similar to: dataframe without repetition

Hi, how can i write this simple sentence : "Hello world" with "Hello" only in bold ? I try > plot(1:5) > title(main=paste(expression(bold("Hello")),"world",sep=" ")) but the result is wrong. thanks, Bruno Si vous n'etes pas destinataires de ce message, merci d'avertir l'expediteur de l'erreur de distribution et de le

Dear R-users, i have two questions : 1- first of all, i wish to know the way to obtain a serie with a format like "00" : ( "01","02","03","04"....) or like postal code ("01100","02222"). for instance, i do : > format(strptime(as.character(c(1:4)),"%H"),"%H") but it sounds complicate and not really

Hi, i have two data.frame x and y like : > x <- data.frame( num = c(1:10), value = runif(10) ) > y <- data.frame( num = c(6:10), value = runif(5) ) and i want to obtain something like : num.x value.x num.y value.y 1 0.38423828 NA 0.2911089 2 0.17402507 NA 0.8455208 3 0.54443465 NA 0.8782199 4 0.04540406 NA 0.3202252 5 0.46052426

Hi Together, I have a problem with the plyr package - more precisely with the ddply function - and would be very grateful for any help. I hope the example here is precise enough for someone to identify the problem. Basically, in this step I want to identify observations that are identical in terms of certain identifiers (ID1, ID2, ID3) and just want to save those observations (in this step,

Hello, Is there a simple and fast function that returns a vector of the number of replications for each object of a vector ? For example : I have a vector of IDs : ids <- c( "ID1", "ID2", "ID2", "ID3", "ID3","ID3", "ID5") I want the function returns the following vector where each term is the number of replicates for the

Hi - I have a data frame with a large number of observations (62,000 rows, but only 2 columns - a character ID and a result list). Sample: > my.df <- data.frame(id=c("ID1", "ID2", "ID3"), result=1:3) > my.df id result 1 ID1 1 2 ID2 2 3 ID3 3 I have a list of ID vectors. This list will have anywhere from 100 to 1000 members, and

Hi all, I have a data.frame I received with data that look like this (comma separated strings in last row): ID Shop Items ID1 A1 item1, item2, item3 ID2 A2 item4, item5 ID3 A1 item1, item3, item4 But I would like to unbind the strings in col(2) items so that it will look like this: ID Shop Items ID1 A1 item1 ID1 A1 item2 ID1 A1 item3 ID2 A2 item4 ID2 A2 item5 ID3 A1 item1 ID3 A1 item3 ID3 A1

Hello, I have a list (mode and class are list) in R that is many elements long and of the form: >length(list) [1] 5778 >list[1:4] $ID1 [1] "num1" $ID2 [1] "num2" "num3" $ID3 [1] "num4" $ID4 [1] NA I'd like to convert the $ID2 value to be in one element rather than in two.?? It shows up as c(\"num2\", \"num3\") if I try to use

Hi Group, I have a data frame below. Within this data frame there are samples (columns) that are measured more than once. Samples are indicated by "idx". So "id1" is present in columns 1, 3, and 5. Not every id is repeated. I would like to create a new data frame so that the repeated ids are averaged. For example, in the new data frame, columns 1, 3, and 5 of the original

Hi Thanks much for the prompt response to my earlier enquiry on packages for regression analyses. Along the same topic(?), I have another question about which I could use some input. I am retreiving data from a MySQL database using RODBC. The table has many BLOB columns and each BLOB column has data in the format "id1 \t id2 \t measure \n id3 \t id4 \t measure...." (i.e. multiple rows

Thanks for pointing me out "aggregate", that works fine! There is one complication though: I have mixed types (numerical and character), So the matrix is of the form: A 1.0 200 ID1 A 3.0 800 ID1 A 2.0 200 ID1 B 0.5 20 ID2 B 0.9 50 ID2 C 5.0 70 ID1 One letter always has the same ID but one ID can be shared by many letters (like ID1) I just want to keep track of the ID, and get

Hello. I am playing with LLVM and trying to make Z80 (Zilog Z80) backend. The source code is attached. I have succesfully made some simple test. But now I have problem with ADD instruction. The source C code is: typedef struct { unsigned char id1; unsigned char id2; unsigned char id3; } testS; void simple() { testS test; test.id1 = 0x40; test.id2 = 0x80; test.id3 = 0xc0; } It

Hi all, I'm a beginner user of R. I am stuck at what I thought was a very obvious problem, but surprisingly, I havent found any solution on the forum or online till now. My problem is simple. I have a file which has entries like the following: #ID Value1 List_of_values ID1 0.342 0.01,1.2,0,0.323,0.67 ID2 0.010 0.987,0.056,1.3,1.5,0.4

Dear List, I have been trying to extract associations from a matrix whereby individual locations are within a certain distance threshold from one another. I have been able to extract those individuals where there is 'no interaction' (i.e. where these individuals are not within a specified distance threshold from another individual) and give these individuals a unique Group ID containing

Can someone show me some code to do normalization by the median of some control genes for the example below? Many Many Thanks in advance This strategy selects a subset of genes (called ?control genes?) and makes the median of their data distribution similar across arrays. ??? ??? id1??? id2??? id3 control1??? 0.8??? 0.7??? 0.6 control2??? 0.6??? 0.2??? 0.4 probe1??? ??? 0.3??? 0.2??? 0.5

I'm new to R (previously used SAS primarily) and I have a genetics data frame consisting of genotypes for each of 300+ subjects (ID1, ID2, ID3, ...) at 3000+ genetic locations (SNP1, SNP2, SNP3...). A small subset of the data is shown below: SNP_ID SNP1 SNP2 SNP3 SNP4 Maj_Allele C G C A Min_Allele T A T G ID1 CC GG CT AA ID2 CC GG CC AA ID3 CC GG nc AA

Hi Peter, I think the problem is that you did not explicitly define stack alignment in Z80TargetMachine.cpp DataLayout("e-p:16:8:8-i8:8:8-i16:8:8-i32:8:8-n8") Try to add S16 to the string if your stack is 2-byte aligned. Refer to http://llvm.org/docs/LangRef.html#datalayout . If it does not work, try to specify the layout in the input module using target layout directive. David On

I have two data sets: File1.txt: Name id1 id2 id3 ... N1 0 1 0 ... N2 0 1 1 ... N3 1 1 -1 ... ... File2.txt: Group id1 id2 id3 ... G1 1.22 1.34 2.44 ... G2 2.33 2.56 2.56 ... G3 1.56 1.99 1.46 ... ... I like to do: x1<-c(0,1,0,...) y1<-c(1.22,1.34, 2.44, ...)

Hello. I have played with DataLayout and found a solution with is uknown to me. I added S16 and also s0:16:16, but it had not worked. Then I found that in Z80FrameLowering.h I am calling TargetFrameLowering with stack aligment set to 8. So I changed it to 2 bytes. But this also didn't help. Then I changed llc to show TargetDataLayout and found that a option is set to a0:0:64. So I changed

Dear r experts, Sorry for this basic question, but I can't seem to find a solution? I have this data frame: df <- data.frame(id = c("id1", "id1", "id1", "id2", "id2", "id2"), A = c(11905, 11907, 11907, 11829, 11829, 11829), v1 = c(NA, 3, NA,1,2,NA), v2 = c(NA,2,NA, 2, NA,NA), v3 = c(NA,1,NA,1,NA,NA), v4 = c("N",