Displaying 20 results from an estimated 5000 matches similar to: "Change console language ?"
2007 Feb 15
3
Working with temporal data
Hi,
I have several files with data in this format:
20070102
20070102
20070106
20070201
...
The data is sorted and each line represents a date (YYYYMMDD). I would
like to analyze this data using R. For instance, I would like to have
a histogram by year, month or day.
I've already made a simple Perl script that aggregates this data but I
believe that R can be much more powerful and easy on
2007 Jun 20
2
Averaging dates?
Hi,
What's the best way to average dates?
I though mean.POISXct would work fine but...
> a
[1] "2007-04-02 19:22:00 WEST"
> b
[1] "2007-03-17 16:23:00 WET"
> class(a)
[1] "POSIXt" "POSIXct"
> class(b)
[1] "POSIXt" "POSIXct"
> mean(a,b)
[1] "2007-04-02 19:22:00 WEST"
> mean(b,a)
[1] "2007-03-17
2007 Feb 23
2
Google Custom Search Engine for R
Hi,
Since "R" is a (very) generic name, I've been having some trouble
searching the web for this topic. Due to this, I've just created a
Google Custom Search Engine that includes several of the most relevant
sites that have information on R.
See it in action at:
http://google.com/coop/cse?cx=018133866098353049407%3Aozv9awtetwy
This is really a preliminary test. Feel free to
2007 Feb 16
1
Working with temporal data [Solved]
Just for the record, here are my steps for producing a date based histogram.
Data is stored in a file where each line only has a date - 2007/02/16
>d<-readLines("filename.dat")
>d<-as.Date(d, format="%Y/%m/%d")
>pdf(yearly.pdf)
>hist(d, "years")
>dev.off()
Instead of "years" you can also use "days", "weeks",
2007 Mar 02
2
Error in length of vector ?
Hi,
I'm having a weird result with the length() function:
>a
[... omited ...]
[9994] NA "2003-12-03 16:37:00" "2002-06-26 18:43:00"
[9997] "2005-07-04 04:00:00" "2007-02-16 22:09:00" "2007-02-24 15:49:00"
[10000] NA
> length(LastModified)
[1] 9
> length(c(LastModified))
[1] 9
I was expecting to get
2007 Mar 07
2
No years() function?
Hi,
I'm trying to aggregate date values using the aggregate function. For example:
aggregate(data,by=list(weekdays(LM),months(LM)),FUN=length)
I would also like to aggregate by year but there seems to be no
years() function.
Should there be one? Is there any alternative choice?
Also, a hours() function would be great. Any tip on this?
Thanks in advance!
S?rgio Nunes
2008 Jun 17
2
Measuring dispersion
Hi,
I'm looking for a function to measure the dispersion of a set of
values ranging from 0 to 1.
This function should be 0 if all the values are evenly spaced within
the interval and it should be > 0 if values are clustered.
The more clustered the values are, the higher should the function be.
An example:
[0; 0.2; 0.4; 0.6; 0.8; 1] - function should be ~ 0
[0; 0.1; 0.1; 0.15; 1] -
2005 Dec 13
4
Ploting graphics using X tints from a color
Hi,
I'm trying to draw a 2D plot using multiple tints of red. The
(simplified) setup is the following: || year | x | y ||
My idea is that each year is plotted with a different tint of red.
Older year (lightest) -> Later year (darkest). I've managed to plot
this with different scales of grays simply by doing:
palette(gray(length(years):0/length(years)))
before the plot and for each
2005 Dec 13
1
Manipulating matrices
Hi,
I'm pretty new to R and I've been having some problems filtering data
in matrices.
I have the following initial dataset:
|| year | name | varA ||
I have multiple values for "varA" for the same "year" and the same "name".
Having this as the input I would like to obtain the following:
|| year | name | {varA mean} ||
Where I only have one line for each
2009 Jun 01
1
Bug in hist() when working with Dates ?
Hi,
It seems that hist() has a buggy behavior when breaking over "days".
The bug can be reproduced in a few steps:
> d=data.frame(date=c("2009-01-01", "2009-01-02", "2009-01-02"))
> d$date=as.Date(d$date)
> d$date
[1] "2009-01-01" "2009-01-02" "2009-01-02"
> h=hist(d$date, "days")
> h$count
[1] 3
2020 Nov 11
2
Samba 4.11 with SSL authority CA role
I have OpenSSL forgenrate the CA root file in my server and work fine. My
question is, ?howto i say to Samba (configuration) for work with CA
certificates? . I dont find information about this.
Thanks.
Saludos.
