Displaying 20 results from an estimated 6000 matches similar to: "pairwise comparisons among treatments"
2009 Jan 08
1
Letter-based representation of pairwise comparisons
Hi!
I have been working several years with R but it's my first public question.
I hope I'll be clear :) .
This question is related to obtaining letter-based representation of
non-parametric pairwise comparisons.
I have a dataframe with this structure (but with quite more rows and cols):
A B C factor
1 2 2 one
2 1 2 one
2 2 3 two
2 3 2 two
1 4 2 three
9 8 1 three
I have no normality,
2002 Mar 10
1
multiple pairwise slope comparisons
Hello,
I have a linear model with different slopes for different treatment
groups. I need to pairwise compare the different slope estimates for
the different treatment groups. Is there a package that does pairwise
comparisons of slope coefficients, making the appropriate adjustments in
the P values?
Thanks,
John.
--
==========================================
John Janmaat
Department of
2004 Sep 08
1
pairwise comparisons
Hello,
I am a new R user. I am trying to calculate vector correlations for all
pairwise comparisons in my data frame without repeats. I am familiar with the
expand.grid function, but this includes repeats. Is there a way to use
expand.grid and eliminate repeats? Or is there another function that can be
used to do this?
Thank you.
Rebecca
--
Rebecca Young
Graduate Student
Ecology &
2011 Apr 13
2
setting pairwise comparisons of columns
Hi,
I have a number of genes (columns) for which I want to examine pairwise
associations of genotypes (each row is an individual)...For example (see
data below), I would like to compare M1 to M2, M2 to M3, and M1 to M3 (i.e.
does ac from M1 tend to be found with bc from M2 more often than expected.)
Down stream I will be performing chi square tests for each pair.
But I am looking for a way to
2007 Oct 19
1
conduct pairwise column comparisons without comparing a column to itself
# Hello
# I have a question regarding pairwise calculations of a matrix using a
"for-loop."
# Below I have a matrix "X" with 8 columns. These are genotypic data so
Column1 & Column2 is
# a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and
Coulmn7 & 8 is a unit.
# I have a loop designed to calculate the number of times an individual in
2006 Feb 15
2
Pairwise comparison after repeated measures ANOVA
I am analyzing some data obtained after measuring some parameters at
different times in samples obtained from many subjects. The model is
quite simple: aov(parameter ~ Time + Error(Subject/Time))
Now I want to make a pairwise comparison between the levels of Time.
However, I have not find how to do such a thing. I cannot use TukeyHSD
or pairwise.t.test, I supposse. Maybe using contrasts?
Could
2003 Jun 17
1
How to generate a pairwise non-parametric comparison table?
Dear list
I am comparing the results of several different experimental setups. With kruskal.test() I can test if there is any difference at all in any of them, if I understand it correctly. But now, when there is a difference, how do I generate a (half-) table of pairwise comparisons, using e.g. wilcox.test(), to find the ones where the difference actually occurs.
I guess I don't have to
2008 Apr 04
2
pairwise.t.test for paired data
Dear R-help, I have a question about pairwise.t.test and adjustment for
multiple comparisons for paired data points.
I have the following data:
n=c("x", "x", "x", "x", "x", "x", "x", "x", "x", "x", "y", "y",
"y", "y", "y", "y",
2013 Jan 27
3
Package: VennDiagram. Error in draw.pairwise.venn Impossible: cross section area too large
Dear list,
When I use VennDiagram package, I got a error as follow:
venn.plot <- draw.pairwise.venn(
area1 = 3186,
area2 = 325,
cross.area = 5880);
Error in draw.pairwise.venn(area1 = 3186, area2 = 325, cross.area = 588) :
Impossible: cross section area too large.
Does anyone have suggestion?
Thank you.
2008 Nov 12
2
pairwise.wilcox.test
Un texte encapsul? et encod? dans un jeu de caract?res inconnu a ?t? nettoy?...
