Displaying 20 results from an estimated 11000 matches similar to: "change read.table by scan"
2005 Jul 22
1
multiplicate 2 functions
Thks for your answer,
here is an exemple of what i do with the errors in french...
> tmp
[1] 200 150 245 125 134 345 320 450 678
> beta18
Erreur : Objet "beta18" not found //NORMAL just to show it
> eta
[1] 500
> func1<-function(beta18) dweibull(tmp[1],beta18,eta)
> func1<-func1(beta18) * function(beta18)
dweibull(tmp[2],beta18,eta)
Erreur dans dweibull(tmp[1],
2005 Jul 27
1
thks all
hi all
I wish to thanks every body on the R mailing list for answering very fast, directly in my mail box ;).
I've finish my work with R and i can say that it is very difficult at the beginning, and when you succeed you are stopped by a stack overflow when you call your nice recursive function (which was working with a tab of 100 element) with a tab of 900 elements, but R just do what you
2005 Dec 07
2
concatenate data frame
hi all
Here is a small part of my code:
tab_tmp<-tab[1:(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])),length(tab)];
tab_tmp1<-tab[(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])):length(TotalFillTimeHours),length(tab)];
tab<-c(tab_tmp,tab_tmp1);
attach(tab);
Here is the output:
Error in attach(tab) : attach only works for lists and data frames
Execution halted
2005 Dec 16
1
column name of a table
hy all,
I wish to switch in a part in my code that use "read.table" to "scan", actually i use this:
tab<-scan("data.dat",what=integer(),skip=1)
dim(tab)<-c(75,length(tab)/75)
tab<-t(tab)
It gives me a new tab with 75 columns, but i when i was using read.table with headers then attach i could use the columns names to access the data values, now how can i
2005 Oct 18
2
hist of dates
Hi all
I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong...
> hist.Date(dt_cycles)
Error: couldn't find function "hist.Date"
> hist.date(dt_cycles)
Error: couldn't find function "hist.date"
> cycles
[1] 7 1
2006 Jan 04
1
produce hours greater than 23
Hy all,
I wish to use the date function to draw againt the lifetime of a motor.
This lifetime is given to me in Hours (it can go over 5000 hours)
I'm unable to find how to convert this lifetime value to something like %H:%M:%S because when R see 24H it says 1 day, i don't want that, i just want %H:%M:%S with a value of %H higher than 24...
for example:
i've got this value in hours:
2005 Jul 22
1
Generate a function
hi all,
I need to generate a function inside a loop:
tmp is an array
for (i in 1:10)
{
func<- func * function(beta1) dweibull(tmp[i],beta1,eta)
}
because then i need to integrate this function on beta.
I could have written this :
func<-function(beta1) prod(dweibull(tmp,beta1,eta)) (with eta and beta1 set)
but it is unplottable and no integrable... i could make it a bit different but
2005 Nov 30
1
about sorting table
hi all,
I load a table with headers that enable me to acces it by the column names:
tab<-read.table("blob/data.dat",h=T)
attach(tab)
everythings are OK, but i try to sort this table against one of his column like this:
tab<-tab[order(tab$IndexUI),];
It is still ok, the table is sorted, if i type "tab" i see a sorted table.
but, when i call the column by their names,
2005 Dec 08
1
truncate/overwrite a data frame
hi all,
I've got a data frame, this data frame have 76 columns and 22600 rows.
The data inside can be redundant because the data can be captured simultaneously and overlap each other.
My aim is to supress these overlaps
I've test some solutions to do that but they all give a big cpu load and eat all of the memory then swap a lot, then killall R because it don't end.
actually
2005 Nov 24
1
font size in legend
Hy all
I use barplot to draw frequencies by dates.
On the x axis it shows only 1 date for 2 bars, i've understand why, because R cant put so much date on the same axis, it will get out of the graph.
that's why i tought about reducing the size of the font used to stamp the x axis.
anyone knows the right way? i've tryed par(cin) and barplot(cin=3) but it says i cannot do it at this
2005 Aug 02
1
plotting 3 functions on same graph
hi all,
I wish to draw on the same graphic device 3 functions.
But i don't want them to be on different graph, i want to compare them on the same
I don't need mfrow or mfcol, I need something else...
1 graph on 1 device inside this graph 3 ploted function.
I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why?
why not
2005 Aug 02
1
multiple scale
Hi all
i need to put on one graph 2 functions who's x axis is the same and y not.
I mean on horizontal the time, and on vertical left: pressure, on vertical right: rpm of a motor, is R able to do that?
i've found this that i could adapt maybe (i don't need time series really?) :/ :
(http://tolstoy.newcastle.edu.au/R/help/04/03/1456.html)
##
## Description: A simple function which
2005 Aug 02
1
(no subject)
hi all,
I wish to draw on the same graphic device 3 functions.
But i don't want them to be on different graph, i want to compare them on the same
I don't need mfrow or mfcol, I need something else...
1 graph on 1 device inside this graph 3 ploted function.
I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why?
why not
2005 Oct 13
1
drawing against a date
hy all
I wish to draw a graph against a date,
I have a set of date like this DD/MM/YYYY, corresponding to it a set of integer , i wish to draw on x side the dates (the space between the dates have to be constant, not based on the time between 2 dates but on the number of dates) and on y side the integers.
Do i have to make a tricky function under R ?
I've search the help for graphical
2005 Jul 19
1
integrate fails with errors
Hi all,
i'm new to R,
I need to modelize in R a statistic algorithm,
This algo use Weibull, normal law, linear regression, normalisation, root mean square, to find eta and beta fitting the weibull model (to analyse few results) and further when we will get more information apply bayes model .
the problem is when When i try to integrate it fails with errors.
by the way i like to integrate
2006 May 16
1
variable row names
Hy all,
I wish to use a variable as rownames for a set of datas.
By example :
> nom<-"toto"
> prenom<-"tutu"
> res<-c(1,2)
> res<-t(res)
> res
[,1] [,2]
[1,] 1 2
> colnames(res)<-c(nom,prenom)
> res
toto tutu
[1,] 1 2
> nom
[1] "toto"
>
I wish to call the rowname by the
2007 Jan 04
3
problem with plot() and POSIXt dates
Hy all,
I'm plotting graphs using plot() function, they are on X axes POSIX dates:
"POSIXt" "oldClass" "POSIXct" "POSIXlt"
I can't figure out why sometimes it prints the month and days and sometimes it prints the unix timestamp.
It appens usually when the xlim is short like only some days.
xlim is settled as a POSIXt like this
"2006-12-30
2006 Jul 13
3
colors on graph
Hy all,
I need to draw something in 2 dimension that has 3 dimension, the choice
has been made to use colors to display the third dimension into the
graph.
Has someone done something like that, i can't figure out how to
parametize the colors.
Thks for all ideas,
COMTE Guillaume
[[alternative HTML version deleted]]
2006 May 17
0
variable colnames
Hy all,
I apologize i've used rownames instead of colnames in my first exemple. (that's why i changed the mail object) I was on mars when i wrote my question...
Every answer where correct ... but, because i've made a wrong question, people wern't able to understand...
So finally i'm speaking about colnames :
Let's be more precise:
I've got a query that gives me for
2006 Apr 18
5
3D pie
Hi all,
Is there a way to draw 3D pie with R (like excel does)?
I know how to do it in 2D, just by using pie(something)...
I know it isn't the best way to represent data, but people are sometimes
more interested by the look and feel than by the accuracy of the
results...
If there is no way, have you another suggestion ? (i already use
dotchart instead of pie)
Thks to all of