similar to: Difficulties with for() {while(){}}

Hi, Please, change the brazilian mirror http://www.termix.ufv.br/CRAN/ to http://www.insecta.ufv.br/CRAN/ in R homepage. Thanks ROnaldo -- Se dois homens no mesmo trabalho concordam o tempo todo, um deles ?? demais. Se discordam sem parar, ent??o os dois s??o dispens??veis --Darryl F. Zanuck -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior

Hi, I have these vectors: > WEEK <- rep(c(1:52),2) > YEAR <- rep(c(2000,1999),c(52,52)) How to make a vector of Date with weeks in years? I try as.date from survival package, but it dont work with weeks, just only with days, months etcs. Thanks Ronaldo -- "Realmente minha cidade e muito facultativa" --Elivelton, ao rep?rter da Jovem Pan que falava das muitas

Hi, I have some data that have this behaviour: | |******* | * | * | * | * |---------------- What is the best and simpler way to fit this in R? Thanks Ronaldo -- Ela pilotava um Continenal 2001 com igni????o autom??tica Magiclic... -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior ] |>

Hi, I have this: lme(y~x1+x2,random=~1|x1/x2) How to make this random effect using lmer? I try this: lmer(y~x1+x2+(1|x1/x2) But it dont work. Any idea? Thanks Ronaldo -- System halted! -- |> // | \\ [***********************************] | ( ?? ?? ) [Ronaldo Reis J??nior ] |> V [UFV/DBA-Entomologia ] | / \ [36570-000 Vi??osa -

Hi, look this: > summary(fam??lia) Anacardiaceae Annonaceae Bombacaceae Cecropiaceae 2 4 1 3 Chrysobalanaceae Clusiaceae Euphorbiacaea Fabacea 1 1 4 3 Fabaceae Flacourtiaceae Humiriaceae indeterminada

Hi, I try to run the example of Crawley's Book on the page 661, but it fail, look > repmeasures <- read.table("../Packages/Crawley/data/repmeasures.txt",header=T) > attach(repmeasures) > rep <- as.factor(rep) > library(nlme) > model <- lme(height~seed,random=~time|rep/seed) Erro em lme.formula(height ~ seed, random = ~time | rep/seed) : iteration limit

I have a data set with the following structure (with many more obs.): var1 expt day diameter 1 1 2 0.5 1 1 3 0.9 1 1 4 1.3 1 1 5 1.7 1 2 2 0.3 1 2 3 0.5 1 2 4 0.9 1 2 5 1.6 2 1 2 0.7 2 1 3 1.2 2 1 4 1.6 2 1 5 2.3 2 2 2 0.4 2 2 3 0.8 2 2 4 1.6 2 2 5 3.2 I can get separate regression analysis for each level of var1 and expt with the command: by(data3, data3$var1:data3$expt, function(x)

Its just a simple question I guess: I have a vector with missing information like x<-c(0,1,31,131,NA,133,NA,310,NA,112,3,1,2,93) How can I make a vector like this no missing in it. I used the x[x<0] commabd and tried some more, with no success. thx Korbinian

Hi, I make a upgrade to R 2.1.0 and in some analysis I give an error: anova(model,test="F") Analysis of Deviance Table Model: binomial, link: logit Response: landing/total Terms added sequentially (first to last) Df Deviance Resid. Df Resid. Dev F Pr(>F) NULL 16 105.079 trat 1 93.149 15 11.930 93.15 Warning message:

Hi, the question on subject is possible? example: m1 <- lmer(y~1+(1|subject)) m2 <- update(m1,.~.+x) I try but dont work, exist any other method for this? Thanks Ronaldo -- He won a Toyota now, eh? -- pal?ndromo -- |> // | \\ [***********************************] | ( ? ? ) [Prof. Ronaldo Reis J?nior ] |> V [UNIMONTES/Depto. Biologia

Dear list members, i am trying to get ldap + samba + kerberos working and have tried to make the proper configuration. Integrating samba + ldap was pretty easy, but getting kerberos to work seems a nightmare. Here it is what i tried (copy and pasted from my link client): harley at 802-1x:/etc/samba$ kdestroy harley at 802-1x:/etc/samba$ kinit harley at UFV.BR's Password: harley at

Hello, This is my first post, and my english is not very good, but I will try... I have a problem with boot the R. After that I install ubuntu 9.10 the R don't run. When I open the terminal and digit R, appear the message: */usr/lib/R/bin/exec/R: error while loading shared libraries: libgfortran.so.3: cannot open shared object file: No such file or directory* What's happening? Can

Hi, I try to put a legend in a xyplot graphic. xyplot(y~x|g,ylim=c(0,80),xlim=c(10,40),as.table=T,layout=c(2,3), ylab="N??mero de machos capturados",xlab=expression(paste("Temperatura (",degree,"C)")), key=list(corner=c(0,0),x=0, y=0, text=list(legenda),lines=list(col=cor, lwd = espessura, lty=linha),columns=7,between=0.5,betwen.columns=0.5,cex=0.8)) The problem

Is possible to integrate this diferential equation: dN/dt = Nr(1-(N/K)) in R using the integrate() function? Or any other diferential equation? If yes, how? If no, anybody know any software on linux that make this? Inte Ronaldo -- O problema de ter os dois p??s bem firmes no ch??o ?? que voc?? n??o vai conseguir tirar as cal??as. --An??nimo -- |> // | \\

Hi, I make an analysis and depending of the order of the variables, the significance change, look. m1 <- glm((infec/ntot)~idade+sexo+peso,family=binomial,weights=ntot) > anova(m1,test="F") Analysis of Deviance Table Model: binomial, link: logit Response: (infec/ntot) Terms added sequentially (first to last) Df Deviance Resid. Df Resid. Dev F Pr(>F)

Hi, anybody have the dataset used in Gamma Errors chapter of the Crawley's books (An Introduction to Data Analysis using S-Plus). specifically the functionalresponse and the Density datasets. Thanks Ronaldo -- For every problem there is one solution which is simple, neat, and wrong. -- H. L. Mencken -- |> // | \\ [***********************************] | ( ? ? ) [Ronaldo Reis

Hi, How can I, from a single "driver" file, source other files in such a way that I can access their functions with parameters defined in my "driver" file? I wish to do this to avoid creating a single, self-contained but clunky piece of code. I have searched and found functions such as file(), pipe(), open(), found manuals on creating my own packages, etc. but I become

Hi all, I try to test a linear slope using offset. I have: > m2 <- glm(Y~X*V) > summary(m2) Call: glm(formula = Y ~ X * V) Deviance Residuals: Min 1Q Median 3Q Max -2.01688 -0.56028 0.05224 0.53213 3.60216 Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 1.3673 0.8476 1.613 0.119788 X

Hi, I have a new (for me) situation. I have a function for one linear model: y = 9.7909-0.035*x I have the variance of system var = 13.01403 Is possible to create a random vector points of Y (simulating the real data) over this curve using the function and the variance? I need this to a discipline. I have this: | \ | \ -> y = 9.7909-0.035*x and var = 13.014 | \ | \ | \ | \

Hi, I try to make a vector in a for for loop, but it dont work. Look: > a <- 0;for(i in c(1:2)) { for(j in c(1:2)) { a <- i+j; print(a)}} [1] 2 [1] 3 [1] 3 [1] 4 I try to make this a vector, like this: [1] 2 3 3 4 > a <- 0;for(i in c(1:2)) { for(j in c(1:2)) { a[j] <- i+j}}; print(a) [1] 3 4 > a <- 0;for(i in c(1:2)) { for(j in c(1:2)) { a[i] <- i+j}}; print(a) [1]