similar to: display of a loess fitted surface

Good evening, I am Marta Colombo, student at Milan's Politecnico. Thank you very much for your kindness, this mailing list is really useful. I am using the function kde2d for two-dimensional kernel density estimation and I'd like to know something more about this kind of density estimator. In particular I'd like to know: what bandwidth is used ? Thank you in advance for your attention

Good evening,I am Marta Colombo, student of "Politecnico di Milano". I'm studying Local Regression Techniques such as loess, smoothing splines and kernel smoothers. Choosing "symmetric" for the argument "family" in loess function it is possible to produce a robust estimate , in function smooth.spline and ksmooth I didn't find this possibility. Well, is there a

Hi! I am Marta Colombo, student in Mathematical Engineering at "Politecnico di Milano". For my master degree thesis I have to analyze some categorical data. My dataset is composed by 327 individuals and 16 variables. I am using Fisher exact test to test independence on IxJ contingency tables, but I have a problem with one variable. R gives me this error message: FEXACT error 7.

Good evening, I am Marta Colombo, student at Milan's Politecnico. Thank you very much for your kindness, this mailing list is really useful. I am using the function kde2d for two-dimensional kernel density estimation and I'd like to know something more about this kind of density estimator. In particular I'd like to know: what bandwidth is used ? Thank you in advance for your attention

Good evening, I am Marta Colombo, student of the "Politecnico" in Milan and I'm looking for some help.I'd like to know how I can see R-Squared using loess because in the output there are only: number of observations equivalent number of parameters residual standard error and even looking at the summary I wasn't able to find it. Thank you very much for the attention, Marta

To my understanding, a confidence interval typically covers a single valued parameter. In contrast, a confidence band covers an entire line with a band. In regression, it is quite common to construct confidence and prediction bands. I have found that many people are connecting individual confidence/prediction interval values produced with predict(object,sd.fit=T,type="conf/pred") and

I'm trying to find a bootstrap based confidence band for a linear model. I have created a data set with X and Y X=runif(n,-1.25,1.25) e=rnorm(n,0,1) Y=exp(3*X)+5*sin((30*X)/(2*pi))+2*e fit=lm(Y~X) summary(fit)   I define a bootstrap function named PairedBootstrap which is not listed here. Than I try many ways to find the confidence band. One way is to predict Y using the model I get above for

Hi all. I hope I have my terminology right here... For a simple lm, one can add ?pointwise confidence bounds? to a fitted line using something like >predict(results.lm, newdata = something, interval = "confidence") (I'm following DAAG page 154-155 for this) I would like to do the same thing for a glm of the logistic regression type, for instance, the example in MASS pg

Carlos, mi intencion es entender el codigo: https://github.com/woobe/blenditbayes/blob/master/2013-06-street-level-crime/analysis.R Para luego hacer mi trabajo, algo similar a esto, pero adaptado a mi región. Si te fijas en las lineas 141-161, esta esto: ## Convert the base map into a ggplot object ## All added Cartesian coordinates to enable more geom options later on map.ggmap <-

Para este ejemplo especifico: Deseo saber si tmp genera un objecto ggplot > tmp <- ggplot(mtcars, aes(x = hp, y=mpg)) + geom_point() El objecto o variable tmp, devuelve una lista y un gráfico, la clase dice ser ggplot, >class(tmp) [1] "gg" "ggplot" > typeof(tmp) [1] "list" El 30 de enero de 2014, 13:00, daniel

Hello, I am a newbie in R, I just did my first function, which works!!! And I would like to know, if I can create a directory in the library with my functions, in a way, which I could call that like we call the packages ? Can anyone help me? Thanks in advance Marta ><((((?>`?.??.???`?.?.???`?...?><((((?>`?.??.???`?.?.???`?...?><((((?>

Daniel, Disculpa si no entiendo, pero, entonces un objecto ggplot en en realidad una función y no un gráfico El 30 de enero de 2014, 11:09, Marta Garcia <marta000garcia@gmail.com>escribió: > Sí, devuelve Error: No layers in plot, no le he agregado capas > por eso el error, la funcion me dice que es un gráfico > > > El 30 de enero de 2014, 10:31, José María Mateos

Dear all, Is there a way to plot / calculate pointwise confidence bands or interval values for a non parametric regression like sm.regression? Thank you in advance. Regards, Martin

Just trying to create returns from prices, and do something like: returns.z = tail(prices.z,-1)/head(prices.z,-1) - 1 # should be equivalent to returns = exp(diff(log(prices.z))) - 1 Curiously, I get a zoo object back with zeros everywhere and also with the index having one fewer element than it should. Does anyone know how to pointwise divide zoo objects, and what exactly "/" is

Marta, Seguramente, al desconocer tu objetivo, no te servirá de mucho lo que te diga. No se si quieres escribir un paquete para mapas o simplemente hacer un mapa con la librería ggmap sin preocuparte de la magia interna. Si lo que necesitas es lo segundo puede que te sirva el siguiente ejemplo: http://journal.r-project.org/archive/2013-1/kahle-wickham.pdf

Hi there, I had written a library under R 1.9.0 and now I would like to import that library under R 2.0.1 Apparently it does not work; I can install the package, but when I try to read it the error is the following: Error in library(compvar) : 'compvar' is not a valid package -- installed < 2.0.0 I have checked other libraries in R 2.0.1 and I noticed that there is a new folders

Hi all, I am trying to execute Xserver on Dom0 but an error occurres. I have a fresh Debian Lenny install. I''ve installed Xen via aptitude, restarted the system with Xen kernel, and then installed xfce4 with all dependencies. When i try startx i get this errors: (WW) RADEON; No matching Device section for instalnce (BusID PCI:4:0:1) found Fatal server error: xf86MapVidMem:

Hola Daniel, si perdona di a responder directamente y no me di cuenta. Ya se donde esta el error, pero queria preguntar si a puede ser que mi R funcione mal o algo porque esta manhana ejecute mi script y funciono perfectamente y ahora volvi a ejecutarlo y me volvio a dar el mismo problema de ayer , despues de reiniciar y demas el tinnR y el R, no se si me vacila o es que tengo algo mal en

Hola, Tengo la version R 3.1, estoy intentado usar este script pero me dice que el simbolo " no tiene que estar ahi, ya intente borrando comillas o diferentes formas y no lo consigo, si alguien sabe agradezco ayuda. setwd("C:/users/marta/desktop/DB") library(chron) library(xlsx) filename<-"univerest_50.csv" filename<-"monicap_50.csv"

Hi, Suppose a=matrix(1:9,3,3) > a [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 Now, > class(a[1:2,]) [1] "matrix" > class(a[1:3,]) [1] "matrix" > class(a[,1:2]) [1] "matrix" > class(a[,1:3]) [1] "matrix" But, > class(a[1,]) [1] "integer" > class(a[,1]) [1]