similar to: Bootstrap error message: Error in statistic(data, origina l, ...) : unused argument(s) ( ...)

Displaying 20 results from an estimated 2000 matches similar to: "Bootstrap error message: Error in statistic(data, origina l, ...) : unused argument(s) ( ...)"

2006 Apr 20
1
Bootstrap error message: Error in statistic(data, origina l, ...) : unused argument(s) ( ...) [Broadcast]
I quoted the relevant part of the documentation for you. Have you actually try to read what it says? Sure, you don't get any error, but have you checked whether any bootstrapping was actually done? Most of those functions are generics, thus having the "..." argument that can take anything. Doesn't mean they will be used. See if the following helps: > x <- 1:10 >
2006 Apr 20
0
Bootstrap error message: Error in statistic(data, original, ...) : unused argument(s) ( ...)
Dear colleagues, I've been swamped and fighting with error for a few hours but still desperately having absolutely no clue: What's wrong with my bootstraping code? Thanks a lot! ------------------------ Error Message: > bootResults=boot(X, myFun, R=10000); Error in statistic(data, original, ...) : unused argument(s) ( ...) ------------------------ My code is:
2010 Sep 03
3
S4 Method Signatures
Hello, If the signature of a method defines which generic it implements then I'm confused about why this minimal example I invented won't work : setGeneric("myFun", function(rs, ...){standardGeneric("myFun")}) setGeneric("myFun", function(cs, ...){standardGeneric("myFun")}) setMethod("myFun", "numeric", function(rs, colour =
2006 Feb 02
2
How to get the namespace of a function?
I declared the environment of the function myfun to be NULL as follows: environment(myfun) <- NULL Later on I called that myfun and got an error message because the function index() in the zoo package was called inside myfun and was not visible: Error in myfun(args) : couldn't find function "index" I tried to use zoo::index() instead of index(), but that did not work. In fact,
2011 Feb 02
1
pass nrow(x) to dots in function(x){plot(x,...)}
Dear Rers, I have a function to barplot() a matrix, eg myfun <- function(x, ...) { barplot(x , ... )} (The real function is more complicated, it does things to the matrix first.) So I can do: m1 <- matrix(1:20,4) myfun(m1) myfun(m1, main="My title") I'd like to be able to add the number of rows of the matrix passed to the function to the "..." argument, eg
2009 Jun 12
1
how to trigger variable creation?
Hello R users, i'm wondering how to trigger variable creation. Whenever a variable is created i want my own function myFun(...) to be started. if (exists("x")) {rm(x)} # after removal of x # any of these calls x<-10 # should call myFun x=10 # should call myFun assign(x,10) # should call myFun etc.
2015 Oct 22
2
Changed behaviour when passing a function?
Of course (and unsurprisingly) Duncan is correct. I see that behavior in R 3.1.0, as well as the modern ones Duncan mentioned. What I said is true, as far as it goes, but the symbol being resolved is FUN, so when looking for a function it doesn't find the function version of round. Did you perhaps have a function named FUN in your global environment? If so you are being bitten by what I
2002 Jan 07
1
Mishandling missing "..." (PR#1247)
R> myfun <- function(x, ...) {x[...] <- 0; x} R> myfun(3) Error in myfun(3) : SubAssignArgs: invalid number of arguments It fails because no ... was passed. The workaround (and desired behavior) is: R> myfun <- function(x, ...) {if (missing(...)) x[] <- 0 else x[...] <- 0; x} R> myfun(3) [1] 0 Deja vu? This is the one piece of my PR#1110 (Oct 3, 2001) that I
2011 Jul 23
1
call a function with explicitly not setting an argument
Is there a way to call a function, and explicitly set an argument to 'not specified'? My situation is the following. I have a function which passes on most of its arguments to another function. The second function, myfun2, serializes all arguments and is out of my control. myfun <- function(...){ return(myfun2(...)); } now, the value for arguments of myfun are stored in variables.
