similar to: normalise a function

Thks for your answer, here is an exemple of what i do with the errors in french... > tmp [1] 200 150 245 125 134 345 320 450 678 > beta18 Erreur : Objet "beta18" not found //NORMAL just to show it > eta [1] 500 > func1<-function(beta18) dweibull(tmp[1],beta18,eta) > func1<-func1(beta18) * function(beta18) dweibull(tmp[2],beta18,eta) Erreur dans dweibull(tmp[1],

Hi all, i'm new to R, I need to modelize in R a statistic algorithm, This algo use Weibull, normal law, linear regression, normalisation, root mean square, to find eta and beta fitting the weibull model (to analyse few results) and further when we will get more information apply bayes model . the problem is when When i try to integrate it fails with errors. by the way i like to integrate

hi all I wish to thanks every body on the R mailing list for answering very fast, directly in my mail box ;). I've finish my work with R and i can say that it is very difficult at the beginning, and when you succeed you are stopped by a stack overflow when you call your nice recursive function (which was working with a tab of 100 element) with a tab of 900 elements, but R just do what you

hi all, I need to generate a function inside a loop: tmp is an array for (i in 1:10) { func<- func * function(beta1) dweibull(tmp[i],beta1,eta) } because then i need to integrate this function on beta. I could have written this : func<-function(beta1) prod(dweibull(tmp,beta1,eta)) (with eta and beta1 set) but it is unplottable and no integrable... i could make it a bit different but

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

hi all, I wish to draw on the same graphic device 3 functions. But i don't want them to be on different graph, i want to compare them on the same I don't need mfrow or mfcol, I need something else... 1 graph on 1 device inside this graph 3 ploted function. I saw something unsing data.frame, but i think it's overkill, and something less complicated must exist, if not why? why not

Hi all i need to put on one graph 2 functions who's x axis is the same and y not. I mean on horizontal the time, and on vertical left: pressure, on vertical right: rpm of a motor, is R able to do that? i've found this that i could adapt maybe (i don't need time series really?) :/ : (http://tolstoy.newcastle.edu.au/R/help/04/03/1456.html) ## ## Description: A simple function which

hi all Here is a small part of my code: tab_tmp<-tab[1:(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])),length(tab)]; tab_tmp1<-tab[(no[off_set[i-1]+1]+(no[off_set[i]+1]-no[off_set[i-1]+1])):length(TotalFillTimeHours),length(tab)]; tab<-c(tab_tmp,tab_tmp1); attach(tab); Here is the output: Error in attach(tab) : attach only works for lists and data frames Execution halted

hy all, I wish to switch in a part in my code that use "read.table" to "scan", actually i use this: tab<-scan("data.dat",what=integer(),skip=1) dim(tab)<-c(75,length(tab)/75) tab<-t(tab) It gives me a new tab with 75 columns, but i when i was using read.table with headers then attach i could use the columns names to access the data values, now how can i

Hy all, I wish to use the date function to draw againt the lifetime of a motor. This lifetime is given to me in Hours (it can go over 5000 hours) I'm unable to find how to convert this lifetime value to something like %H:%M:%S because when R see 24H it says 1 day, i don't want that, i just want %H:%M:%S with a value of %H higher than 24... for example: i've got this value in hours:

Hi all I wish to draw an histogram... with dates but the following append, i don't know where is the problem, help(hist.Date) works and i don't see any usefull information on what i'm doing wrong... > hist.Date(dt_cycles) Error: couldn't find function "hist.Date" > hist.date(dt_cycles) Error: couldn't find function "hist.date" > cycles [1] 7 1

Hy all I use barplot to draw frequencies by dates. On the x axis it shows only 1 date for 2 bars, i've understand why, because R cant put so much date on the same axis, it will get out of the graph. that's why i tought about reducing the size of the font used to stamp the x axis. anyone knows the right way? i've tryed par(cin) and barplot(cin=3) but it says i cannot do it at this

hi all, I load a table with headers that enable me to acces it by the column names: tab<-read.table("blob/data.dat",h=T) attach(tab) everythings are OK, but i try to sort this table against one of his column like this: tab<-tab[order(tab$IndexUI),]; It is still ok, the table is sorted, if i type "tab" i see a sorted table. but, when i call the column by their names,

Hi all, Before the amount of data given has grown i was initially using read.table to load the values inside R. It was feeding my needs because i could tell read.table h=T, then use attach to access the values by columns names. Now it takes 20 seconds to load the data's and the first enhancement i could do is to win some time on the load of the data's... How could i use the scan

hi all, I've got a data frame, this data frame have 76 columns and 22600 rows. The data inside can be redundant because the data can be captured simultaneously and overlap each other. My aim is to supress these overlaps I've test some solutions to do that but they all give a big cpu load and eat all of the memory then swap a lot, then killall R because it don't end. actually

I have done a fair bit of spectral analysis, and hadn't finished collecting my thoughts for a reply, so hadn't replied yet. What exactly do you mean by normalize? I have not used the functons periodogram or spectrum, however from the description for periodogram it appears that it returns the spectral density, which is already normalized by frequency, so you don't have to worry about

hy all I wish to draw a graph against a date, I have a set of date like this DD/MM/YYYY, corresponding to it a set of integer , i wish to draw on x side the dates (the space between the dates have to be constant, not based on the time between 2 dates but on the number of dates) and on y side the integers. Do i have to make a tricky function under R ? I've search the help for graphical

Env: R 2.8.1, Win Xp, Eclipse/StatET In a .Rd file, I have an example containing the lines: # calculate Y M, using polynomial contrasts trends <- as.matrix(VocabGrowth) %*% poly(8:11, degree=3) colnames(trends)<- c("Linear", "Quad", "Cubic") [At the risk of a long message, I'll append the complete .Rd file at the end of this message, in case this was

*Hi all,* * * *The following is my general idea for the project. For a complete query parser I still need to consider more details. Please give me feedback because the description of this project is lack of detailed information, and I can submit my proposal without giant deviation.* * * design principle of query parsing: 1) better understanding user input. All search engine do is understanding

Greetings all- I'd like to install Oreka on a Centos 5.x server for monitoring my Asterisk systems(using port mirroring) but I find I'm having problems with the version of libpcap installed. The latest is 0.9.4 but the orkaudio RPM (built for Centos 4.2) requires libpcap 0.8.3. I've tried making symlinks to overcome the issue but with no success. Without having to build Oreka from