similar to: Handling dates

Hello, I'm having difficulty passing an object name to a lapply function. Can somebody tell me the trick to make this work? #Works T13702 <- TRACKDATA[["13702.xls"]][["data"]] min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1], x[1, 3])))) 16553 #Works d<-2 assign(paste("T",substr(names(TRACKDATA)[d],1,(nchar(names(TRACKDATA)[d]

The date library contains a function date.mdy that converts a number D to the date (month,date,year as a list) at D days after 1 Jan 1960. This a convention that fits in with SASs. The logic would be that the result was the date at D days after 1 Jan 1960 00:00:00 (which is a POINT in time as opposed to a date which is an interval), so that any D with 2<=D<3 was rounded to 3 Jan 1960 and

Hi everyone, I am trying to use the function as.date() from the "dates" package in R 2.10.0 to convert a character date to a Julian date, as follows: > as.date("02-MAY-01", order="mdy") # convert May 2, 2001 to a Julian date [1] 2May1 However, when trying to convert a character date from the year 2000 to a Julian date, I get an <NA> instead of the desired

I'm having a problem with output from date.mdy in the date package. Goal: to take a long vector of dates of the form "01/22/99" and extract values month="01", day="22", year="1999". I am providing the vector of class dates in the attached file to date.mdy: > mdy_dates<-date.mdy(trimmed_dates) The first few obs of the

Colleagues I want to download the package "date" from CRAN <http://cran.r- project.org/> to get the R-scripts (for version 1.2.0) *** date/INDEX *** as.date Coerce Data to Dates date.ddmmmyy Format a Julian date date.mdy Convert from Julian Dates to Month, Day, and Year date.mmddyy Format a Julian date date.mmddyyyy Format a Julian date date.object Date Objects mdy.date

I have a zooreg object and I want to be able to generate a value for seasons and 11-day composites paste it onto my zoo data frame, along with year, month and days. Right now I have the following to work from: eg. dat.zoo.mdy <- with(month.day.year(time(dat.zoo)), cbind(dat.zoo, year, month, day, quarter = (month - 1) %/% 3 + 1, dow = as.numeric(format(time(dat.zoo), "%w")))) For

Hi, I'm trying to use the date library and I think I'm getting an incorrect warning when I make a plot with plot.date(). For example: > library(date) > x <- as.date(1:100) > y <- 1:100 > plot(x, y, log = "y") Warning message: parameter "log" couldn't be set in high-level plot() function The problem appears to be in the last line of plot.date()

Dear friends. As promised ver 1.01 solved the former problem and now dates plot OK in windows. But. In the following code, "cex.axis"=0.5 works OK but "xaxp"=c(14620,14680,4) has seemingly no effect. The limits for xaxp was found from the default plot and inspecting par(). I need to put the date marks at specific points. Could I suppress them altogether and make a new xaxis

HI all, My I am trying to convert character date (mm/dd/yy) to YYYY-mm-dd date format in one of the columns of my data file. The first few lines of the data file looks like as follow head(Atest,10);dim(Atest) ddate 1 19/08/21 2 30/04/18 3 28/08/21 4 11/10/21 5 07/09/21 6 15/08/21 7 03/09/21 8 23/07/18 9 17/08/20 10 23/09/20 [1] 1270076 1 I am using the following

It seems that you have load the "survival" package date.mdy is a function from this one. In this function the "origin" of the time is the first day of 1970 in the base package the origin is the first day of 1960 it's very curious... Benjamin Esterni France From: "Vegard Andersen" <vegard.andersen@ism.uit.no> Subject: [R] Date conversion problem using

Hi, I have a set of irregular time series and i want to produce a simple plot, with dates on x axis and attribute value of y axis. This is simple enough but my x axis is divided automatically by ticks every 5 years. I would like to have a tick every year at January 1st. I am not sure how i can do that - i end up with something very close to what i want, but it is clunky and not very correct. I

I'm having problems using the date library with notched boxplots. I have separate month, day, and year columns and would like to plot the columns as a date against other variables. I have used the mdy.date(month,day,year) command before with plot(), but it doesn't seem to work with boxplot(). Instead of the dates along the x-axis, I get a list of numbers. Maybe I have the code wrong?

Hi, I'm trying to convert a vector containing dates in character format ("dd/mm/yy"): mdy.date (from date package) seems to be able to do that, but it returns to me a vector containing julian dates... but negative! for example: 16/12/03 is converted into -20470 it is because R recognizes year ../03 as 1903, instead of 2003, but how can I do to solve this problem? (of course, I

Hi, I wonder if anybody could help me in converting this easy SAS program into R. (I'm still trying to do that!) PROC IMPORT OUT= WORK.CHLA_italian DATAFILE= "C:\Documents and Settings\carleal\My Documents\REBECCA\stat\sas\All&nutrients.xls" DBMS=EXCEL2000 REPLACE; GETNAMES=YES; RUN; data chla_italian; set chla_italian;

Hello, I am trying to convert calendar dates (Month, Day, Year) into Julian Days   Product code Bureau of Meteorology station number Month Day Year Date_mdy Date 4102001 70014 1 1 1939 1/01/1939 1/01/1939 4102001 70014 1 2 1939 1/02/1939 2/01/1939 4102001 70014 1 3 1939 1/03/1939 3/01/1939 4102001 70014 1 4 1939 1/04/1939 4/01/1939 4102001 70014 1 5 1939 1/05/1939 5/01/1939 4102001 70014 1 6

> > > Dear All, > > > > I am currently using R for windows. > > > > I am wondering why the dates command in chron package does not work in the > > following situation: > > > > cut(dates(c(23,45,67),origin=c(1,1,2004)),"months") > > > > but will work for: > > > >

Dear R users, I have a column with dates (character) in a data frame: 12-Jan-01 11-Jan-01 10-Jan-01 9-Jan-01 8-Jan-01 5-Jan-01 and I need to convert them to (Julian) dates so that I can sort the whole data frame by date. I thought it would be very simple, but after checking the documentation and the list I still don't have something that works. 1. as.Date returns the error below. What am I

survexp in survival5 doesn't seem to work for me. see below: > library(survival5) Attaching Package "package:survival5": The following object(s) are masked from package:base : sort.list > library(chron) > data(ratetables) > survexp(~ratetable(year=julian(6,1,1991), + sex=1,age=35*365.24),times=(0:30)/6*365.24) Error in as.character(as.date(c(min(R[, 3]),

xyplot doesn't seem to want to label my x-axis with dates but instead puts the day-number for each date. begdate is the number of days since January 1, 1960 and was initially created by library(date) ... polls$begdate<-mdy.date(begmm,begdd,begyy) I create a new dataframe (pollstack) which includes begdate. In the process begdate seems to lose its date attribute so I redo it as: >

> Dears users, > I'm trying to run R on a computer with OS X. I installed the R folder > and the dylibs, where they must be installed. I updated my path, and > R runs but tells me : > > dyld: /usr/local/R-1.4.0/lib/R/bin/R.bin version mismatch for > library: /usr/lib/libz.1.dylib (compatibility version of user: 1.1.3 > greater than library's version: 1.0.0)