similar to: panel order in xyplot

Hi there, I am wondering if it is possible to do an xyplot with two y-axes. I'd like to print two parameters in a time series but they both have different scales. Which parameter in xyplot can I add to achieve this result? Thanks a lot for any help. Antje [[alternative HTML version deleted]]

Hi there, I have a question, which I thought is very easy to solve, but somehow I can't find a solution. Probably someone could help me quickly? Here it is: I have two matrices: a [,1] [,2] [,3] [1,] 1 4 9 [2,] 2 6 10 [3,] 3 6 11 [4,] 4 8 12 b [,1] [,2] [1,] 1 4 [2,] 2 5 [3,] 3 6 Now I want to find

Dear group, First I provide you with an example, I found in the newsgroup. Then I'd like to explain my problem to you by means of the output. enviro <- data.frame(Year = rep(2001:2002, each = 365), Day = rep(1:365, 2), Precip = pmax(0, rnorm(365 * 2)), Temp = 2 + 0.2 * rnorm(365 * 2)) xyplot(Precip + Temp ~ Day | Year,

Hi, In voicemail.conf: ; Supported values: ; 'filename' filename of a soundfile (single ticks around the filename ; required) ; ${VAR} variable substitution ; A or a Day of week (Saturday, Sunday, ...) ; B or b or h Month name (January, February, ...) ; d or e numeric day of month (first, second, ..., thirty-first) ; Y Year ; I or l

Hello, I'm trying to plot dayly evolution of the temperature over France from Global Forecast System files ("I'm trying" is the right expression...). akilonlat03 is the temperature for different latitudes and longitudes ? 3 o'clock. akilonlat06 is the temperature for different latitudes and longitudes ? 6 o'clock. I would like to plot akilonlat03 and then akilonlat06

Apparently, as.POSIXlt takes one o'clock as the start of the day : > as.POSIXlt(0,origin="1970-01-01") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 00:00:00") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 23:59:59") [1] "1970-01-02 00:59:59 CET" Cheers -- Joris Meys Statistical

Dear Group, Having a character vector like this one: [1] "03:38:55" "07:42:38" "08:04:27" "08:17:13" "08:41:14" "08:46:58" [7] "08:47:11" "08:53:51" "08:57:51" "08:58:56" I try to do a histogram over times of a day. All I want to know, if my solution is proper or if there is another

I have some time series data like 01/02/1990 0.531 0.479 01/03/1990 0.510 0.522 01/06/1990 0.602 0.604 there is no weekends and holidays. how do I graph them in a single plot that the x-axis is the dates and the y-axis is the time series? Thank you Regards, Jincai Jiang (Office) 212-761-3984 -------------------------------------------------------- This is not an offer (or solicitation

Hi all, I would like to start replacing the realmedia content on a clients web site with the Ogg format. The client (a national tv/radio station) publishes alot of content and have integrated their CMS with the Realmedia system in order to index multimedia with story lines. Eg the following link would be published inside a RAM file to point to the start and end times of a story from the 6

Dear R-helpers, In my data set, I have a time variable 'RecordTime' whose class property is 'times'. When I list my data set, I see the values of RecordTime is like 10:20:30 in a 'h:m:s' format. Suppose I want to choose all the data after 10 o'clock, then use subset(data,RecordTime>10:20:30) just doesn't work. I noticed that all the values of RecordTime seem

Hey, I'm new to R but familiar with other programming languages. Basically, I want to store an array of dates. For each of these dates I want to store only the day of the week and the hour. So for example: "Monday 12" would be Monday at 12 o'clock and "Tuesday 20" would be Tuesday at 8 p.m. Alternatively it could be stored as 0-6 for Sunday to Saturday. So Tuesday

Dear List, I'm trying to use R under Windows on a huge database in MySQL via ODBC (technical reasons for this...). Now I want to read tables with some 160.000.000 entries into R. I would be lucky if anyone out there has some good hints what to consider concerning memory management. I'm not sure about the best methods reading such huge files into R. for the moment I spilt the whole

Man, R has a steep learning curve (but I suppose you all know this). I have very little programming knowledge, so when I search for answers to my questions, I struggle with making sense of a lot of the pages. I have a spreadsheet that I've read into R using read.csv. I've also attached it. It looks like this (except there are 1600+ entries): > Sunday SunDate SunTime

Hi all, I'd like to know, if I can solve this with a shorter command: a <- rnorm(100) which(a > -0.5 & a < 0.5) # would give me all indices of numbers greater than -0.5 and smaller than +0.5 I have something similar with a dataframe and it produces sometimes quite long commands... I'd like to have something like: which(within.interval(a, -0.5, 0.5)) Is there anything I

Hello, I tried to fit a poisson distribution but looking at the function fitdistr() it does not optimize lambda but simply estimates the mean of the data and returns it as lambda. I'm a bit confused because I was expecting an optimization of this parameter to gain a good fit... If I would use mle() of stats4 package or mle2() of bbmle package, I would have to write the function by myself

Hello, I'm looking for a solution for the following problem: I have two vectors V1 <- c("apple","honey","milk","bread","butter") V2 <- c("bread","milk") now, I would like to know for each element in V1 if it's equal to one of the elements in V2 I could do: which(V1 == V2[1] | V1 == V2[2]) but what if I

Hello, I have a question how to reshape a given matrix to a data frame. # ---------------------------------- > a <- matrix(1:25, nrow=5) > a [,1] [,2] [,3] [,4] [,5] [1,] 1 6 11 16 21 [2,] 2 7 12 17 22 [3,] 3 8 13 18 23 [4,] 4 9 14 19 24 [5,] 5 10 15 20 25 > colnames(a) <- LETTERS[1:5] > rownames(a) <-

Hello, I'm not very experienced with lattice and I was wondering whether I get get some hints from you how to create a pure heatmap (using levelplot), without any axis, title, legend, margin at all... I just want to see the coloured squares, nothing else. Any suggestions? Antje

Hello, I hope this question is not too stupid. I would like to know how to update levels after subsetting data from a data.frame. df <- data.frame(factor(c("a","a","c","b","b")), c(4,5,6,7,8), c(9,1,2,3,4)) names(df) <- c("X1","X2","X3") my.sub <- subset(df, X1 == "a" | X1 == "b")

Hi there, as I'm not sure to understand the coloring levelplot uses, I'm looking for another easy way to create a heatmap like this: library(lattice) mat <- matrix(seq(1,5, length.out = 12), nrow = 3) mat[1,2] <- 3.5 my.at <- seq(0.5,5.5, length.out = 6) my.col.regions <- rainbow(5) graph <- levelplot(t(mat[nrow(mat):1, ] ), at = my.at, col.regions = my.col.regions)