similar to: Point pattern to grid

Hi all, I am new in R tool. I would like to plot two dataset in in fig. Here is what I did for both a and b data sets jpeg(file="a.jpeg") dat<-read.table('a', header=F, sep=',') dim(dat) y<-dat[,1] y<-y[!is.na(y)] plot(y);lines(lowess(y, f=0.05), col = ("red"), lwd=5) dev.off Two questions: 1. How I can save this lowess smooth data? 2. Once I

I had to move my RedHat 5 box acting as a PDC to a new IP address. It is running samba 3.5.10. After the move, none of my windows or linux samba clients worked anymore. I tried rejoining some to the domain, but would get error Unable to find a suitable server Join to domain 'MRIRESEARCH' is not valid The old PDC IP address is 132.183.202.95 and nothing is at that IP anymore (for 4

Hi, I have installed Debian Buster with encrypted LVM so apon installation my root partition is encrypted. So far so good but as soon as I encrypt the boot partition, after reboot the OS won't start. If I start the drive directly with qemu, it works but it looks like Libvirt is somehow not able to deel with it. What am I missing? -- John Doe

Right now we do a lot of hard to hard disk backup by using rsync to weekly "mirror" the source filesystem to a backup filesystem. This works fairly well for most sources. However, one issue with rsync is that simple things like changing the file name or directory name cause the whole file or directory structure to get recopied over a previous sync. Also, like for mail spools, large

I've installed new fifa and written in the code of the terminal had opened up to play EA Sports intro then comb a new error message in there Standt: "In the program were difficult manager11.exe gent fault and it must be-beeendet We apologize for this unnanehmlichkeiten. The cause may be a problem in the program or may fail to run in wine sein.sie www.appdb.winehq.org tips under the

I have a disk where serveral files have a file size that is much bigger then the space they actually use. THe file size is bogus. In the example below, the size is reported as 4.2MB but the file is really supposed to be on 116K which is true accoring to du and the block list from debugfs. However, doing a 'cat |wc' file actually gives me 4.2MB bytes. Where are those extra bytes coming

I draw dotplot using the following code: sd.dotplot<-dotplot(data.47.nmr$om_sd ~ as.factor(data.47.nmr$position) |as.factor(data.47.nmr$pr), data = data.47.nmr,layout=c(1,1), xlab="Position", xlim=range(data.47.nmr$position),ylab="Sd", main="Changes of omega angle in different positions", scales = list(x = list(rot = 45))) However I get same xlim for each

"Or use <<- assignment I think. (I usually return, but return can only return one object and I think you want two or more" You can return any number of objects by putting them in a list and returning the list. Use of "<<-" is rarely a good idea in R. -- Bert On Fri, Aug 9, 2024 at 1:53?AM CALUM POLWART <polc1410 at gmail.com> wrote: > > OK. The fact

Dear R users, Probably, this is quite a simpe question, but I do not find the proper way to obtain want I need. To explain the problem, I constructed a simple example. Suppose I have the following function: try1<-function(x){ y<-x[1:2] z<-x[3:4] y[1]*(z[1]+z[2])+y[2]*(z[1]+z[2]) } This function will be part of a for loop. This is what I like to obtain for every k: if k=2

Hello world, I am actually transferring a course in data management for students in biology, geography and agriculture from statistica to R - it works surprisingly well. If anyone is interested in my scratch/notepad (in German language), please see www.hydrology.uni-kiel.de/~schorsch/statistik/statistik_datenauswertung.pdf (pages 40-52) The dataset is:

Dear all, I have a character string object: > chara [1] "The name of first slot" and a list object: > class( try1) [1] "list" what I want to do is to use the chara as a slot's name of "try1". Of course I could do it like: > try1$"The name of first slot" <- matrix("", 3, 4) to create a slot of 3x4 matrix with the name

Thanks. Hmm. The loop is doing what it is supposed to do. > try1<-function(joint12=FALSE,marg1=FALSE,marg2=FALSE, +??????????????? cond12=FALSE,cond21=FALSE){ + # *************************************************** + # Testing if loop + # *************************************************** + if(joint12){ +?? {print ("joint12"); cat(joint12,"\n")} +?? {print

OK. The fact it's in a function is making things clearer. Are you trying to update the values of an object from within the function, and have them available outside the function. I don't speak functional programming articulately enough but basically v <- 1 funA <- function() { v <- v+1 } funA() cat (v) # 1 You either return the v from the function so funB <- function() {

Is something wrong in the initialisation part that we don't see? joint12 <- marg1 <-F marg1 <-T if (joint12) { print ("joint 12") cat (joint12) } if (marg1) { print("marg 1") cat(marg1) } Would probably be my diagnostic approach On Fri, 9 Aug 2024, 04:45 Steven Yen, <styen at ntu.edu.tw> wrote: > Can someone help me with the if loop below?

Hello, I recently began using R and the lme4 package to carry out linear mixed effects analyses. I am interested in the effects of variables 'prime','time', and 'mood' on 'reaction_time' while taking into account the random effect 'subjects.' I've read through documentation on lme4 and came up with the following formula for use with lmer:

Hi, I have started using symbolic links on an SMB share and find that symbolic links whose target no longer exists cannot be removed on the client side. Example, on the SMB client side in an SMB-mounted directory: 1. Create a file and a relative symlink to it: $ touch a $ ln -s a b $ ls -l total 0 -rw-rw-r--. 1 andi andi 0 Jan 6 14:42 a lrwxrwxrwx. 1 andi andi 1

On Nov 28, 2010, at 1:57 PM, Bill Wendling wrote: > On Nov 28, 2010, at 2:59 AM, John McCall wrote: > >> On Nov 28, 2010, at 2:20 AM, Bill Wendling wrote: >> >>> On Nov 27, 2010, at 4:57 PM, John McCall wrote: >>> >>>> On Nov 25, 2010, at 3:03 AM, Duncan Sands wrote: >>>>> I'm pointing out that if the invoke instruction

Hi, I was wondering if there is a direct approach for lining up 2-column matrices according to the values of the first column. An example and a brute-force approach is given below: x <- cbind(1:10, runif(10)) y <- cbind(5:14, runif(10)) z <- cbind((-4):5, runif(10)) xx <- seq( min(c(x[,1],y[,1],z[,1])), max(c(x[,1],y[,1],z[,1])), 1) w <- cbind(xx, matrix(rep(0, 3*length(xx)),

It appears there is still misunderstanding about my situation/setup. Sorry, I know this is strange. I have an LDAP server for my Linux infrastructure that is totally seperate from the corporate AD Windows domain. At one point my LDAP did have the samba schema installed with my its own SID's and smbpasswd's in it. My web app for users to change their Linux password would on the backend

Hi: Goal: use R to turn a matrix of 1's and 0's into a corresponding image (e.g. png) of black and white pixels. Why R: Yes, I can do this more efficiently and precisely with a perl module like Image::PBM. Been there, done that many times, etc. (Just humor me. I'm trying to do this with R for a number of reasons.) Problem: