similar to: factor as seq() in for loop

Displaying 20 results from an estimated 400 matches similar to: "factor as seq() in for loop"

2010 Feb 05
2
glm models with more than one response
Hi everyone, I am trying to construct a glm and am running into a couple of questions. The data set I am using consists of 6 categories for the response and 6 independent predictors representing nutrient concentrations at sample point locations. Ultimately I'd like to use the probabilities for each response category in a simulation model such that these probabilities are used to define a
2003 Jun 25
3
Help
hi my name is Tomer,im using R version 1.4 i've encontered a couple of problems with my my R programing. 1. i cant understand what is the whights in the nnet$wts command(which weight fit to the nodes). 2.my OS is Windows XP , i want to operate R from the command line and i want it to operate a file automaticly(the commands written in a text file) ,is it possible?( i know that in unix it
2003 Nov 04
1
glm offset and interaction bugs (PR#4941)
Full_Name: Charles J. Geyer Version: 1.8.0 OS: i686-pc-linux-gnu (Suse 8.2) Submission from: (NULL) (134.84.86.22) Two bugs (perhaps related, perhaps independent) revealed by the same Poisson regression with offset mydata <- read.table(url("http://www.stat.umn.edu/geyer/5931/mle/seeds.txt")) out.fubar <- glm(seedlings ~ burn01 + vegtype * burn02 + offset(log(totalseeds)),
2009 Oct 27
1
Using a variable in the formula
I am sure this question has come up, but searching hasn't given me any results. So I need to enter this line: mx1 <- randomForest(X1 ~ elevation + slope + vegtype, data = moths.train) But the problem is that X1 is currently hard coded. I would instead like to be able to put in the value of X1 through a list. For example: list <- list("X1", "X2", "X3")
2006 Oct 15
1
gamma distribution don't allow negative value in GLMs?
Dear friends, when i use glm() to fit my data, i use glm(formula = snail ~ vegtype + mhveg + humidity + elevation + soiltem, *family = Gamma(link = inverse),* data =a,)) It shows: error in eval(expr, envir, enclos) : *gamma distribution don't allow negative value*. But i use result<-glm(formula = snail ~ vegtype + mhveg + humidity + elevation + soiltem, family = poisson, data =a) #this
2003 May 22
7
extract half a matrix
Dear all, I'm new to matrix operations in R. I couln't find a solution to the following problem among earlier help mails or in An introd to R, I guess because the question is really basic. I want to extract all above the diagonal, i.e. from 1 2 3 4 1 0 26 49 49 2 26 0 44 40 3 49 44 0 21 4 49 40 21 0 I want 26 49 44 49 40 21 Thanks in advance! Sincerely, Tord
2007 Mar 19
5
order of values in vector
Dear all, I would like to get the order of the values in a vector. I have tried rank(), order() and searched the archive, though without success. Here is an example of a try x= c(20,30,50,40,60,10) cbind(sort.list(x),x) x [1,] 6 20 [2,] 1 30 [3,] 2 50 [4,] 4 40 [5,] 3 60 [6,] 5 10 but I was hoping to get this: x [1,] 2 20 [2,] 3 30 [3,] 5 50 [4,] 4 40 [5,] 6 60 [6,] 1 10 I'm
2003 Dec 07
2
par(las = 1) not possible in polymap(), library(splancs)?
