Displaying 20 results from an estimated 3000 matches similar to: "Why only a "" string for heading for row.names with write.csv with a matrix?"
2010 Jul 02
3
Knowledge discovery
Hi,
I have 100000 units with 10 attributes (attr1, attr2, attr3, etc...)
For instance:
unit attr1 attr2 attr3 ...
1 a ww 12
2 a re 11
3 b ww 09
4 c yt 02
5 a qw 02
...
I'd like to answer to the question:
a) what are the most frequent combinations of attributes?
b) How could I describe the relations
2010 Jun 01
2
Help on aggregate method
Dear R experts,
I would really appreciate if you had an idea on how to use more
efficiently the aggregate method:
More specifically, I would like to calculate the mean of certain
values on a data frame,? grouped by various attributes, and then
create a new column in the data frame that will have the corresponding
mean for every row. I attach part of my code:
matchMean <-
2009 Sep 18
1
inconsistency in attaching attributes to NULL
In R-devel (svn 49628) and back to at least R 2.7.0 we get
inconsistent results when attempting to attach attributes to
a variable with the value NULL.
If we use attributes<- it finishes but changes the value to list().
> a<-NULL
> attributes(a)<-list(attr1="First attribute", attr2=2+2i)
> a
list()
attr(,"attr1")
[1] "First
2006 Jan 05
2
Confused...
Ok,
So, I''ve got two data tables associated through a foreign key.
class Child < ActiveRecord::Base
belongs_to :parent, :class => Parent, :foreign_key => "parent_id"
# also has attr1, attr2
end
class Parent < ActiveRecord::Base
has_many :children, :class => Child, :foreign_key => "parent_id"
end
So, I''m trying to build the new/edit
2011 May 25
1
Subtracting rows by id
Dear R users,
I have two datasets:
id1 <- c(rep(1,10), rep(2,10), rep(3,10))
value1 <- sample(1:100, 30, replace=TRUE)
dataset1 <- cbind(id1,value1)
id2 <- c(1,2,3)
subtract.value <- c(1,3,5)
dataset2 <- cbind(id2, subtract.value)
I want to subtract the number of rows in the subtract.value that
corresponds to the id value in dataset1. So for the 1 in id1, I want
to
2012 Jan 04
1
AR update / create pattern: is there an easier way?
I find myself writing the following frequently:
r = MyActiveRecord.where(:attr1 => cond1, :attr2 => cond2, ...)
r.exists? ? r.first : r.create
... which has the effect of returning an instance of MyActiveRecord if
all the conditions are met, or creating one if it doesn''t. A variant of
this:
c = MyActiveRecord.new(:attr1 => val1, :attr2 => val2, ...)
r =
2012 Apr 14
3
Choose between duplicated rows
Dear r experts,
Sorry for this basic question, but I can't seem to find a solution?
I have this data frame:
df <- data.frame(id = c("id1", "id1", "id1", "id2", "id2", "id2"), A =
c(11905, 11907, 11907, 11829, 11829, 11829), v1 = c(NA, 3, NA,1,2,NA), v2 =
c(NA,2,NA, 2, NA,NA), v3 = c(NA,1,NA,1,NA,NA), v4 = c("N",
2013 Apr 12
1
Removing rows that are duplicates but column values are in reversed order
Hi,
From your example data,
dat1<- read.table(text="
id1?? id2?? value
a????? b?????? 10
c????? d??????? 11
b???? a???????? 10
c????? e???????? 12
",sep="",header=TRUE,stringsAsFactors=FALSE)
#it is easier to get the output you wanted
dat1[!duplicated(dat1$value),]
#? id1 id2 value
#1?? a?? b??? 10
#2?? c?? d??? 11
#4?? c?? e??? 12
But, if you have cases like the one
2008 Jul 09
2
Parsing
Dear R users,
I have a big text file formatted like this:
x x_string
y y_string
id1 id1_string
id2 id2_string
z z_string
w w_string
stuff stuff stuff
stuff stuff stuff
stuff stuff stuff
//
x x_string1
y y_string1
z z_string1
w w_string1
stuff stuff stuff
stuff stuff stuff
stuff stuff stuff
//
x x_string2
y y_string2
id1
2011 Apr 25
2
Problem with ddply in the plyr-package: surprising output of a date-column
Hi Together,
I have a problem with the plyr package - more precisely with the ddply
function - and would be very grateful for any help. I hope the example
here is precise enough for someone to identify the problem. Basically,
in this step I want to identify observations that are identical in
terms of certain identifiers (ID1, ID2, ID3) and just want to save
those observations (in this step,
2010 Sep 07
1
average columns of data frame corresponding to replicates
Hi Group,
I have a data frame below. Within this data frame there are samples
(columns) that are measured more than once. Samples are indicated by
"idx". So "id1" is present in columns 1, 3, and 5. Not every id is
repeated. I would like to create a new data frame so that the repeated
ids are averaged. For example, in the new data frame, columns 1, 3,
and 5 of the original
2007 Apr 20
2
Fastest way to repeatedly subset a data frame?