---
Miguel
El mar., 10 nov. 2020 a las 15:22, S?rgio Basto (<sergio at serjux.com>)
escribi?:
> On Tue, 2020-11-10 at 14:48 -0300, Miguel Angel Coa M. via samba wrote:
>
2019 Dec 05
5
security = ads, backend = ad parameter not working in samba 4.10.10
On Thu, 2019-12-05 at 17:15 +0000, Rowland penny via samba wrote:
> On 05/12/2019 17:00, S?rgio Basto wrote:
> > On Thu, 2019-12-05 at 10:15 +0000, Rowland penny via samba wrote:
> > > On 05/12/2019 06:16, S?rgio Basto wrote:
> > > > Sorry , I spoke too soon getent passwd "a new user to this
> > > > server"
> > > > doesn't work .
2019 Dec 05
2
security = ads parameter not working in samba 4.10.10
On Thu, 2019-12-05 at 04:57 +0000, S?rgio Basto via samba wrote:
> On Fri, 2019-11-29 at 18:33 +0000, Rowland penny via samba wrote:
> > On 29/11/2019 18:17, S?rgio Basto via samba wrote:
> > > On Fri, 2019-11-29 at 17:19 +0000, Rowland penny via samba wrote:
> > > > Lets start by removing this: krb5-server-1.15.1-
> > > > 37.el7_7.2.x86_64
> > >
2013 Feb 28
1
[SOLVED] replace Windows 2003 dc]
S?rgio Henrique <sermac at gmail.com> quatschte am Mon, Feb 25, 2013 at 04:26:30PM +0000:
> Solved.
>
> I have sucessfully migrated a windows 2008R2 domain to samba4 and then
> create a new samba domain as a replica.
>
> A lot of steps i had to introduce.
Hi S?rgio,
> 1- Working on DNS
> add samba dc to forest and domain dns _ldap values
> change DNS SOA to
2019 Dec 05
2
security = ads, backend = ad parameter not working in samba 4.10.10
On Thu, 2019-12-05 at 10:15 +0000, Rowland penny via samba wrote:
> On 05/12/2019 06:16, S?rgio Basto wrote:
> > Sorry , I spoke too soon getent passwd "a new user to this server"
> > doesn't work .
> > But wbinfo -u or wbinfo -g always worked perfectly in any case ,
> > why
> > getent don't ?
> >
> If 'wbinfo -u' works,
2019 Nov 28
2
security = ads parameter not working in samba 4.9.5
On 28/11/2019 20:01, S?rgio Basto wrote:
> This recommendation , why ? wiki say to add it [1]
> [1]
> https://wiki.samba.org/index.php/Setting_up_a_Share_Using_Windows_ACLs#Enable_Extended_ACL_Support_in_the_smb.conf_File
Yes, but under it, in a bright orange warning box, it says this:
On a Samba Active Directory (AD) domain controller (DC), extended ACL
support is automatically
2004 Aug 04
1
R Matrix package solve
hello.
I have a query about the Matrix package for R. I wrote some code a while
ago using the Matrix package version 1.6.2 with an early version of R, to
do some linear least squares for regression:
xn
[,1] [,2] [,3] [,4]
[1,] 1 0.7429352 0.5519528 0.4100652
[2,] 1 0.7443713 0.5540886 0.4124477
[3,] 1 0.7447385 0.5546355 0.4130584
[4,] 1 0.7459597 0.5564558
2004 Jan 09
4
Erro C0000001
Hi everybody
I get it the follow error:
The System can not log on.
Between parentheses (C0000001).
What the means of this, please?
--
Gilberto Nunes
Suporte Rede Bonja - Bom Jesus/Ielusc
Fone: 433-0155 - ramal 235
www.ielusc.br - suporte@ielusc.br
Linux User n? 199930
ICQ #136176504
--
Gilberto Nunes
Suporte Rede Bonja - Bom Jesus/Ielusc
Fone: 433-0155 - ramal 235
www.ielusc.br -
2023 May 17
1
[Gluster-devel] Error in gluster v11
On Tue, May 16, 2023 at 4:00?PM Gilberto Ferreira <
gilberto.nunes32 at gmail.com> wrote:
> Hi again
> I just noticed that there is some updates from glusterd
>
> apt list --upgradable
> Listing... Done
> glusterfs-client/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
> glusterfs-common/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
> glusterfs-server/unknown 11.0-2
2023 May 16
1
[Gluster-devel] Error in gluster v11
Hi again
I just noticed that there is some updates from glusterd
apt list --upgradable
Listing... Done
glusterfs-client/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
glusterfs-common/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
glusterfs-server/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
libgfapi0/unknown 11.0-2 amd64 [upgradable from: 11.0-1]
libgfchangelog0/unknown 11.0-2 amd64