similar to: Polar Graph

hello, to use the function plot3d, i should use the package R.basic! plot3d {R.basic} If people know exactly a site to load this package, please give me the URL! Thanks Sabine --------------------------------- [[alternative HTML version deleted]]

Hi, I would like to know the similarity between variables, but I don't exactly how begin and as from what dataframe or matrix! I have a matrix where in row I have 'Good', 'Medium','Bad' and in columns I have my Criterions ! What function and package should I use? Thanks a lot Sabine --------------------------------- ils, photos et vidéos ! [[alternative

Is it possible to do a graphic in 3D? This is my source: but this one is on 2D and at moment variables put on other variables, so it is difiicult to differentiate them visibly. plot(corresp(data,nf=2),xlim=c(-1,1),ylim=c(-1,1)); Thanks Sabine --------------------------------- ils, photos et vidéos ! [[alternative HTML version deleted]]

Hello, I've got a problem in a sql query! for(j in 1:length(criteria$Title)) { graphe_par<-sqlQuery(channel,"select q.type,crit.Title, r.Value from criteria crit, reply r,question_reply qr, question q, question_criteria qc, form_question fq where qr.reply=r.ID and qr.question=q.ID and qc.question=q.ID and crit.ID=qc.criteria and fq.question=q.ID and fq.form=4 and

Hello, I would like to know if it's possible to modify the name of groups of bar because on my barplot2, I have 5 groups of bars and one of them is called "User Contributes" and when I save the plot "User contributes" is to big so I don't have it on my plot! Is it pssible to put the name vertically! Thanks! Sabine --------------------------------- ils, photos

Hi, I would to get the first letter of a word like: > title_cat TitleCat 1 Training I would like T from Training! Thnaks a lot for your help Sabine --------------------------------- T侀l侀chargez le ici ! [[alternative HTML version deleted]]

hi, My code: data<-matrix(data=c(0.425,0.5,0.75,0.125,0.25,0.475,0.375,0.25,0.625,0.5,0.1,0.125,0,0.25,0.25),nrow=3,ncol=5,byrow=TRUE, dimnames=list(c("Good","Medium","Bad"),c("Content","Logistic","Trainer","Supply","User contribution"))) plot(corresp(data,nf=2),xlim=c(-1,1),ylim=c(-1,1)); The plot is

Hi, I would like to write text on 2 lines for example. For example, if you have a long sentence and you want to cut it at the 45 caracter and put the continuation underneath! Is it possible? Thanks Sabine --------------------------------- [[alternative HTML version deleted]]

hi, is it possible to create a matrix with one row and according to add a row? in fact, at present, I'm doing an algorithm which fill a matrix. On the web site of CRAN, the package basic is impossible to be load! can you tell me where i can found it! Thanks Sabine --------------------------------- [[alternative HTML version deleted]]

Dear R users, The Sweave code below runs fine, as it is. However, an error occurs when the line 'library(xtable)' is uncommented: Error: chunk 1 Error in "label<-"(`*tmp*`, value = "month") : no applicable method for "label<-" Is anybody aware of this and knows a workaround? Thanks, Sander. *******************

Dear R users, Could somebody tell me why the grey color ramp is repeated in this graph, eventhough the ramp values go from 0 to 1? I must be missing something obvious, but I can not see it! z <- c(0.064329041,0.117243316,0.161565116,0.19923015,0.231642175,0.259835539,0.284571226, 0.038507288,0.094184749,0.140959431,0.180803984,0.215159105,0.245096084,0.271412845,

Hi -- I have searched the documentation and archives on graphing capabilities in R for the past couple of hours, but I haven't been able to find anything directly related to my problem. I want to create a plot with several lines displayed on it. I want each line to be displayed in a different color, so it seems the only way to do this is to create a plot and then use the lines() function.

Hi, I would like to know if people have found the package made4 to load! I would like the .zip If you have the @ on internet to load it please give me it! Thanks a lot, Sabine --------------------------------- [[alternative HTML version deleted]]

Hello, On my barplot, I have on the axis y, the names of the rows of my matrix r_mat! is it possible to change the color of these names on my barplot? barplot2(t(r_mat),beside=TRUE,horiz=TRUE,plot.grid=TRUE,xlab="R",font.lab=4,las=2,xlim=c(0,1)) thanks, Sabine --------------------------------- [[alternative HTML version deleted]]

Dear all, We have a large data set with temperature data for weather stations across the globe (15000 stations). For each station, we need to calculate the number of days a certain temperature is exceeded. So far we used the following S code, where mat88 is a matrix containing rows of 365 daily temperatures for each of 15000 weather stations: m <- 37 n <- 2 outmat88 <- matrix(0,

hi list, i have to ask you again, having tried and searched for several days... i want to do a TukeyHSD after an Anova, and want to get the adjusted p-values after the Tukey Correction. i found the p.adjust function, but it can only correct for "holm", "hochberg", bonferroni", but not "Tukey". Is it not possbile to get adjusted p-values after

Hi, I would like to compare 2 lists resulted from a sql query! bu there are different levels, so when I want to do: release1<-sqlQuery(channel,paste("select distinct c.ID,c.Title TitleCrit from category cat, category_criteria cc, criteria c, question_criteria qc, question q, form_question fq, form f, release_form rf, release r, product_release pr, product p where cat.ID=cc.category and

ich hätte ein problem: im rahmen meiner projektarbeit stehe ich vor der aufgabe, einen beliebigen datensatzt einzulesen, die empirische verteilungsfunktion des datensatztes zu zeichnen, aber das ganze so, dass die y-achse nach der quantilsfunktion der exponetialverteilung mit parameter=1 transformiert werden soll! leider steh ich da jetzt wirklich an! würde mich serh freuen, wenn mir jemand

Dear all, I have a data frame containing the results of an experiment. Like this: a<-seq(1,4,by=1) b<-seq(1,2,by=1) test<-expand.grid(b,a,a) colnames(test)<-c("replicates","bins", "groups") test$abc <- rnorm(32) test$def <- rnorm(32) test$ghi <- rnorm(32) test The following code snippet aggregates the data for one variable and then draws a

Hi: Is there any function in R which can convert the long/lat to UTM(Universal Transverse Mercator)? There are quite a few converters on Internet. However, the interface is designed as input->output which I can not convert lots of locations at the same time. Another question is whether there is a function in R which can tell the time zone from the location's lat/long? Thank you!