Hi -
I have a data frame with a large number of observations (62,000 rows,
but only 2 columns - a character ID and a result list).
Sample:
> my.df <- data.frame(id=c("ID1", "ID2", "ID3"), result=1:3)
> my.df
id result
1 ID1 1
2 ID2 2
3 ID3 3
I have a list of ID vectors. This list will have anywhere from 100 to
1000 members, and
2011 Nov 12
1
With an example - Re: rbind.data.frame drops attributes for factor variables
When I use rbind() or rbind.data.frame() to add a row to an existing
dataframe, it appears that attributes for the column of type "factor" are
dropped. See the sample example below to reproduce the problem. Please
suggest How I can fix this.
Thanks,
Sammy
a=c("Male", "Male", "Female", "Male")
b=c(1,2,3,4)
c=c("great", "bad",
2006 Sep 13
3
group bunch of lines in a data.frame, an additional requirement
Thanks for pointing me out "aggregate", that works fine!
There is one complication though: I have mixed types (numerical and character),
So the matrix is of the form:
A 1.0 200 ID1
A 3.0 800 ID1
A 2.0 200 ID1
B 0.5 20 ID2
B 0.9 50 ID2
C 5.0 70 ID1
One letter always has the same ID but one ID can be shared by many
letters (like ID1)
I just want to keep track of the ID, and get
2005 Nov 09
3
dataframe without repetition
Hello,
with a data.frame like this :
> toto <-
data.frame(id=c("id1","id1","id2","id3","id3","id3"),dpt=c("13","13","34","30","30","30"))
> toto
id dpt
1 id1 13
2 id1 13
3 id2 34
4 id3 30
5 id3 30
6 id3 30
what is the most efficient ways to obtain :
id
2008 Jan 10
1
data.frame manipulation: Unbinding strings in a row
Hi all,
I have a data.frame I received with data that look like this (comma
separated strings in last row):
ID Shop Items
ID1 A1 item1, item2, item3
ID2 A2 item4, item5
ID3 A1 item1, item3, item4
But I would like to unbind the strings in col(2) items so that it will look
like this:
ID Shop Items
ID1 A1 item1
ID1 A1 item2
ID1 A1 item3
ID2 A2 item4
ID2 A2 item5
ID3 A1 item1
ID3 A1 item3
ID3 A1
2012 Feb 22
1
Lattice and horizontally stacked density plots
Hello,
I am try to make a density plot where plots are stacked like the one
found here:
http://dsarkar.fhcrc.org/lattice/book/images/Figure_14_03_stdBW.png
I am facing problems, however. Using the code example below, I'd like
to generate a separate panel for each val of id2. Within each panel,
I'd like to have individual histograms each on separate lines based on
the value of id1. ?Note
2009 Dec 10
1
problem with data processing in R
Hi,
I'm stuck with parsing data into R for heatmap representation.
The data looks like:
1 id1 x1 x2 x3 .... x20
2 id1 x1 x2 x3 .... x20
3 id1 x1 x2 x3 .... x20
4 id1 x1 x2 x3 .... x20
.........
348 id2 x1 x2 x3 .... x20
349 id2 x1 x2 x3 .... x20
350 id2 x1 x2 x3 .... x20
351 id2 x1 x2 x3 .... x20
.........
The data is sorted for the IDs (id1,id2 .....id40) and I like to
2011 Apr 20
1
How to check if a value of a variable is in a list
Hi all,
I am working with some social network analysis in R and ran into a problem I
just cannot solve.
Each observation in my data consists of a respondent, some characteristics
and up to five friends. The problem is that all of these five friends might
no show up later as a respondent (observation). Therefore I might not have
characteristics on all the friends listed in the data and I want to
2008 Sep 25
2
How to order some of my columns (not rows) alphabetically
Hello,
I have a dataframe with 9 columns, and I would like to sort (order) the
right-most eight of them alphabetiaclly, i.e.:
ID1 ID2 F G A B C E D
would become
ID1 ID2 A B C D E F G
Right now, I'm using this code:
attach(data)
data<-data.frame(ID1,ID2,data[,sort(colnames(data)[3:9])])
detach(data)
but that's not very elegant. Ideally I could specify which columns to
sort and