similar to: insert value according to indice

Displaying 6 results from an estimated 6 matches similar to: "insert value according to indice"

2006 Feb 08
1
adding variable into dataframe by indice
R-Helpers, I am trying to insert a value into a dataframe. This value is a proportion calculated by counting the number of those individuals with that value and then inserting the proportion at the end of the dataframe to only those individuals with the given value. The problem I am running into is that the proportions are not being attached to only those individuals with the specified value
2010 May 20
1
sqldf: issues with natural joins
Hello, I'm having trouble discovering what's going wrong with my use of natural joins via sqldf. Following the instructions under 4i at http://code.google.com/p/sqldf/, which discusses creating indices to speed joins, I have been only unreliably able to get natural joins to work. For example, > Tid <- c('AES 01-01-02 10:58:00', 'AES 01-01-02 11:53:00', 'AES
2010 Jan 11
1
Getting a date out of an indice in a time series
I have a weekly data set imported via: tsSource=ts(sh1$I000,start=c(2004,1),freq=52) I am now getting to some 'spit and polish' but I realize something I can't wrap my head around. Given an outlier I find at say tsSource[54] ... how can get translate index 54 into the date\week. I mean I can figure out obviously that entry 52 is last week of 2004 but since the data goes for many
2011 Nov 15
3
how to indice the column in the data.frame
hi R,users Now I read a data from a txt file newdata<-read.table("1.txt") in the 1.txt ,there are several column shown as below 1 3 4 5 2 3 5 6 4 5 6 7 so when I want analysis the second column anadata<-newdata$V2 but my question I can not use some certain variable to indice the column? e.g cmn=2 anadata<-newdata$Vcmn how can I finish this command ?can anyone help me ? thank
2016 Sep 06
2
usar un for para cambiar indice
Estimados usuarios-de-R: Tengo un problema. Si por ejemplo tengo una lista conformada por la serie historia del PBI de 10 paƬses. >Tiempo <- seq(1:100) >plot(Tiempo, PP$"Serie 1", type="l",col="1") >lines(Tiempo, PPcapita$"Serie 2") >lines(Tiempo, PPcapita$"Serie 3") >lines(Tiempo, PPcapita$"Serie 4")
2004 Jul 08
2
Getting elements of a matrix by a vector of column indice s
See if the following helps: > m <- outer(letters[1:5], 1:4, paste, sep="") > m [,1] [,2] [,3] [,4] [1,] "a1" "a2" "a3" "a4" [2,] "b1" "b2" "b3" "b4" [3,] "c1" "c2" "c3" "c4" [4,] "d1" "d2" "d3" "d4" [5,]