similar to: Parameter Constraints in nls.lm()

Displaying 20 results from an estimated 6000 matches similar to: "Parameter Constraints in nls.lm()"

2006 Jan 12
1
Problem with NLSYSTEMFIT()
Hello, I want to solve a nonlinear 3SLS problem with "nlsystemfit()". The equations are of the form y_it = f_i(x,t,theta) The functions f_i(.) have to be formulated as R-functions. When invoking "nlsystemfit()" I get the error Error in deriv.formula(eqns[[i]], names(parmnames)) : Function 'f1' is not in the derivatives table
2006 Jan 23
1
varphi symbol for ylab expression
Hi all, it is possible to invoke certain graphical functions (e.g. curve) with an expression argument, e.g. "ylab=expression(phi)". There are some greek letters with a second script. For instance, in latex two symbols do exist: phi and varphi. Is the second symbol also available in an expression()? If yes, how? Kind regards, Kilian
2007 Sep 04
1
(fwd) Bug#440721: FTBFS on sparc while linking usr/klibc/libc.so
new klibc sparc build failure against gcc 4.2 ----- Forwarded message from Kilian Krause <kilian at debian.org> ----- Subject: Bug#440721: FTBFS on sparc while linking usr/klibc/libc.so From: Kilian Krause <kilian at debian.org> To: Debian Bug Tracking System <submit at bugs.debian.org> Date: Mon, 03 Sep 2007 23:35:23 +0200 Package: klibc Version: 1.5.6-2 Severity: serious
2010 Feb 16
1
nls.lm & AIC
Hi there, I'm a PhD student investigating growth patterns in fish. I've been using the minpack.lm package to fit extended von Bertalanffy growth models that include explanatory covariates (temperature and density). I found the nls.lm comand a powerful tool to fit models with a lot of parameters. However, in order to select the best model over the possible candidates (without covariates,
2013 Apr 01
2
Is DUD available in nls()?
SAS has DUD (Does not Use Derivatives)/Secant Method for nonlinear regression, does R offer this option for nonlinear regression? I have read the helpfile for nls() and could not find such option, any suggestion? Thanks, Derek [[alternative HTML version deleted]]
2009 Feb 12
1
Using nls or nls.lm with a simulation output
We would like to fit parameters using a simulation with stochastic processes as theoretical values. We generate a simple exemple with nls.lm to see the logic and the problem: First without stochasticity (it is a dummy example, the fited value is simple the mean of a set of 10 numbers): #Ten numbers x <- 1:10 #Generate 10 Gaussian random number with mean=3 sd=1 simy <- rnorm(length(x),
2011 Mar 15
1
Problem with nls.lm function of minpack.lm package.
Dear R useRs, I have a problem with nls.lm function of minpackl.lm package. I need to fit the Van Genuchten Model to a set of data of Theta and hydraulic conductivity with nls.lm function of minpack.lm package. For the first fit, the parameter estimates keep changing even after 1000 iterations (Th) and I have a following error message for fit of hydraulic conductivity (k); Reason for
2017 Jan 12
2
[PATCH v2 1/2] drm/nouveau: Don't enabling polling twice on runtime resume
As it turns out, on cards that actually have CRTCs on them we're already calling drm_kms_helper_poll_enable(drm_dev) from nouveau_display_resume() before we call it in nouveau_pmops_runtime_resume(). This leads us to accidentally trying to enable polling twice, which results in a potential deadlock between the RPM locks and drm_dev->mode_config.mutex if we end up trying to enable polling
2007 Nov 21
3
R as server application
Is there a way to use R as a client server application? Whitch means: 1. install R on a server (running as a service) 2. from client send R-scripts through IDE/Editor (TINN-R) to "R-server" 3. receive R-output on client All the Best Kilian Schwab
2006 Oct 27
1
Error using "White-corrected" Anova (white.adjust="hc3")
Hello. I try to compute a "White-corrected" ANOVA. Therefore I use the command "Anova" implemented in the car()-package): Anova(modelname, white.adjust="hc3") and receive the error message: "Fehler in SS[i] <- SS.term(names[i]) : nichts zu ersetzen" (German) "Error in SS[i] <- SS.term(names[i]) : nothing to replace" (probably being the
