Displaying 20 results from an estimated 300 matches similar to: "predict nbinomial glm"
2012 Sep 04
5
Associations and Math between Models
I''ve setup two models, 1 and 2, that are associated by
has_and_belongs_to_many. I''m trying to get an attribute from model_1 to use
in a method in model_2. When I use the code below, I get an error saying
''undefined method model_1_id''. What am I missing? Thanks!
Model_2.rb
Class Model_2 < ActiveRecord::Base
...
has_and_belongs_to_many :model_1
def
2005 Aug 15
1
error in predict glm (new levels cause problems)
Dear R-helpers,
I try to perform glm's with negative binomial distributed data.
So I use the MASS library and the commands:
model_1 = glm.nb(response ~ y1 + y2 + ...+ yi, data = data.frame)
and
predict(model_1, newdata = data.frame)
So far, I think everything should be ok.
But when I want to perform a glm with a subset of the data,
I run into an error message as soon as I want to predict
2009 Jun 26
1
Alternate error structures in lme4?
Hi R users,
The nlme library enabled several alternate error structures useful for
longitudinal or repeated-measures data. For example, a continuous AR(1)
process:
model_2 = update(model_1, correlation = corCAR1(form = ~ time | subject))
Does anybody know if this is available in lme4?
Thank you
Ben
--
View this message in context:
2008 Apr 27
1
parallel max, min, and median of dataframe columns
Hello, all,
I have a dataframe of three rows and umpteen columns. I want to show the
maximum, minimum, and median with a vertical line and a central dot (I'd
use a boxplot, but with only three data points, that's overkill; I can't
just use points, because of overlap and some of the other data plotted on
the graph).
This works:
> boxplot(data_frame,
2008 Aug 13
1
need help with stat functions(like adaboost, random forests and glm)
Ok, so basically I have a dataframe named data_frame
data_frame contains:
startdate
startprice
endpricethreshold1
endpricethreshold2
endpricethreshold3
all of these endpricethresholds are true/false binary vectors. They are
true or false depending on whether the endprice was above or below whatever
the endpricethreshold is.
now I want to try to use lets say the general linear model to have
2006 Jan 24
1
No scientific notation in format
Hi
I have a data.frame with the following numbers (first column are month
numbers)
07,0,0,0,0.315444056314174,0,0,0,12.5827462764176,0.079194498691732,
0.0280828101707015,0,0.0695808222378877
08,0,0,105600,0.393061160316545,0,0,0,8.95551253153947,0.0880023174276553,
0.285714285714286,0,0.0669139911789158
09,0,0,0,0,12.5,0,0,13.5135887094281,0.0557531529154668,0,0,
0.0487526139182026
2006 Aug 26
1
problems with loop
Dear all,
I am trying to evaluate the optimisation behaviour of a function. Originally
I have optimised a model with real data and got a set of parameters. Now I
am creating simulated data sets based on these estimates. With these
simulations I am estimating the parameters again to see how variable the
estimation is. To this end I have written a loop which should generate a new
simulated data
2012 Jan 01
1
empty files created with trellis xyplot jpeg device
New years greetings.
I have been setting up a function to generate multiple jpeg charts. When
the calls are issued at the interactive console, the jpeg files are
generated without an issue. When I try to issue the same calls from a
function, some chart files are empty. It appears to only be related to
trellis charts. Any help to troubleshoot this is appreciated.
Regards,
-mike
R version
2002 Mar 02
1
accessing factor levels from C
Hi,
I am trying to get information about factors from a C-program. As I see,
the factors are basically integers with attribute ,,levels''. But
unfortunately I am not been able to read the levels information. I am
using:
SEXP variable, levels;
...
variable = VECTOR_ELT( data_frame, j);
switch( TYPEOF( variable)) {
case INTSXP:
if( isFactor( VECTOR_ELT( data_frame,
2006 Jul 28
2
negative binomial lmer
To whom it may concern:
I have a question about how to appropriately conduct an lmer analysis for negative binomially distributed data. I am using R 2.2.1 on a windows machine.
I am trying to conduct an analysis using lmer (for non-normally distributed data and both random and fixed effects) for negative binomially distributed data. To do this, I have been using maximum likelihood,
2017 Nov 08
2
Ggplot error
Hello,
I've an error recently.
ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line()
Error: Found object is not a stat.
> sessionInfo()
R version 3.4.2 (2017-09-28)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 16.04.3 LTS
Matrix products: default
BLAS: /usr/lib/openblas-base/libblas.so.3
LAPACK: /usr/lib/libopenblasp-r0.2.18.so
locale:
[1] LC_CTYPE=tr_TR.UTF-8
2017 Nov 08
0
Ggplot error
I was not able to reproduce this problem. I tried two environments
1. Ubuntu 14.04.5 LTS, R version 3.4.2 (same R version as yours)
2. Windows 10, same R version
On Wed, Nov 8, 2017 at 9:50 AM, Zeki ?ATAV <zcatav at gmail.com> wrote:
> Hello,
> I've an error recently.
>
> ggplot(data = mtcars, aes(x= wt, y= mpg)) + geom_line()
> Error: Found object is not a stat.
>
2009 Jul 02
3
Testing for membership in an array of strings
As an R beginner, I feel brain dead today as I can not find the answer
to a relatively simple question.
Given a array of string values, for example lets say "mary", "bob",
"danny", "sue", and "jane".
I am trying to determine how to perform a logical test to determine if
a variable is an exact match for one of the string values in the array
2010 Aug 17
3
Weird differing results when using the Wilcoxon-test
Hi,
I became a little bit confused when working with the Wilcoxon test in R.
As far as I understood, there are mainly two versions:
1) wilcox.test{stats}, which is the default and an approximation, especially,
when ties are involved
2) wilcox_test{coin}, which does calculate the distribution _exactly_ even,
with ties.
I have the following scenario:
#---BeginCode---
# big example
size = 60
2017 Nov 08
1
Ggplot error
I get the same result as Eric? withR version 3.4.2 (2017-09-28)
Platform: x86_64-pc-linux-gnu (64-bit)
Running under: Ubuntu 17.04
It looks like you have "tidyverse" loaded so I tried it with just ggplot2 loaded and with tidyverse loaded.?
On Wednesday, November 8, 2017, 4:16:14 AM EST, Eric Berger <ericjberger at gmail.com> wrote:
I was not able to reproduce this
2009 Mar 18
1
error with effects package.
Dear R helpers,
I have the following model
model_1<-glm(y~A+B+C+E+A:D,contrasts=list(D=contrasts_D),data=mydata,na.action=na.omit)
with: options(contrasts=c("contr.sum", "contr.poly"))
A,B and E are 2-levels factor,
C is covariate,
D is 20 levels factor with 10 in relation with the first levels of
factor A, the other in relation with the second levels of factor A
2001 Dec 19
2
R strings from C
Hi,
I am trying to study R internal behaviour. So long, I have not
succeeded to access the value of R strings from C.
I use:
void salvesta_tabel(
SEXP data_frame,
SEXP file
)
{
printf( "nimi %d\n", (R_CHAR)( file));
}
and from the R side:
salvesta.tabel <-
function (x, file = "") {
.Call( "salvesta_tabel", x, file)
}
When calling
2007 Jun 05
4
Refactor all factors in a data frame
Hi all,
Assume I have a data frame with numerical and factor variables that I
got through merging various other data frames and subsetting the
resulting data frame afterwards. The number levels of the factors seem
to be the same as in the original data frames, probably because subset()
calls [.factor without drop = TRUE (that's what I gather from scanning
the mailing lists).
I wonder if
2005 Feb 23
3
bias of a boot statistic
Question:
How can I get access to the bias value of a boot statistic?
Details:
Boot function:
boot(data, statistic, R, sim="ordinary", stype="i",
strata=rep(1,n), L=NULL, m=0, weights=NULL,
ran.gen=function(d, p) d, mle=NULL, ...)
When I create an object, containing the bootstrap statistic (object <- boot
(....))I can call it and will get an output
2017 Sep 04
1
Dataframe Manipulation
Hello Ulrik,
Can you please explain this code means how and what this code is doing
because I'm not able to understand it, if you can explain it i can use it
in future by doing some Lil bit manipulation.
Thanks
data_help <-
data_help %>%
mutate(Purchase_ID = 1:n()) %>%
group_by(Purchase_ID) %>%
do(split_items(.))
cat_help %>% gather("Foo",