2012 Jul 05
1
Extracting srcref for S4 methods
Hi, on R version 2.15.1 (2012-06-22) (Platform: i686-pc-linux-gnu (32-bit)) sourced functions have srcref attached as an attribute. Are such data also available for S4 generics and methods? How? (See sample code below) Thank you. Bests, Renaud f <- textConnection( " f <- function(){} setGeneric('myfun', function(x, ...) standardGeneric('myfun'))
2007 Feb 23
1
how to use apply with two variables
Hi, this is a made-up example. Function "myfun" returns two arguments. Can "apply" be used so that "myfun" is called only once? Thanks Serguei mat<-matrix(runif(50),nrow=10,ncol=5) myfun<-function(x) { mymean<-mean(x) mysd<-sd(x) return(mymean,mysd) } out1<-t(apply(mat,1,function(x) myfun(x)$mymean)) out2<-t(apply(mat,1,function(x)
2011 Feb 03
1
mapply question (?)
Hi, I have a function myFun which I want to call multiple times, using different argument lists. myFun("v1", "2009", 1) myFun("v2", "2008", 1) myFun("q", "2001") How can I easily do this in R? Should I use mapply? I unsuccessfully tried something like: x <- list(c("v1", "2009", 1), c("v2",
2023 Aug 03
3
feature request: optim() iteration of functions that return multiple values
Dear all, I have used optim a lot in contexts where it would useful to be able to iterate function myfun that, in addition to the primary objective to be minimized ('minimize.me'), could return other values such as alternative metrics of the minimization, informative intermediate values from the calculations, etc. myfun <- function() { ... return(list(minimize.me = minimize.me, R2 =
2011 Sep 26
4
Testing for arguments in a function
I don't understand how this function can subset by i when i is missing.... ## My function: myfun = function(vec, i){ ret = vec[i] ret } ## My data: i = 10 vec = 1:100 ## Expected input and behavior: myfun(vec, i) ## Missing an argument, but error is not caught! ## How is subsetting even possible here??? myfun(vec) Is there a way to check for missing function arguments, *and*
2009 Oct 21
1
formula and model.frame
Suppose I have the following function myFun <- function(formula, data){ f <- formula(formula) dat <- model.frame(f, data) dat } Applying it with this sample data yields a new dataframe: qqq <- data.frame(grade = c(3, NA, 3,4,5,5,4,3), score = rnorm(8), idVar = c(1:8)) dat <- myFun(score ~ grade, qqq) However, what I would like is for the resulting dataframe (dat) to include
2013 Jun 07
1
It seams that fast99 function (sensitivity package) does not work out for norm distribution.
Dear all mailing listers, Does Anyone have the same problem as mine when using the fast99 (extended-FAST method) to perform SA of model with norm distribution inputs? See the simple example given following. Any suggestion will be greatly appreciated. Thank you! Marino # Simple example # 1. uniform version (It works well) library(sensitivity) Myfun<-function(x){return(rowSums(x))} SA1
2010 Aug 11
2
storing the results of an apply call
Hi R-users, I have a function (myfun) that I want to apply to the rows of a matrix. Basically, "myfun" takes the values from the matrix ("exp.des"), which represent the different combinations of my experimental design, and pass them as arguments to some other functions (fun1 and fun2). As I want to replicate the results of fun1 and fun2 a certain number of time (e.g. 5), I
2002 Apr 30
1
MemoryProblem in R-1.4.1
Hi all, In a simulation context, I'm applying some my function, "myfun" say, to a list of glm obj, "list.glm": >length(list.glm) #number of samples simulated [1] 1000 >class(list.glm[[324]]) #any component of the list [1] "glm" "lm" >length(list.glm[[290]]$y) #sample size [1] 1000 Because length(list.glm) and the sample size are rather large,
2011 Oct 11
2
stop()
Suppose I have a function, such as the toy example below: myFun <- function(x, max.iter = 5) { for(i in 1:10){ result <- x + i iter <- i if(iter == max.iter) stop('Max reached') } result } I can of course do this: myFun(10, max.iter = 11) However, if I reach the maximum
2011 Jul 25
1
do.call in "with" construction
Dear all, I'd appreciate any help to rectify what must be a misconception of mine how environments work: ########################## myEnv <- new.env() myEnv$a.env <- 1 myEnv$symbols.env <- "a.env" a.global <- 2 symbols.global <- "a.global" myFun <- function(symbols){do.call("print", lapply(symbols, FUN=as.name))} do.call("myFun",