similar to: issues with identical()

Dear all, I would be pleased if anyone could help me. The Rhelp description for the figs parameter is "a two-element vector describing the number of rows and colunns in a screen matrix". So, why does my code (below) produce a 2x1 screen matrix instead of a 1x2 one? Thanks in advance, rodrigo. ----------------------------------------------------------- plot.new()

On Wed, May 24, 2017 10:45 am, Warren Young wrote: > On May 24, 2017, at 8:52 AM, Chris Adams <linux at cmadams.net> wrote: >> >> Once upon a time, Warren Young <warren at etr-usa.com> said: >>> a. It???s transmitting from a fixed location in a time zone you >>> probably aren???t in ??? US Mountain ??? being the least populous of >>> the lower

[Going a bit off-topic here, and going to do a bit of a deep-dive on RF stuff, but maybe it will be useful to Chris] On 05/24/2017 12:20 PM, Valeri Galtsev wrote: > It is insightful, yet... There are a bunch of other factors that may need > to be taken into account. Angular transmission pattern of satellite (horn? > or is it yagi? antenna) vs ground based (monopole? or dipole? antenna -

I'm trying to use a paper by Hardin & Rocke: http://handel.cipic.ucdavis.edu/~dmrocke/Robdist5.pdf as a guide for a function to identify outliers in multivariate data. Attached below is a function that is my attempt to reproduce their method and also a test to see what fraction of the data are identified as outliers. Using this function I am able to reproduce their results regarding the

Hi all, Here I am trying to implement the switch() function to choose value of a variable depending on the value of an input variable :   temp1 <- "1"               temp1.name <- switch(temp1,                                   1 == "aa",                                   2 == "bb",                                   3 == "cc",

Dear all, I'm trying to gsub() "%" with "\%" with no obvious success. > temp1 <- c("mean", "sd", "0%", "25%", "50%", "75%", "100%") > temp1 [1] "mean" "sd" "0%" "25%" "50%" "75%" "100%" > gsub("%",

this is a bad question but I can't figure it out and i've tried. if i sort the 2 column matrix , temp1, by the first column, then things work as expected. But, if I sort the 1 column matrix, temp2, then it gets turned coerced to a vector. I realize that I need to use drop=FALSE but i've put it in a few different places with no success. Thanks. temp1 <-

I am using R 2.1.1 in an windows XP environment. I have 2 dataframes, temp1 and temp2. Each dataframe has 20 variables (“cocolumns") and 525 observations (“rows”). All variables are numeric. I want to create a new dataframe that also has 20 columns and 525 rows. The values in this dataframe should be the sum of the 2 other dataframe. (i.e. temp1$column

i'm sorry. i had an error in my previous code because i left out a letter in the rownames. while fixing that, i also found a solution. so i'm sorry for the confusion. below is my fix. temp2 <- matrix(rnorm(10),nc=1,nrow=10) rownames(temp2) <-

Hi, I have a data.frame that is date ordered by row number - earliest date first and most current last. I want to create a couple of new columns that show the max and min values from other columns *so far* - not for the whole data.frame. It seems this sort of question is really coming from my lack of understanding about how R intends me to limit myself to portions of a data.frame. I get the

It seems that MASS suggest to judge on the basis of sum(residuals(mode,type="pearson"))/df.residual(mode). My question: Is there any rule of thumb of the cutpoiont value? The paper "On the Use of Corrections for Overdispersion" suggests overdispersion exists if the deviance is at least twice the number of degrees of freedom. Are there any further hints? Thanks. -- Ronggui

I stumbled onto this working on an update to coxph. The last 6 lines below are the question, the rest create a test data set. tmt585% R R version 2.12.2 (2011-02-25) Copyright (C) 2011 The R Foundation for Statistical Computing ISBN 3-900051-07-0 Platform: x86_64-unknown-linux-gnu (64-bit) # Lines of code from survival/tests/singtest.R > library(survival) Loading required package: splines

R-help - I have this set of aggregated tables (sample data below via dput()). And I would like to have delayValue as the column variables with the "temp" (temp1, temp2, temp3) values as the row variables. However I would like to have the temp variables *aggregated into single rows* so that I have the frequency ("Freq" | counts) of each time each "delayValue" occurs

HI Irucka, Please check this: temp<- structure(list(`:Bostoncitydata` = structure(list(Month = c(1L, 2L, 3L, NA), Data1 = c(1.5, 12.3, 11.4, NA), Data2 = c(9.1342, 12.31, 3.5, NA)), .Names = c("Month", "Data1", "Data2"), class = "data.frame", row.names = c(NA, -4L)), `:Chicagocitydata` = structure(list(Month = c(1L, 2L, 3L, 4L, 5L, NA), Data1 = c(1.52,

Hi Irucka, I tried it and was able to plot it without any errors.? Here, your code indicates you need two lines. temper[[i]][1] ?temper[[1]][1] # which is the column 1. ? Month 1???? 1 2???? 2 3???? 3 ?temper[[1]][2] #? Data1 #1?? 1.5 #2? 12.3 #3? 11.4 Suppose I use names(temper) instead of seq_along(temper) pdf("irucka.pdf") ?lapply(names(temper),function(i)

Okay, someone explain this behaviour to me: Browse[1]> replace(rep(0, 4000), temp1[12] , temp2[12])[3925] [1] 0.4462404 Browse[1]> temp1[12] [1] 3926 Browse[1]> temp2[12] [1] 0.4462404 Browse[1]> replace(rep(0, 4000), 3926 , temp2[12])[3925] [1] 0 For some reason, R seems to shift indices along when doing this replacement. Has anyone encountered this bug before? It seems to crop up

Given an x-vector with, say, 3 elements, I would like to compute the following vector of permutated products (1-x1)*(1-x2)*(1-x3) (1-x1)*(1-x2)*x3 (1-x1)*x2*(1-x3) x1*(1-x2)*(1-x3) (1-x1)*x2*x3 x1*(1-x2)*x3 x1*x2*(1-x3) x1*x2*x3 Now, I already have the correctly sorted matrix of permutations! So, the input looks something like: #input x<-c(0.3,0.1,0.2) Nx<-length(x) Ncomb<-2^Nx

Dear R-help, I have a character vector, some elements will be numeric, some not, and some even empty. E.g.: temp1 <- c("abcd"," 2 ","") I'm only interested in the numeric elements, the rest I can just throw away. It is easy enough to loop through the vector: temp <- try(eval(parse(text=temp1[1])), silent=TRUE); class(temp) # try-error temp <-

Hi, > temp1[1:6,] AAAA_XXX BBBBBB_XXX CCCCC_XXX DDDDD_XXX EEEEE_XXX SkHep1_XXX 50 0.75285 0.30630 0.56330 0.45755 0.49665 0.74685 63 0.35930 -0.22725 0.04725 0.53955 0.56390 0.51170 69 -1.57515 -1.67610 -1.61695 -1.11685 -0.00085 -1.89155 91 0.84640 0.43595 0.62350 0.46645 0.09430 1.03985 136 0.42050 0.42340 0.61730 0.13950 -0.57600

Hi, temp3<- read.table(text=" ID CTIME WEIGHT HM001 1223 24.0 HM001 1224 25.2 HM001 1225 23.1 HM001 1226 NA HM001 1227 32.1 HM001 1228 32.4 HM001 1229 1323.2 HM001 1230 27.4 HM001 1231 22.4236 #changed here to test the previous solution ",sep="",header=TRUE,stringsAsFactors=FALSE) ?tempnew<- na.omit(temp3) ?grep("\\d{4}",temp3$WEIGHT) #[1] 7 9 #not correct