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hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

Thks for your answer, here is an exemple of what i do with the errors in french... > tmp [1] 200 150 245 125 134 345 320 450 678 > beta18 Erreur : Objet "beta18" not found //NORMAL just to show it > eta [1] 500 > func1<-function(beta18) dweibull(tmp[1],beta18,eta) > func1<-func1(beta18) * function(beta18) dweibull(tmp[2],beta18,eta) Erreur dans dweibull(tmp[1],

Hi all, I have some some problem with regard to finding the integral of a function containing an indicator function. please see the code below: func1 <- function(x, mu){ (mu^2)*dnorm(x, mean = mu, sd = 1)*dgamma(x, shape=2)} m1star <- function(x){ integrate(func1, lower = 0, upper = Inf,x)$val} T <- function(x){ 0.3*dnorm(x)/(0.3*dnorm(x)+0.7*m1star(x))} func2 <-

On Wed, Jan 10, 2018 at 5:21 AM, James Y Knight <jyknight at google.com> wrote: > > On Fri, Jan 5, 2018 at 9:58 PM, Ryan Prichard via llvm-dev < > llvm-dev at lists.llvm.org> wrote: > >> 2. *Termination landing pads.* >> >> Clang sometimes uses a landing pad that calls __clang_call_terminate to >> terminate the program. GCC instead leaves a gap in

Hi all, I have some some problem with regard to finding the integral of a function containing an indicator function. please see the code below: func1 <- function(x, mu){ (mu^2)*dnorm(x, mean = mu, sd = 1)*dgamma(x, shape=2)} m1star <- function(x){ integrate(func1, lower = 0, upper = Inf,x)$val} T <- function(x){ 0.3*dnorm(x)/(0.3*dnorm(x)+0.7*m1star(x))} func2 <-

hi all I wish to thanks every body on the R mailing list for answering very fast, directly in my mail box ;). I've finish my work with R and i can say that it is very difficult at the beginning, and when you succeed you are stopped by a stack overflow when you call your nice recursive function (which was working with a tab of 100 element) with a tab of 900 elements, but R just do what you

Folks, A small group of us are working together to develop a set of R functions to support data management and analysis using Eclipse/StatET in a Windows environment. We are using Git/EGit for version control. We work within our own repository and occasionally push to a common remote location. I'd like to have the code source files from the 'local' git repository without

hi all, I need to generate a function inside a loop: tmp is an array for (i in 1:10) { func<- func * function(beta1) dweibull(tmp[i],beta1,eta) } because then i need to integrate this function on beta. I could have written this : func<-function(beta1) prod(dweibull(tmp,beta1,eta)) (with eta and beta1 set) but it is unplottable and no integrable... i could make it a bit different but

Dear List: I have the following simple program: x<- sample(site) VarGuilda1<- var(tapply(x,site,func1)) VarGuilda2<- var(tapply(x,site,func2)) VarGuilda3<- var(tapply(x,site,func3)) VarGuilda4<- var(tapply(x,site,func4)) VarGuilda5<- var(tapply(x,site,func5)) VarGuilda6<- var(tapply(x,site,func6)) VarGuilda7<- var(tapply(x,site,func7)) VarGuilda8<-

Hi all, i'm new to R, I need to modelize in R a statistic algorithm, This algo use Weibull, normal law, linear regression, normalisation, root mean square, to find eta and beta fitting the weibull model (to analyse few results) and further when we will get more information apply bayes model . the problem is when When i try to integrate it fails with errors. by the way i like to integrate

Hi all I have a problem pertaining to local and global variables. Say I have a function defined as follows: a<-function(x) {y<x^2} i.e a(2) [1] 4 function b is now defined to take the value of y and do some manipulation with it. As it stands I dont know how to store the variable y such that other functions are able to reference its value. I know that I

Hi all i need to put on one graph 2 functions who's x axis is the same and y not. I mean on horizontal the time, and on vertical left: pressure, on vertical right: rpm of a motor, is R able to do that? i've found this that i could adapt maybe (i don't need time series really?) :/ : (http://tolstoy.newcastle.edu.au/R/help/04/03/1456.html) ## ## Description: A simple function which

hy all, I wish to switch in a part in my code that use "read.table" to "scan", actually i use this: tab<-scan("data.dat",what=integer(),skip=1) dim(tab)<-c(75,length(tab)/75) tab<-t(tab) It gives me a new tab with 75 columns, but i when i was using read.table with headers then attach i could use the columns names to access the data values, now how can i

Hy all, I wish to use the date function to draw againt the lifetime of a motor. This lifetime is given to me in Hours (it can go over 5000 hours) I'm unable to find how to convert this lifetime value to something like %H:%M:%S because when R see 24H it says 1 day, i don't want that, i just want %H:%M:%S with a value of %H higher than 24... for example: i've got this value in hours:

hi all Here is a small part of my code: tab_tmp<-tab[1:(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])),length(tab)]; tab_tmp1<-tab[(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])):length(TotalFillTimeHours),length(tab)]; tab<-c(tab_tmp,tab_tmp1); attach(tab); Here is the output: Error in attach(tab) : attach only works for lists and data frames Execution halted

On Fri, Jan 5, 2018 at 9:58 PM, Ryan Prichard via llvm-dev < llvm-dev at lists.llvm.org> wrote: > 2. *Termination landing pads.* > > Clang sometimes uses a landing pad that calls __clang_call_terminate to > terminate the program. GCC instead leaves a gap in the call site table, > and the personality routine calls std::terminate. For the 4MB > libQt5Core.so sample I'm

Hi, my name is Guilherme and I'm trying to solve an optimization problem in R, regarding reliability and survival time of equipments. I Have to write the function in the image attached to this email, please take a look, where the f(t) is weibull's distribution density function, Ca=1000 and Cb=100 are costs of two equipments and i'm using shape=2.5 and scale=20. However, a few problems

Hi all I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong... > hist.Date(dt_cycles) Error: couldn't find function "hist.Date" > hist.date(dt_cycles) Error: couldn't find function "hist.date" > cycles [1] 7 1

Greetings all- I'd like to install Oreka on a Centos 5.x server for monitoring my Asterisk systems(using port mirroring) but I find I'm having problems with the version of libpcap installed. The latest is 0.9.4 but the orkaudio RPM (built for Centos 4.2) requires libpcap 0.8.3. I've tried making symlinks to overcome the issue but with no success. Without having to build Oreka from

Hello folks, I wanted to setup Oreka to monitor calls on a trixbox box I have setup. Oreka doesn't seem to be catching all of the calls though.... I have port mirroring setup on the port that trixbox is connected to, mirrored to the port Oreka is connected to. I have read that Asterisk doesn't work as a SIP Proxy, so I wondered if this meant that some phones, after checking in with