similar to: polynomials transformation

Dear All, How can I sort a data frame (using one of the column)? Thanks for your support. Regards. Abd. Rahman Kassim (PhD) Head Forest Ecology Branch Forest Management & Ecology Program Forestry and Conservation Division Forest Research Institute Malaysia Kepong 52109 Selangor, Malaysia ***************************************** Checked by TrendMicro Interscan Messaging Security. For any

Dear All, I'm trying to attach a legend outside the plot (Inside plot OK), but failed. Any help is very much appreciated. Thanks. Abd. Rahman Kassim, PhD Forest Management & Ecology Program Forestry & Conservation Division Forest Research Institute Malaysia Kepong 52109 Selangor MALAYSIA ***************************************** Checked by TrendMicro Interscan Messaging Security.

Dear All, I'm trying to save a dataframe using write.table command. It works, but when I retrieved, there's an error message as shown below: > write.table(soil.dat,file="C:/soil.rdata") > load("C:/soil.rdata") Error: bad restore file magic number (file may be corrupted)-- no data loaded I can figure out the error message. Any assistance to solve the

Dear All, I've tried to add axis limit ( e.g. ylim=c(0,50)) to the log-log plot, but it turn out to be error (see below). Any solution is much appreciated. > plot(maxsd$tph,maxsd$qdbh,log="xy",xlab="Stand density(trees per ha)",ylab="Quadratic mean dbh (cm)",ylim=c(0,50)) Error in plot.window(xlim, ylim, log, asp, ...) : Infinite axis extents

Dear All, I have a question on overlaying a filled.contour (e.g. on soil properties data) and contour (by elevation) in one graph. Both have the same z matrix dimension. I'm able to overlay both graph, but the plots dimension did not overlap well on the same plots. How can I have both filled.contour and contour on the same graph? The commands that I have written are as follows:

Dear R-User, Appreciate any helps. It looks simple, but I don't have a clue. Given that I have a dataframe of tree population with three variables: sp=species , d0=initial_size grow=growth increment from initial size per year How can I calculate the future growth increment of each tree for the next 3 years. The following Rscript was written, #---------- a0 <-

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Dear list, I understand that to raise matrix A to power (-1/2) we should use something like this: eigen(A)$vectors%*%diag(1/sqrt(eigen(A)$values))%*%t(eigen(A)$vectors) [from previous discussions: http://r.789695.n4.nabble.com/matrix-power-td900335.html] But this will only do it for negative sqrt of the matrix not for other fraction powers like (-3/2). Seeing that these things be can done

My company is using Trend Micro InterScan Messaging Security Suite 7.0 for linux. This setup uses Postfix as a mail gateway for MS Exchange. The problem I'm having is ever so often Postfix 2.2.11 will lose the Transport mapping lookup tables setting. When this happens, mail into our domain will stop being relayed to our Exchange server. FYI: please remember, I'm ok with understanding how

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I've got a context in my dialplan like so but pressing 0 doesn't seem to be working. Instead of dropping out to the "o" extension, it's just returning to the start of the direcotry app. Same with star. Anyone see where I've gone awry? [attendant] ; <snip> exten => *,1,NoOp(Attendant: Directory) exten => *,n,Directory(default,attendant,eb)

Hi, I want to remove all punctuation characters in a string. I was trying it use a regular expressions but it doesn't work. Here is a sample os what i want: str <- 'ABD - remove de punct, and dot characters.' str <- gsub('[:punct:]','',str) str "'ABD remove de punct and dot characters" is there any function that do this kind of thing? Thanks to

I just need to confirm something with pattern matching folks. I have a factor with the following levels in a very large data set: > levels(all$Classical.Statistic) [1] "" "AB;ABD" "CollapsedSteps" "CR_P" "CR_Prop;CR_P;AB" [6] "NMK"

I am sorry, I'd like to split my column ("names") such that all the beginning of a string ("X..") is gone and only the rest of the text is left. x<-data.frame(names=c("X..aba","X..abb","X..abc","X..abd")) x$names<-as.character(x$names) (x) str(x) Can't figure out how to apply strsplit in this situation - without using a

Hello, I changed the log path in shorewall.conf, LOGFILE=/var/log/messages to LOGFILE=/var/log/shorewall, and then I touched the shorewall file in /var/log, permission root:root 600, after shorewall restart, no logging messages appear in /var/log/shorewall. so how can I fix this problem ? Thanks !! _______________________________________ YM - 離線訊息

I am a novice user of R and am stumbling on how to order a dataset produced during my session. I have a 1863 row X 14 column dataset that I want to put out to a file. I want the output sorted by the first column and then by the second column both in ascending order. The first column is character and the second is numeric (I hope). I used an "as.numeric" function to assign that

Hi I am searching for a way to do something like "ABC" -> c("A","B","C"). How can this be accomplished? I tried cut() and split(), but they do something else, it seems. The purpose for doing this is to find the number of common (and uncommon) characters, i.e. ultimately I want something like this: > foo("ABD","ADE") c(2,1) # 2

Was just playing around with trying to sort out validation of zip/postcodes depending on what country the user lived in, and was wondering if anyone has done this in a nice way? Seems to me that it would be a relatively simple addition to Globalize to add a regex for zip code validation to the things already in there? Or am I missing a trick? Thanks geoff -------------- next part --------------