Nom : non disponible
URL : <https://stat.ethz.ch/pipermail/r-help/attachments/20081112/618073fe/attachment.pl>
2004 Sep 15
7
Splitting vector into individual elements
Is there a means to split a vector into its individual
elements without going the brute-force route for arguments
to a predefined function call?
offred.rgb <- c(1, 0, 0) * 0.60;
## Brute force style
offred.col <- rgb(offred.rgb[1],
offred.rgb[2],
offred.rgb[3],
names = "offred")
## Desired style
2008 Jan 02
2
strange behavior of cor() with pairwise.complete.obs
Hi all,
I'm not quite sure if this is a feature or a bug or if I just fail to understand
the documentation:
If I use cor() with pairwise.complete.obs and method=pearson, the result is a
scalar:
->cor(c(1,2,3),c(3,4,6),use="pairwise.complete.obs",method="pearson")
[1] 0.9819805
The documentation says that
" '"pairwise.complete.obs"' only
2008 Apr 28
0
restricting pairwise comparisons of interaction effects
I'm interested in restricting the pairwise comparisons of interaction
effects in a multi-way factorial ANOVA, because I find comparisons of
interactions between all different variables different to interpret.
For example (supposing a p<0.10 cutoff just to be able to use this
example):
> summary(fm1 <- aov(breaks ~ wool*tension, data = warpbreaks))
Df Sum Sq Mean Sq F
2012 Feb 13
0
pairwise comparisons with multcomp package
Hi,
I've got this model and following Hothorn et al advices, I used glht for a
post hoc comparison
> modezqM<-glm(rojos~estacion*zona3,quasipoisson,subset=(edadysexo=="M"))
> anova(modezqM,test="F")
Df Deviance Resid. Df Resid.
Dev F Pr(>F)
NULL 293 41148
2012 May 11
0
Additional info: help with SMATR: help with pairwise comparisons using MA regression?
Also, this works (taking out multcomp=TRUE, multcompmethod="adjusted"):
com.test=ma(Head.W1~Leg.3.1+Site, type="elevation", data=queens)
print(com.test)
....so for some reason it will do an MA regression on all my data
point together, but shows an error when I try to do pairwise
comparisons between groups.
Thank you,
Ioulia
--------
On Fri, May 11, 2012 at 2:09 AM, Ioulia
2012 Jul 30
0
pairwise comparisons in accordance with regression fit
Hello,
I have a unconventional question arising from my current master thesis on
regression modeling. Suppose we have fitted a (linear) relationship between
a dependent variable y and an independent variable x. Now we choose two
points on the x-axis, i.e. according to percentiles x10 and x90. These two
points are chosen to select the data points for two groups in order to
perform pairwise
2010 Sep 10
2
pairwise.t.test vs t.test
Dear all, I am perplexed when trying to get the same results using pairwise.t.test and t.test.
I'm using examples in the ISwR library,
>attach(red.cell.folate)
I can get the same result for pairwise.t.test and t.test when I set the variances to be non-equal, but not when they are assumed to be equal. Can anyone explain the differences, or what I'm doing wrong?
Here's an example
2011 Apr 13
0
setting pairwise comparisons of columns (genes)
Hi,
I have a number of genes (columns) for which I want to examine pairwise
associations of genotypes (each row is an individual)...For example (see
data below), I would like to compare M1 to M2, M2 to M3, and M1 to M3 (i.e.
does ac from M1 tend to be found with bc from M2 more often than expected.)
Down stream I will be performing chi square tests for each pair.
But I am looking for a way to
2000 Jun 20
0
Pairwise comparisons/contrasts from a coxph model?
Hello,
this is probably more a statistical question than an R-specific problem, but
I'll risk it.
I've fitted a Cox Proportional hazard model with one factor Treatment (seven
levels) as a predictor variable. The general Null hypothesis (all groups
show the same survival behaviour) is clearly rejected. Now, is there any
(statistically sensible) way of doing pairwise comparisons and/or
2004 Oct 22
1
cor, cov, method "pairwise.complete.obs"
Hi UseRs,
I don't want to die beeing idiot...
I dont understand the different results between:
cor() and cov2cov(cov()).
See this little example:
> x=matrix(c(0.5,0.2,0.3,0.1,0.4,NA,0.7,0.2,0.6,0.1,0.4,0.9),ncol=3)
> cov2cor(cov(x,use="pairwise.complete.obs"))
[,1] [,2] [,3]
[1,] 1.0000000 0.4653400 -0.1159542
[2,] 0.4653400 1.0000000