similar to: histogramm?

hello, i am using the hist function with classified values. The class breaks are >1, so histogram$density is != 1. How to plot the histogram with freq=FALSE and the real class density values. I used: > h2 = hist(value, breaks = breaks_vector) > h2$density = round(h2$counts/sum(h2$counts), 2) > h2$intensities = h2$density > plot(h2, freq=F) but this isn't the best way, i

Hello My data looks ugly in a normal histogramm. How can I create a histogramm with a Y-axis in log-scale? Thanks for your help! David Graf --

Hi, My question is in the subject. Here, a picture that's illustrating my problem : http://r.789695.n4.nabble.com/file/n3248321/graph.png This figure comes from an article published in Cancer Cell by K.E. Gascoigne and S.S. Taylor in 2008. Thanks you very much and sorry for my English. -- View this message in context:

thank you for your answer i checked my code and it now works One more question... do you know how to have an 3D histogramm from a known matrix of probabilities Cline >From: "David Barron" <mothsailor at googlemail.com> >To: "C?line Henzelin" <celine_appui at hotmail.com>, r-help ><r-help at stat.math.ethz.ch> >Subject: Re: [R] (no subject)

Hi, i get no success change the title of the "fill" (colour) legend and the defintion of "levels". Have anybody a hint how i can do this. df <- data.frame(variable=sample(c("A","B","C"),1000,replace=T,prob=c(0.22,0.28,0.5)),group=gl(2,500)) p <- ggplot(df, aes(x = variable)) p + geom_histogram(aes(y= ..count.. /

Hello! I'm not sure if this is an german list, so I will post in english. I'm using R on my gentoo linux and now I got an spss .sav file. I found that r has a function like read.spss("file.sav") but when I try this I get the Error: couldn't find function "read.spss". Can anyone tell me what's going wrong? Thanks for your help, Martin

I think there are a couple of things in ?hist that are not quite as clear as they could be. (1) freq: logical; if 'TRUE', the histogram graphic is a representation of frequencies, the 'counts' component of the result; if 'FALSE', _relative_ frequencies ("probabilities"), component 'density', are plotted. Defaults to

Hi, list, I am using 'sgeostat' package by Albrecht Gebhardt and I am trying to put a correlation coefficient of some kind on the lagplots. Is there a possiblity to do so? Thanks Mahdi -- ----------------------------------- Mahdi Osman (PhD) E-mail: m_osm at gmx.net ----------------------------------- GMX im TV ... Die Gedanken sind frei ... Schon gesehen? Jetzt Spot online ansehen:

Hello, Im reading through some manuals, but I cannot find my answer. I have a file containing many data: Vpn Code Family Age F1 F2 ... F17 1 1 M 46 1 2 ... 1 2 1 D 18 3 2 ... 4 3 2 M 50 3 3 ... 3 ... and so on. Now I can read it by: F = read.table("file", header=T) but now I want to seperate the mothers (M) and daugthers (D) of the family with all the data in all other fields.

Hello, I'm a newbie on this list. I have a R code but its execution take a very long time. Is it possible to compile it (in C for example) to decrease the execution time ? -- ---------------- Alexandre DEPIRE INRETS / GARIG

Hello, I'm a newbie on this list. I have a R code but its execution take a very long time. Is it possible to compile it (in C for example) to decrease the execution time ? -- ---------------- Alexandre DEPIRE INRETS / GARIG

Hello, I develop some R package on Linux machine with C subroutines. The programs in C are well compiled on Linux machine and so I have some ".so" files. Now, I want to do the same work on windows, so I install R (the last version) on windows, with Active Perl and djgpp, which is, as I know, the gcc version for windows (to compile C program), but unfortunately when I run "R CMD

Hi there. I have now found that dist() does what I want in a specific case. But I have (out of many fields) in my Fragebogen.data file: Vpn Code Family Test 1 X1 m 45 2 X1 t 58 3 X2 m 44 4 X2 t 43 ... When I now do: Fbg <- read.table("Fragebogen.data", header=TRUE) dist(Fbg['Test']) I have the distances between everyone to everyone. Now I want to have the mothers (m in

Hello, I can plot histogrammes but I want to know how can I do to plot 2 histogrammes at the same time (in the same window). hist(as.numeric(as.character(B[,1])),col="lightblue", border="pink") hist(as.numeric(as.character(A[,1])),col="yellow", border="pink") thanks. _____________________________________________________________________________ l

Dear All, I am a undergraduate using R for the first time. It seems like an excellent program and one that I look forward to using a lot over the next few years, but I have hit a very basic problem that I can't solve. I want to produce a standardised histogram, i.e. one where the area under the graph is equal to 1. I look at the manual for the histogram function and find this: freq:

To whom it may concern, I have a problem concerning the design of a histogram. How do I change the border widths of the bars of a histogram. The initial command is: hist (punkte,breaks=30, xlab="Punkte", ylab="H?ufigkeit", main="Histogramm", col= heat.colors(30), border= "red") I suspect that it has to do with the "lwd" command but can't

Dear alltogether, I experience very strange behavior of imputation of NA's with the NORM library. I use R 2.2.0, win32. The code is below and the same dataset was also tried with MICE and aregImpute() from HMISC _without_ any problem. The problem is as follows: (1) using the whole dataset results in very strange imputations - values far beyond the maximum of the respective column, >

Hi, I'm a R newbie and I have a supervised 2-class classification problem. To find out the best representation of my data (dim = 45). I want to perform LDA und QDA on the diffrent data representations to find out, which is best to discriminate the 2 sets. For LDA there exists a method plot.lda shows (in the 2 class case) a histogramm of the data, projected onto the linear discriminants (pleas

Dear colleague, unfortunately 'rnorm' does not create normal distributed numbers as you can see with following histogramm: > hist(rnorm(1000000),breaks=100) and > hist(pnorm(rnorm(1000000)),breaks=100) I have done several chi^2-tests which have all failed: > chi2unif<- function(x,N) > { > anz=length(x) > f0<-rep(anz/N,times=N) >

Hi list, this is my second try for first post on this list (I tried to post via email and nothing appeared in my email-inbox, so now I try to use the nabble-web-interface) - I hope that you will only have to read one post in your inbox! Okay, my question ... I was able to plot a histogram and add the density()-line to this plot. I was able to plot a cumulative form of this histogram. Yet, I was