anyone tell me how
2008 Oct 26
2
Two sample Cramer-von Mises test
Hall all,
Where can I find the two sample Cramer-von Mises test in R package?
Thank you.
Legendy
--
View this message in context: http://www.nabble.com/Two-sample-Cramer-von-Mises-test-tp20174229p20174229.html
Sent from the R help mailing list archive at Nabble.com.
2009 Nov 07
1
EM algorithm to fit circular mix of uniform+Von Mises
Hi all,
I'm curious if anyone has coded an Expectation-Maximization algorithm
that could help me model some circular data I have. I'd like to model
it as a mixture of uniform and Von Mises centered on 0, so the only
free parameters is the mixing proportion and the kappa of the Von
Mises. I couldn't find anything in the contributed packages that
seemed to suit this purpose. Any
2017 Jun 27
5
Nash equilibrium and other game theory tools implemented in networks using igraph or similar
Does anyone know of some code, and examples that implement game theory/Nash
equilibrium hypothesis testing using existing packages like igraph/statnet
or similar?
Perhaps along the lines of this article:
Zhang, Y., Aziz-Alaoui, M. A., Bertelle, C., & Guan, J. (2014). Local Nash
Equilibrium in Social Networks, *4*, 6224.
Best,
Chris Buddenhagen
cbuddenhagen at gmail.com
[[alternative HTML
2011 Oct 28
1
weibull fitdistr problem: optimization failed
I'm getting errors when running what seems to be a simple Weibull
distribution function:
This works:
x <-
c(23,19,37,38,40,36,172,48,113,90,54,104,90,54,157,51,77,78,144,34,29,45,16,15,37,218,170,44,121)
rate <- c(.01,.02,.04,.05,.1,.2,.3,.4,.5,.8,.9)
year <- c(100,50,25,20,10,5,3.3,2.5,2,1.2,1.1)
library(MASS)
x <- sort(x)
tryCatch(
f<-fitdistr(x, 'weibull'),
error
2012 Jan 26
1
3-parametric Weibull regression
Hello,
I'm quite new to R and want to make a Weibull-regression with the survival package. I know how to build my "Surv"-object and how to make a standard-weibull regression with "survreg".
However, I want to fit a translated or 3-parametric weibull dist to account for a failure-free time.
I think I would need a new object in survreg.distributions, but I don't know how
2002 Jan 17
1
weibull in R
Hi all
I try to make a weibull survival analysis on R.
I know make this on GLIM, and now I try to make the GLIM exercice GLEX8 on R
to learning and compare the test.
The variables are:
time censor group bodymass
In GLIM I make:
$calc %s=1 $ to fit weibull rather than exponential
$input %pcl weibull $
$macro model group*bodymass $endmac$
$use weibull t w %s $
Then, GLIM estimate an alpha for the
2002 Dec 18
2
weibull test
Hello
What is the appropriate method to test if a given distribution is a
weibull
thank you
meriema
email
meriema.belaidouni at int-evry.fr
2001 Aug 28
2
Estimating Weibull Distribution Parameters - very basic question
Hello,
is there a quick way of estimating Weibull parameters for some data points
that are assumed to be Weibull-distributed?
I guess I'm just too lazy to set up a Maximum-Likelihood estimation...
...but maybe there is a simpler way?
Thanks for any hint (and yes, I've read help(Weibull) ;)
Kaspar Pflugshaupt
--
Kaspar Pflugshaupt
Geobotanical Institute
ETH Zurich, Switzerland
2005 Mar 14
0
Parameters of Weibull regression
Dear list, dear Frank,
I try to fit a Weibull survival regression model with package Design:
sclear <- psm(sobj~V1+V2,dist="weibull")
sobj is a one-dimensional survival object (no event indicators), V1 and V2
are factors.
I get the following result:
Parametric Survival Model: Weibull Distribution
psm(formula = sobj ~ V1 + V2, dist = "weibull")
Obs Events