similar to: Orientation of tickmarks labels in boxplot/plot

Hi, if I use the xyplot (or levelplot) function (lattice library) with the option axs="i", I have the problem that the tickmarks lie a bit outside the "plot-box". Consider for example: library(lattice) x<-seq(0,1,by=0.01) y<-seq(0,1,by=0.01) xyplot(y~x,type="l",xlim=c(0,1),ylim=c(0,1),scales=list

Hi All, I am attempting to work with some data from loggers. I have read in a .csv exported from MS Access that already has my dates and times (in 24 clock format), (with StringsAsFactors=FALSE). > head(tdata) LogData date time 1 77.16 2008/04/24 02:00 2 61.78 2008/04/24 04:00 3 75.44 2008/04/24 06:00 4 89.43 2008/04/24

Dear Group, I have the following data matrix which is a timeseries. > dput(tData) structure(list(A = c(0.2, 0.13, 0.05, 0.1, 0.02, 0.18, 0.09, 0.06, 0.13), B = c(0.15, 0.06, 0.09, 0.02, 0.03, 0.12, 0.01, 0.15, 0.06), C = c(-0.1, 0, -0.07, -0.06, -0.05, -0.05, -0.06, -0.08, -0.07), D = c(-0.15, -0.05, -0.1, -0.03, -0.13, -0.04, -0.1, -0.04, -0.15), E = c(-0.17, -0.16, -0.08, -0.07, -0.09,

I would like to incorporate multiple summary plots from the rms package into a single device and to control the titles, and also to open a new device when I reach a specified number of plots. Currently I am only getting a single "plot(summary(" graph in the upper left- hand corner of each successive device. However, in the rms documention I see instances of a loop being used with

Hello R users, I have been trying to output all my results (text, plots, etc) into the same postscript file as one document, but have been unable to...Can anyone help me improve my code below so that I can accomplish this? Currently I have to output them separately then piece them back together into one document.. Thanks in Advance for any help! options (scipen=999, digits=7)

Hi all, I have been previously been using scatterplot3d package to create some graphs but unfortunately it does not allow me to rotate the plot on all three axis. The cloud() function in the lattice package does allow me to do so. When I was using scatterplot3d I was using a script (Shown Below) to calculate the mean, quartiles and range limits for all three axis and I was representing that on the

Dear, When i multiply the y of a regression by 10, I would expect that the coefficient would be multiply by 10 and the z value to stay constant. Here some reproducible code to support the case. *Ex 1* library(mvtnorm) library(VGAM) set.seed(1) x=rmvnorm(1000,sigma=matrix(c(1,0.75,0.75,1),2,2))

I am attempting to add a calculated column to a data frame. Basically, adding a column called "newcol2" which are the stock closing prices from 1 day to the next. The one little hang up is the name of the column. There seems to be an additional data column name included in the attributes (dimnames?). So when i run HEAD(DATAFRAMENAME) i get the column name = "Open". but

I don't normally have to go anywhere near this stuff , but it seems to me that this should be a straight-forward process in R. For the purposes of this enquiry I thought I would use something I can work out on my own. So I have my matrix and the right hand results from that matrix tdata <- matrix(c(0,1,0,-1,-1,2,0,0,-5,-6,0,0,3,-5,-6,1,-1,-1,0,0),byrow = T,ncol = 5) sumtd <-

Dear all, ?The code below is used to generate interval censored data but unfortunately there is an error with the ifelse which i am not able to rectify. ?Can somebody help correct it for me. Thank you t<-rexp(20,0.2)? v<-c(0,m,999)? y<-function(t,v){ ? z<-numeric(length(t (( ? ? s<-numeric(length(t (( ? ? ? for(i in 1:length(t)){ ? ? ? ? for(j in 1:length(v-1))? ? ? ? ? { ifelse

A user sent me an example where coxph fails, and the root of the failure is a case where names(mf) is not equal to the term.labels attribute of the formula -- the latter has an extraneous newline. Here is an example that does not use the survival library. # first create a data set with many long names n <- 30? # number of rows for the dummy data set vname <- vector("character",

Hello R users, I am new to R and am wondering if anyone can help me out with the following issue: I wrote a function to build ts models using different inputs, but when R displays the call for a model, I cannot tell which variables it is using because it shows the arguments instead of the real variables passed to the function. (e.g Call: lm(formula = dyn(dep ~ lag(dep, -1) + indep)) --->

Hola a todos Estoy intentando hacer un análisis rápido de una serie temporal de datos diarios pero me encuentro con algunos problemas. Me gustaría en primera instancia hacer una regresión lineal pero no encuentro la forma. Tras leer los datos diarios creo un objeto de la clase zoo y sobre éste no puedo utilizar lm(). He leído algo sobre dynlm pero no encuentro la forma. Se agradece

Dear R-users first, thanks to Paul Murrell for fixing my problem "What line is labeled in persp()". It works great now (in the development version). One more question (I don't know if it's related to the "old" problem): the annotation on the z-axis overwrites the numbers at the tickmarks and sometimes, if numbers are pretty long, the numbers themselfe overlap the

Problem: How can I format tickmark labels of log scaled axes of lattice graphics in the usual `xxx'-Format (and not in the scientific format). Example: (according to the help-page of xyplot): In the first plot I get the xxx-Format, in the second plot I get the scientific format (10^xxx): data(sunspot) plot( 1:37, sunspot, log='y',type='l') xyplot( sunspot ~ 1:37,

I have tData as below. I need to set the names with the headers from the first row in sHeaders Sorry .. forgot how to set the names from row in another data frame .. pls advise. names(tData) = sHeaders[1,] does not work correctly Also, why doesn't drop.levels(sHeaders) not work? dput(tData) structure(list(V1 = structure(c(3L, 1L, 1L, 2L), .Label = c("P H Ravi Kumar", "Rahul

Hi, All, This is my program ts1.sim <- arima.sim(list(order = c(1,1,0), ar = c(0.7)), n = 200) ts2.sim <- arima.sim(list(order = c(1,1,0), ar = c(0.5)), n = 200) tdata<-ts(c(ts1.sim[-1],ts2.sim[-1])) tre<-c(rep(0,200),rep(1,200)) gender<-rbinom(400,1,.5) x<-matrix(0,2,400) x[1,]<-tre x[2,]<-gender fit <- arima(tdata, c(1, 1, 0), method = "CSS",xreg=t(x))

On Wed, Aug 9, 2023 at 3:20 PM Dan Cropp <dcropp at amtelco.com> wrote: > I have a customer who just encountered a crash while running Asterisk > 18.17.1 version. > > > > I’m trying to adapt to the changes so not sure where best to look or how > to possibly report this. > > > > I started by going through >

Consider the following simple data set and a call to ave: > tdata <- data.frame(f1=c(1,1,1,1,2,2,2,2), f2=c(1,2,1,2,1,1,1,1), y=1:8) > with(tdata, table(f1, f2)) f2 f1 1 2 1 2 2 2 4 0 > with(tdata, ave(y, f1, f2, FUN=max)) [1] 3 4 3 4 8 8 8 8 Warning message: In FUN(X[[i]], ...) : no non-missing arguments to max; returning -Inf There are no missing values in the

Dear all, After a thorough research, I still find myself unable to find a function that does linear regression of 2 vectors of data using the "total least squares", also called "orthogonal regression" (see : http://en.wikipedia.org/wiki/Total_least_squares) instead of the "ordinary least squares" method. Indeed, the "lm" function has a