Displaying 20 results from an estimated 3000 matches similar to: "matrix math"
2012 Oct 31
2
Aggregate Table Data into Cell Frequencies
R-help -
I have this set of aggregated tables (sample data below via dput()). And I
would like to have delayValue as the column variables with the "temp"
(temp1, temp2, temp3) values as the row variables. However I would like to
have the temp variables *aggregated into single rows* so that I have the
frequency ("Freq" | counts) of each time each "delayValue" occurs
2010 Nov 19
3
Sweave Dynamic Graph Question
i have a time Series of IBM closing px from 1/1/2000 to today
I want to graph the time serie by dividing the graph by year and month
all the monthly graphs with the same year will go to one page. so from
1/1/2000 to 11/19/2010. i will have
11 pages, and each page will have 12 graphs (jan to dec) except for 2010.
I am able to do it in R, but when i use sweave, I can only print the last
page.
2011 Mar 09
2
Anomaly with unique and match
I stumbled onto this working on an update to coxph. The last 6 lines
below are the question, the rest create a test data set.
tmt585% R
R version 2.12.2 (2011-02-25)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: x86_64-unknown-linux-gnu (64-bit)
# Lines of code from survival/tests/singtest.R
> library(survival)
Loading required package: splines
2005 Dec 29
1
Problems with calloc function.
Hi all,
I have a C code in Linux, it has 7 pointers and compile e run OK, but when I
run in R happens problems with calloc function, it returns NULL.
###############################################
> int *temp1,*temp2,*temp3,*temp4;
temp1 = (int *)calloc(col,sizeof(int));
if(temp1 == NULL){
printf("\n\n No Memory1!");
exit(1);
}
temp2 = (int *)calloc(col,sizeof(int));
2010 Oct 17
4
how to convert string to object?
temp = "~aparch("
temp1 = paste(temp,1, sep = "")
temp2 = paste(temp1,1, sep = ",")
temp3 = paste(temp2, ")",sep = "")
temp 3 is a character but I want to convert to formula object. How do I do
this?
--
View this message in context: http://r.789695.n4.nabble.com/how-to-convert-string-to-object-tp2999281p2999281.html
Sent from the R help mailing
2012 Mar 29
1
Error, Variable is Missing
Hi, I am writing a function to plot a pdf of a distribution,
GNL.pdf.fn = function(x,mu,sigma,alpha,beta,rho)
{
y = x-rho*mu
cf.fn = function(s){
cplex = complex(1,0,1)
temp1 = alpha*beta*exp(-sigma*s^2/2)
temp2 = (alpha-cplex*s)*(beta+cplex*s)
out = (temp1/temp2)^rho
out
}
temp.fn = function(s){
(Mod(cf.fn(s)))*cos(Arg(cf.fn(s))-s*y)
}
int.fn =
2013 Mar 29
1
multiple plots and looping assistance requested (single plot)
HI Irucka,
Please check this:
temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L,
2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342,
12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA,
-4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L,
3L, 4L, 5L, NA), Data1 = c(1.52,
2025 Jan 28
1
R CMD check says no visible binding for global variable
Naresh,
I am not sure how you are creating your data.frame so it has no, I think, column names. There are two scenarios including one where it is not really a valid data.frame and one where it can be handled before any other use as shown below. If it cannot be used, you might need to modify how your SQL or the function you call creates it so it includes either names it chooses or that you supply.
2025 Jan 28
1
R CMD check says no visible binding for global variable
There you go, once again helping strengthen ;)
John
Get Outlook for iOS<https://aka.ms/o0ukef>
________________________________
From: R-help <r-help-bounces at r-project.org> on behalf of avi.e.gross at gmail.com <avi.e.gross at gmail.com>
Sent: Tuesday, January 28, 2025 12:01:25 AM
To: 'Naresh Gurbuxani' <naresh_gurbuxani at hotmail.com>; r-help at r-project.org
2012 Jul 14
2
Loading in Large Dataset + variables via loop
Hello, I'm new to R with a (probably elementary) question.