Dear all, I want my PhD thesis which I hand in tomorrow to look even nicer: Does polymap in the splancs library not allow horizontal plotting of y-labels? I have tried polymap(studyarea, xlab = "x (m)", ylab = "y (m)", las = 1) but it doesn't change the labels? Mayby some function in library(spatstat) support las? Thanks! Sincerely, Tord
2003 Jan 22
3
Error when using polr() in MASS
Dear all, I get an error message when I use polr() in MASS. These are my data: skugg grupp frekv 4 1 gr3 0 5 2 gr3 3 6 3 gr3 6 10 1 gr5 1 11 2 gr5 12 12 3 gr5 1 > > summary(polr(skugg ~ grupp, weights=frekv, data= skugg.cpy1.dat)) Error in optim(start, fmin, gmin, method = "BFGS", hessian = Hess, ...) :
2003 Nov 23
4
remove 0 rows from a data frame
Dear all, As part of a larger function, I am randomly removing rows from a data frame. The number of removed rows is determmined by a Poisson distribution with a low mean. Sometimes, the random number is 0, and that's when the problem starts: My data frame: > temp occ x y dbh age 801 0 2977.196 3090.225 6 36.0 802 0 2951.892 3083.769 8 40.6 803 0 2919.111
2003 Feb 05
1
simplify a data frame
Dear all, For the past three hours I have tried simplify a data frame. I would be really happy if someone could help solving this, I'm sure simple, problem. I want to "aggregate" the data frame: ObjektID BalteNummer Baltessegment S.13 S.13.1 S.13.1.2 S.13 S.13.1 S.13.1.3 S.13 S.13.2 S.13.2.1 S.13 S.13.2 S.13.2.2 S.13 S.13.2 S.13.2.3 S.13 S.13.3 S.13.3.6 S.13 S.13.3 S.13.3.7
2002 Jan 04
4
line up a matrix
Dear all, I try to rearrange my ref. database (now in Excel!! :( ) for importing it into a reference manager program (RIS format). My file basically look like this [3,4]-matrix: rbind(c("a", "b", "c", "d"), c("e", "f", "g", "h"), c("i", "j", "k", "l")) [,1] [,2] [,3]
2003 Jul 21
2
bold AND italic as font in text()
Dear all, Is it possible to somshow plot text as italic AND bold. I tried font=c(2,3) in text(), but it doesn't work. It seems like the latter value is used. Thanks in advance! Sincerely, Tord ----------------------------------------------------------------------- Tord Sn?ll Avd. f v?xtekologi, Evolutionsbiologiskt centrum, Uppsala universitet Dept. of Plant Ecology, Evolutionary Biology
2006 Dec 27
3
counties in different colours using map()
Hi, I would like to plot a map of US counties using different colors. map() seems to be the function to use, e.g. library(maps); map('usa'); map('county', 'colorado', add=T,fill = T, col=c(1:5)) plots Colorado counties using colours 1 to 5. However, I want each color to represent a certain value - a value to be picked from a data frame. This code should show a
2003 Oct 08
2
binomial glm warnings revisited
Dear all, Last autumn there was some discussion on the list of the warning Warning message: fitted probabilities numerically 0 or 1 occurred in: (if (is.empty.model(mt)) glm.fit.null else glm.fit)(x = X, y = Y, when fitting binomial GLMs with many 0 and few 1. Parts of replies: "You should be able to tell which coefficients are infinite -- the coefficients and their standard errors will
2003 Oct 20
4
warning from return() in 1.8 but not in 1.7.0 (PR#4687)
To whom it may concern, I get the following message when I run my function: Warning message: multi-argument returns are deprecated in: return(call.fn, repl, time, from, to, last.year, occup.m, ant.occ.m, > version platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 1 minor 8.0
2003 Jul 31
2
how as.numeric() !-> factor
Dear all, I have divided two vectors: Np.occup97.98<- as.data.frame(cbind(site = levels(sums$site), Np.occup97.98 = sums$Ant.Nptrad97.98/Ant.trad$Ant.trad97.98)) > Np.occup97.98 site Np.occup97.98 1 erken97 0.342592592592593 2 erken98 0.333333333333333 3 rormyran 0.48471615720524 4 valkror 0.286026200873362 However, at a later stage of the analysis I want >
2009 Oct 23
3
opposite estimates from zeroinfl() and hurdle()
Dear all, A question related to the following has been asked on R-help before, but I could not find any answer to it. Input will be much appreciated. I got an unexpected sign of the "slope" parameter associated with a covariate (diam) using zeroinfl(). It led me to compare the estimates given by zeroinfl() and hurdle(): The (significant) negative estimate here is surprising, given
2010 Aug 19
1
GLMM random effects
Hello, I have a couple questions regarding generalized linear mixed models specifically around fitting the random effects terms correctly to account for any pseudo-replication. I am reading through and trying to follow examples from Zuur et al. Mixed Effects Models and Extensions in Ecology with R, but am still at bit unsure if I am specifying the models correctly. Background information: Our
2003 Jan 02
1
replace NA with factor class
Dear all, I have a tree data matrix. For some trees I lack info about tree species, but I want to set them to be spruce. For some reason the tree species names on the remaining (non-NA) rows are changed into numbers (that I do not recognise). I guess that ifelse is not the correct function to use, but I have not found any better one in my searches. Thanks in advance! Sincerely, Tord >