2005 Nov 03
1
How to calculate errors in histogram values
Hi there, I'm new to R but I thought this is the most likely place I could get advice or hints w.r.t the following problem: I have a series of measurements xi with associated uncertainties dxi. I would like to construct the probability density histogram of this data where each density estimate has an associated error that is derived from the dxi. In other words, for large dxi the
2008 Jun 05
1
nls() newbie convergence problem
I'm sure this must be a nls() newbie question, but I'm stumped. I'm trying to do the example from Draper and Yang (1997). They give this snippet of S-Plus code: Specify the weight function: weight < - function(y,x1,x2,b0,b1,b2) { pred <- b0+b1*x1 + b2*x2 parms <- abs(b1*b2)^(1/3) (y-pred)/parms } Fit the model gmfit < -nls(~weight(y,x1,x2,b0,b1,b2),
2000 Apr 28
1
Perfornmance Problem with large files
Hello, i have a linux box running samba as a fileserver for 4 Windows NT 4.0 Workstations. the performance is good on responing-times but loading and writing large files (more than 500 kByte) is too slow. All the users ale working as guest-users. Can this be the cause for my problem? This is my smb.conf file: **************************************************************************** [global]
2006 Jan 30
1
--files-from and --delete mutually exclusive?
Hi rsync developers, I'm trying to get some fancy mirroring done with selecting files from a larger archive through the --files-from option. The only problem that I do see is that rsync will not eat the --delete option whatever I try. Thus, all the old files remain in the mirror archive instead of being deleted. To be more clearly, I want the rsync --files-from option to behave like
2004 Aug 04
4
Asterisk Integration
Can some one give me a tip on how do I integrate two asterisks Thanks Felippe Kilian Martins NPD-UFSC ---------------------------------------------------------------- This message was sent using IMP, the Internet Messaging Program.
2010 Apr 29
1
lm() with non-linear coefficients constraints? --- nls?
dear R experts---quick question. I need to estimate a model that looks like y = (b*T+d*T^3) + (1-b-3*d*T^2)*x + (3*d*T)*x^2 + (-d)*x^3 I only have three parameters. Is nls() the right tool for the job, or is there something faster/better? /iaw ---- Ivo Welch (ivo.welch@brown.edu, ivo.welch@gmail.com) [[alternative HTML version deleted]]
2017 Jun 18
2
R_using non linear regression with constraints
I am using nlsLM {minpack.lm} to find the values of parameters a and b of function myfun which give the best fit for the data set, mydata. mydata=data.frame(x=c(0,5,9,13,17,20),y = c(0,11,20,29,38,45)) myfun=function(a,b,r,t){ prd=a*b*(1-exp(-b*r*t)) return(prd)} and using nlsLM myfit=nlsLM(y~myfun(a,b,r=2,t=x),data=mydata,start=list(a=2000,b=0.05), lower = c(1000,0),
2012 Sep 16
1
trying to obtain same nls parameters as in example
Dear R-users; I'm working with a a dataset that was previously used to fit a nonlinear model of the form: Y ~ a * (1 + b * log(1 - c * X^d)) The parameters published elsewhere are: a = 1.758863, b = .217217, c = .99031, and d = .054589 However, there is no way I can replicate this result. I've tried several options (including SAS) w/o success. The data is: X <-
2010 Apr 06
1
estimating the starting value within a ODE using nls and lsoda
All- I am interested in estimating a parameter that is the starting value for an ODE model. That is, in the typical combined fitting procedure using nls and lsoda (alternatively rk4), I first defined the ODE model: minmod <- function(t, y, parms) { G <- y[1] X <- y[2] with(as.list(parms),{ I_t <- approx(time, I.input, t)$y dG <- -1*(p1 + X)*G +p1*G_b dX <-
2008 May 07
3
function in nls argument
Greetings R users, maybe there is someone who can help me with this problem: I define a function "optim.fun" and want as output the sum of squared errors between predicted and measured values, as follows: optim.fun <- function (ST04, SM08b, ch2no, a, b, d, E) { predR <- (a*SM08b^I(2)+b*SM08b+d)*exp(E*((1/(283.15-227.13))-(1/(ST04+273.15-227.13)))) abserr