Suppose I have a dataset called /A/ with /n/ locations, and each location
contains within it 3 time series of different variables (all of 100 years
length); each time series is of a weather variable (for each location there
is a temperature, precipitation, and pressure). For instance, location 1
has a temperature1 time series, a
2025 Jan 28
2
R CMD check says no visible binding for global variable
Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns.
Something like:
Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;?
Prices <- dbGetQuery(con, myquery)
SetDT(Prices)
Prices[, date = as.Date(date)]
R CMD check say ?no visible binding for global variable ?date??
Sent
2025 Jan 28
1
R CMD check says no visible binding for global variable
On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote:
> Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns.
>
> Something like:
>
> Myquery <- ?SELECT date, price, stock FROM stocktab WHERE stock = ?ABC? AND date > ?2025-01-01?;?
>
> Prices <- dbGetQuery(con, myquery)
> SetDT(Prices)
> Prices[,
2009 Feb 11
2
error in my previous message
i'm sorry. i had an error in my previous code because i left out a
letter in the rownames.
while fixing that, i also found a solution. so i'm sorry for the
confusion.
below is my fix.
temp2 <- matrix(rnorm(10),nc=1,nrow=10)
rownames(temp2) <-
2009 Feb 11
2
sorting a matrix by the column
this is a bad question but I can't figure it out and i've tried. if i
sort the 2 column
matrix , temp1, by the first column, then things work as expected. But,
if I sort the 1 column matrix, temp2, then it gets turned coerced to a
vector. I realize that I
need to use drop=FALSE but i've put it in a few different places with no
success. Thanks.
temp1 <-
2025 Jan 28
1
R CMD check says no visible binding for global variable
This solution worked.
Thanks
Sent from my iPhone
> On Jan 28, 2025, at 3:09?PM, Duncan Murdoch <murdoch.duncan at gmail.com> wrote:
>
> ?On 2025-01-28 1:55 p.m., Naresh Gurbuxani wrote:
>> Data.frame is returned by SQL query. It does have column names. In the function, I make small changes to some columns.
>> Something like:
>> Myquery <- ?SELECT date,
2025 Jan 28
2
R CMD check says no visible binding for global variable
That is an interesting fix Duncan suggested and it sounds now like everything WORKED as intended in data.table except that any checker being used externally is not able to del with things that look like a variable but are actually not a variable currently visible except within a function that is doing deferred evaluation. In this case, it recognizes the raw unevaluated string as being the name of
2008 Jun 23
2
Handle missing values
Hi everyone
I am new to R and have a question about missing values. I am trying to
do a cluster analysis of monthly temperatures and my data are 14 columns
with spatial coordinates (lat,lon) and 12 monthly values:
/lat - lon - temp1 - //temp2 - temp3 - .... - //temp12/
If I omit missing values (my missing values are 99.00) with
/mydata <- na.omit(mydata)/
every row with a
2006 Mar 03
1
NA in eigen()
Hi,
I am using eigen to get an eigen decomposition of a square, symmetric
matrix. For some reason, I am getting a column in my eigen vectors (the
52nd column out of 601) that is a column of all NAs. I am using the option,
symmetric=T for eigen. I just discovered that I do not get this behavior
when I use the option EISPACK=T. With EISPACK=T, the 52nd eigenvector is
(up to rounding error) a
2013 Mar 07
5
multiple plots and looping assistance requested (revised codes)
Hi Irucka,
I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1]
?temper[[1]][1] # which is the column 1.
? Month
1???? 1
2???? 2
3???? 3
?temper[[1]][2]
#? Data1
#1?? 1.5
#2? 12.3
#3? 11.4
Suppose I use names(temper) instead of seq_along(temper)
pdf("irucka.pdf")
?lapply(names(temper),function(i)
2009 May 28
2
Replace is leaking?
Okay, someone explain this behaviour to me:
Browse[1]> replace(rep(0, 4000), temp1[12] , temp2[12])[3925]
[1] 0.4462404
Browse[1]> temp1[12]
[1] 3926
Browse[1]> temp2[12]
[1] 0.4462404
Browse[1]> replace(rep(0, 4000), 3926 , temp2[12])[3925]
[1] 0
For some reason, R seems to shift indices along when doing this replacement.
Has anyone encountered this bug before? It seems to crop up