similar to: R-Help

Dear r-users, Suppose I have three datasets: Dataset-1: Date x y Jan-1,2005 120 230 Jan-2,2005 123 -125 Jan-3,2005 -110 300 Jan-4,2005 114 -21 Jan-7,2005 11 299 Mar-5,2005 200 311 Dataset-2: Date x y Jan-2,2005 123 -125 Jan-3,2005 -110 300 Jan-4,2005 114 -21

Hi, Try this: lines1<- readLines(textConnection("gene1 or1|1234 or3|56 or4|793 gene4 or2|347 gene5 or3|23 or7|123456789")) lines2<-readLines(textConnection(">or1|1234 ATCGGATTCAGG >or2|347 GAACCTATCGGGGGGGGAATTTATATATTTTA >or3|56 ATCGGAGATATAACCAATC >or3|23 AAAATTAACAAGAGAATAGACAAAAAAA >or4|793 ATCTCTCTCCTCTCTCTCTAAAAA >or7|123456789

Hello, I have a question and need your help urgently. I am new to R but want to learn it. I have several files in a folder which I have imported to R using : temp = list.files(pattern="*.txt") >myfiles = lapply(temp, read.delim) The resulting files are on the workspace stored as List[110]. So they are 110 files in the list. Each file has several different columns and rows. My

Dear R developers A question about the class 'listof', defined in package 'stats'. Other than its definition and use in the code for 'anova', we can't see that the class 'listof' is used for anything else (in recommended packages, or elsewhere). In the spatstat package we have been using a 'listof' to represent a list of spatial objects of the same

Hi all; I have a data set with the format below: Year, Day, Hour, Value 2010, 001, 0, 15.9 2010, 001, 1, 7.3 2010, 001, 2, 5.2 2010, 001, 3, 8.0 2010, 001, 4, 0.0 2010, 001, 5, 12.1 2010, 001, 6, 11.6 2010, 001, 7, 13.9 2010, 001, 8, 11.9 2010, 001, 9, 13.6 2010, 001, 10, 16.1 2010, 001, 11, 18.5 That should

Hi, all I've written some R script to calculate the linear regression of a matrix. Here below is my script: >x<-matrix(scan("h:/data/xxx.dat",0),nrow=46,ncol=561,byrow=TRUE) >year <- NULL >year <- cbind(year,as.matrix(x[,1])) >lm.sol<-lm(x~year) >xtrend<-coef(lm.sol)[2,] # get the matrix of regression coefficient >t.test<- ?

I'm trying to write a function to automate doing a variance analysis, part of which involves doing some further calculations. The method I've been using isn't very robust, if variable names change then it stops working. For this dummy data > dput(assayvar,"") structure(list(Run = structure(c(1L, 1L, 1L, 2L, 2L, 2L, 3L, 3L, 3L, 4L, 4L, 4L), .rk.invalid.fields =

Dear R users,[IF THE FORMAT OF MY EMAIL IS NOT CLEAR, I HAVE ATTACHED A TEXT FILE FOR A CLEAR VIEW] I would like to use the R output file in Fortran. my file Is exactly in the following format. ELISA/BOTTO wATER INN FROM 1900 11 1 TO 1996 12 31 1901.11. 1 447.000 1901.11. 2 445.000 1901.11. 3 445.000 1924.11. 4 445.000 1924.11. 5 449.000 1924.11. 6 442.000 1924.11. 7

Hi, I have a data frame with one column and several rows of the form. "Peak Usage : init:2359296, used:15859328, committed:15892480, max:50331648Current Usage : init:2359296, used:15857920, committed:15892480, max:50331648|-------------------|" I tested the regex Current.*?[\|] in an online tester which greedily matches upto the first 'pipe' character Current

Hi, is anybody out there who knows APL and would help me to translate 52 lines of APL code into propper R? best, Torsten

Hello, I have a list of data with multiple elements, and each element in the list has multiple variables in it. Here's an example: ### Make the fake data dv <- c(1,3,4,2,2,3,2,5,6,3,4,4,3,5,6) subject <- factor(c("s1","s1","s1","s2","s2","s2","s3","s3","s3",

Readers, I have data with different time stamps that I wish to plot (for example): data set 1 time(hh:mm:ss),datum 01:00:00,500 01:00:15,600 01:00:30,750 01:00:45,720 01:01:00,700 01:01:15,725 01:01:30,640 01:01:45,710 data set 2 time,datum 01:00:12,20 01:01:01,55 01:01:55,22 The time interval in data set 1 does not change, but the time interval in data set 2 does change, such that for a

Dear Eliza, Try this: Lines1<-readLines(textConnection("1911.01.01?????? 7.87 1911.01.02?????? 9.26 1911.01.03?????? 8.06 1911.01.04?????? 8.13 1911.01.05????? 12.90 1911.02.06?????? 5.45 1911.02.07?????? 3.26 1911.03.08?????? 5.70 1911.03.09?????? 9.24 1911.04.10?????? 7.60 1911.05.11????? 14.82 1911.05.12????? 14.10 1911.06.13?????? 7.87 1911.06.14?????? 9.26

I'm very new to R and utterly blown away by not only the language but the unbelievable set of packages and the documentation and the documentation standards and... I was an early APL user and never lost my love for it and in R I find most of the essential things I loved about APL except for one thing. At this early stage of my learning I can't yet determine if there is a way to

http://idisk.mac.com/jdeleeuw-Public/utilities/apl/apl.R Dedicated to the IBM 2741. Implemented for general multidimensional arrays: drop, take, reshape, shape, rank, select, generalized inner product, generalized outer product, representation, base value, join, expand, reduce, scan, member of, ravel, compress, tranpose, rotate Basically, the APL-I part is complete, and after some testing

I have two files with dates and prices in each. The number of rows in each of them will differ. How do I create a new file which contains data from both these files? Cbind and merge are not helpful. For cbind because the rows are not the same replication occurs. Also if I have similar data how do I write a vlookup kind of function? I am giving an example below: Say Price1 file contains the

Hi, set.seed(45) test1<-data.frame(columnA=rnorm(7,45),columnB=rnorm(7,10)) #used an example probably similar to your actual data apply(test1,2,function(x) sprintf("%.1f",median(x))) #columnA columnB # "44.5"? "10.2" par(mfrow=c(1,2)) lapply(test1,function(x) {b<-

I'm trying to import a matrix created in PARI/GP into R but am having problems. The data in the text file has entries separated by commas but the rows themselves are separated by semicolons rathen than being on a new line. Is there a way to get R to recognise that ";" means start a new row ? -- View this message in context:

Hi R users, Wonder if somebody could give me help on how to reshape this type of data: ----------------------------------------------------------------------------------------------------------------------- Date:10.09.19 Time:21:39:05 Lat:N62.37.18 Long:E018.07.32 0000-0010 | 28| 28 0010-0020| 302| 302 0020-0030| 42| 42 0030-0040| 2| 2 0040-0050| 1| 1 0060-0070| 1| 1

nowhere does it say that centos is approved for use in DoD. it is not on the APL, only RedHat and SuSE