similar to: append

Dear R users: I've a list containing parameters (A , B & C), and I want create a data frame using data in these list. > coffee [[1]] A B C 1 1 0.5 7.78 2 1 1.0 6.06 3 1 2.0 3.67 4 1 4.0 1.35 5 1 6.0 0.49 6 1 8.0 0.18 [[2]] A B C 1 2 5 7.78 2 2 10 6.06 3 2 20 3.67

Hi, all: a<-data.frame(x=c(1:10),y=c(10:1)) edit(a) how to quit the edit in Linux, and then do other computing? As In Windows, just close the edit window, but how to do in Linux? Thanks in advanced !!

Hi Function sequence() repeatedly concatenates its output, and this is slow. It is possible to improve on the performance of sequence by defining myseq <- function(x){unlist(sapply(x,function(i){1:i}))} The following session compares the performance of myseq(), and sequence(), at least on my G5: > identical(sequence(1:50),myseq(1:50)) [1] TRUE > system.time(ignore <-

Hi Function sequence() repeatedly concatenates its output, and this is slow. It is possible to improve on the performance of sequence by defining myseq <- function(x){unlist(sapply(x,function(i){1:i}))} The following session compares the performance of myseq(), and sequence(), at least on my G5: > identical(sequence(1:50),myseq(1:50)) [1] TRUE > system.time(ignore <-

Hi, I have encountered this problem quite a few times and thought I would ask. Let's say that I have two endpoints, a and b, which are integers. If a <= b, I would like to get a:b, but if a > b, then numeric(0), for example: myseq(3,5) => 3:5 myseq(3,3) => 3 myseq(3,2) => numeric(0) The operator : just gives decreasing sequences in the latter case, and I could not coax seq

I am trying to build Miredo 1.1.5 (http://www.remlab.net/miredo/devel.shtml.en) I have followed the rpmbuild instructions from: http://www.owlriver.com/tips/non-root/, and have the miredo source in ~/build/miredo-1.1.5. I run ./configure (as the INSTALL text file tells me to do) and get the error: checking for Judy.h usablity... no checking for Judy.h presence... no checking for Judy.h...

Hi, I am very new to R and wanted to know if there is a package that, given very long nucleotide sequences, searches and identifies short (7-10nt) motifs.. I would like to look for enrichment of certain motifs in genomic sequences. I tried using MEME (not an R package, I know), but the online version only allows sequences up to MAX 60000 nucleotides, and that's too short for my needs..

Since upgrading my server from CentOS 4.5 to 4.6 I've been getting the following error from amanda backups: mutilate /home lev 1 FAILED [compress got signal 11, /bin/tar got signal 13] I was away from the house for most of the end of December and had a couple of other issues that came up that could have been related but apparently weren't (why is it that several things all go wrong

Hi. Suppose I have a vector that I partition into disjoint, contiguous subvectors. For example, let v = c(1,4,2,6,7,5), partition it into three subvectors, v1 = v[1:3], v2 = v[4], v3 = v[5:6]. I want to find the maximum element of each subvector. In this example, max(v1) is 4, max(v2) is 6, max(v3) is 7. If I knew that the successive subvector maxima would never decrease, as in the example,

Last Friday, I noticed that it is difficult to work with regression models in which there are factors. It is easier to do the old fashioned thing of coding up "dummy" variables with 0-1 values. The predict function's newdata argument is not suited to insertion of hypothetical values for the factor, whereas it has no trouble with numeric variables. For example, if one uses a

Hi there, I am looking for R-packages that can help me visualize properties on nucleotide sequences. I want to display sequences in the 1-100K base range as lines and plot features above and below those lines. Any ideas would be welcome. Thanks, Bernd [[alternative HTML version deleted]]

Dear All, I am using the plotrix library to plot some matrices. I have a problem: some of my data are outliers, hence using a linear color scale does not work very well (you would see too many cells having a similar, indistinguishable color). See the code snipped at the end of the email. Plotting the logarithm of the data gets the job done, but my problem is that I would like to write in every

Hi there, I'm dealing with a pretty big dataset (~22,000 entries) with numerous entries for every day over a period of several years. I have a column "judy" (for Julian Day) with 0 beginning on Jan. 1st of every new year (I want to compare tendencies between years). However, in order to control for a leap year (2004), I simply need to subtract 1 from every judy value for the year

I want to create a user "samba" that has admin privileges over the directory where Win95 apps will be installed, but does not have root privileges. Are their any problems with doing so? Thanks, Carey =====================================================================e <> Carey F. Cox, PhD | PHONE: (409) 880-8770 <> <> Assistant

Hello. I know that it is recommended to run smbd as a standalone daemon and to avoid inetd. Can you please tell me why inetd is discouraged and what problems it imposes? Also, I have one user who is having problems accessing her personal files on a MacOSX 10.3.2 via smb. Any ideas what may be causing it? Judy Lin NACS-DCS

Forgive my novice question, but I am a new student of Linux working on presenting the ext3 journaling filesystem to my class. I seek any advice on how to visibly demonstrate (including a purposeful crash of a Linux box) the benefits of ext3 over ext2. I am not worthy to lick the bootstraps of this group, but I beg for any help! The problem I am having extends to even locating the .journal file

If there a way to may samba "handle" files like ftp does during ascii transfers. Changing the ^m to unix end of line markers

-----Original Message----- From: Marcus Johnson [mailto:marjohns@uu.net] Sent: Friday, March 09, 2001 10:18 PM To: 'samba-patches@samba.org' Subject: quick question Hello, Is there an updated Samba registry key that alows Windows 2000 machines map to UNIX servers the one I currently have, which is attached does not work with 2000 but works with NT. Marcus

Hi, all; I got an unusual error while using mclust library 2.1-7 on R 2.0.1. When I tried to run Mclust(rnorm(100)), I got segmentation fault error. Does anyone know what causes this problem? I came across the same problem even when I tried to run the example shown in Mclust help using iris data. Thanks in advance, Tae-Hoon Chung -------------------------------------------------- Tae-Hoon Chung

Basically, the `Detail' section of ?tune says it all: Details: As performance measure, the classification error is used for classification, and the mean squared error for regression. ... Andy > From: Tae-Hoon Chung > > Hi, all; > > Basically, the subject contains the all information I need to know. > In e1071 library, there are functions to tune parameters.