similar to: Where to learn how to deal with time class variable?

Hi,all I only got the time data such as: tms<-c("19:30:23","18:39:10".....) I want to manipulate this time series data. For example, plus one second(or minute) or minus one second This data only has the time(h:m:s), without the date. I know that there are chron package, ISOPix class and the timeDate class, but all these class need the input of date. How can we

Hello, today I've updated on the newest R-Version. But sadly a function I needed didnt want to work: The input is e.g. days(as.Date("21-07-2005","%d-%m-%y")) the error is: Fehler in Math.Date(dts): floor nicht definiert f??r Date Objekte (Error in Math.Date(dts): floor not defined for date objects) Same for year. Only months gives me the correct output. In Version

note: whole function is below- I am sure I am doing something silly. when I use it like USGS(input="precipitation") it is choking on the precip.1 <- subset(DF, precipitation!="NA") b <- ddply(precip.1$precipitation, .(precip.1$gauge_name), cumsum) DF.precip <- precip.1 DF.precip$precipitation <- b$.data part, but runs fine outside of the function: days=7

Man, R has a steep learning curve (but I suppose you all know this). I have very little programming knowledge, so when I search for answers to my questions, I struggle with making sense of a lot of the pages. I have a spreadsheet that I've read into R using read.csv. I've also attached it. It looks like this (except there are 1600+ entries): > Sunday SunDate SunTime

Look at the bottom of the message for my question #here is a little function that I wrote USGS <- function(input="discharge", days=7){ library(chron) library(gsubfn) #021973269 is the Waynesboro Gauge on the Savannah River Proper (SRS) #02102908 is the Flat Creek Gauge (ftbrfcms) #02133500 is the Drowning Creek (ftbrbmcm) #02341800 is the Upatoi Creek Near Columbus (ftbn) #02342500 is

Hello, I gather variants of this question have been asked previously. I have done some reading but only became more confused, as I suspect what I am trying to do is more basic than other applications. The following code readily calculates the difference in days between two dates: newdays <- ISOdate(2005, 5,12) - ISOdate(2006, 12, 22) However, I wanted to be able to deduct the dates in

Not sure if there is an R way to do this or a regular express way, but here is what I am trying to do. I've got lots of data where the format is HH:MM:SS, but I need to format it like HH:MM:00, i.e. round the second down to zero. What is the best way to do this? Thanks again. Jason

Hello, I'm trying to plot dayly evolution of the temperature over France from Global Forecast System files ("I'm trying" is the right expression...). akilonlat03 is the temperature for different latitudes and longitudes ? 3 o'clock. akilonlat06 is the temperature for different latitudes and longitudes ? 6 o'clock. I would like to plot akilonlat03 and then akilonlat06

Apparently, as.POSIXlt takes one o'clock as the start of the day : > as.POSIXlt(0,origin="1970-01-01") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 00:00:00") [1] "1970-01-01 01:00:00 CET" > as.POSIXlt(0,origin="1970-01-01 23:59:59") [1] "1970-01-02 00:59:59 CET" Cheers -- Joris Meys Statistical

I decided my earlier email on this topic was rather long and wordy; here's a condensed version. I am sitting at a Solaris computer in the US/Pacific timezone. I have a file of data having times that includes the following three values 2002-4-7 1:30:00 GMT 2002-4-7 2:30:00 GMT 2002-4-7 3:30:00 GMT I have not been able to find a way to correctly convert these to either of the POSIX

Hi, I'm a bit confused how julian() works. If I understand right, it returns the number of days since the origin. I have a vector: > SLDATX[1:10] [1] "1986-01-06" "1986-01-17" "1986-02-02" "1986-02-04" [5] "1986-02-04" "1986-02-21" "1986-03-06" "1986-03-25" [9] "1986-04-06"

Hi, In voicemail.conf: ; Supported values: ; 'filename' filename of a soundfile (single ticks around the filename ; required) ; ${VAR} variable substitution ; A or a Day of week (Saturday, Sunday, ...) ; B or b or h Month name (January, February, ...) ; d or e numeric day of month (first, second, ..., thirty-first) ; Y Year ; I or l

Hi all, I would like to start replacing the realmedia content on a clients web site with the Ogg format. The client (a national tv/radio station) publishes alot of content and have integrated their CMS with the Realmedia system in order to index multimedia with story lines. Eg the following link would be published inside a RAM file to point to the start and end times of a story from the 6

Hey, I'm new to R but familiar with other programming languages. Basically, I want to store an array of dates. For each of these dates I want to store only the day of the week and the hour. So for example: "Monday 12" would be Monday at 12 o'clock and "Tuesday 20" would be Tuesday at 8 p.m. Alternatively it could be stored as 0-6 for Sunday to Saturday. So Tuesday

Hi all, I have a question concerning xyplot. My data is a data.frame looking like that: In the first column I have numbers from 0 to 23 (hours of a day), the second column contains the name of a weekday (Day as factor) and the third column contains the number I am interested in. So as an example, the first five rows look like that: Hour Day Freq 1 0 Mo 23 2 1 Mo

I think the following examples illustrate the crux of the matter (version and OS info are below). The problem has to do with the transition from standard time to daylight savings time. My timezone, US/Pacific, has two parts: standard time (PST) 8 hours behind GMT and daylight savings time (PDT) 7 hours behind GMT. The transition takes place this year on 7 April at 02:00, when 02:00 is

Dear R-helpers, I have the following data: y happenat x 5185 (07/22/05 00:05:14) 14 5186 (07/22/05 00:15:14) 14 5187 (07/22/05 00:25:14) 14 5188 (07/22/05 00:35:14) 14 ...... I want to choose between 07/25/05 15:30:00 and 07/26/05 12:30:00. Anybody had experience in handling this kind of data? Is there a simple way to subset by the variable

The bug exists on R-1.9.0-alpha compiled the 10/3. Termplot has a problem if either the model only contains a single term or if asked to plot a single term. In addition there are problems with the option se = TRUE. Analysis: termplot starts with terms <- if (is.null(terms)) predict(model, type = "terms", se = se) else predict(model, type = "terms", se = se,

Hello, Can anyone help me out with this problem? After performing logistic regressions and testing the significance with likelihood ratios, I have plotted the results using "termplot". I am wondering, how to get the names of my variables to appear on the x-axis rather than ascending numbers? I have used: termplot(fm, se=T, axes=FALSE, col.se="black") axis(1, 1:4,

Thanks, chdir dir /data error seems go away, but at 12:00 o'clock the following error appear: Feb 20 11:45:03 brulx01 vsftpd: Mon Feb 20 11:45:03 2006 [pid 12273] [job260] OK DOWNLOAD: Client "10.90.1.1", "/data/mde/DATA/.././ACTUAL/mdeact260.msg", 12481 bytes, 174.76Kbyte/sec Feb 20 11:56:10 brulx01 smbd[12410]: [2006/02/20 11:56:10, 0]