similar to: reason for na.last=TRUE in rank

Dear R-help readers, In R 1.8.1 it was easy to print the documentation for recommended packages: go to the full reference manual (refman.pdf) and print the relevant pages, which were contiguous. With R 1.9.0 some of those packages (e.g. "ts") have become part of the "stats" package, and hence their documentation is scattered throughout that of the other component packages of

dear list, i am having trouble coloring the bars in a barplot. my data have two groups, which i would like to plot side by side. within each group i want to sort the observations in decreasing order, like a pareto chart. the bar colors would relfect the value of a third variable. below i have generated a reproducible example. the bar heights are a given pig's "gain",

A question for R (and perhaps S and SPlus) historians. Does anyone know the reason for the inconsistency in the way that the action that should be taken when data are missing is specified? There are several variants, na.action, na.omit, "T", TRUE, etc. I know that a foolish consistency is the hobgoblin of a small mind, but consistency can make things easier. My question is not meant

dear expeRts, i would like to merge the data frame entries in a list. for example: > #input > myl <- list(q1=data.frame(id=c("Alice", "Bob"), grade=c(90, 49)), q2=data.frame(id=c("Alice", "Chuck"), grade=c(70, 93)), q3=data.frame(id=c("Bob", "Chuck"), grade=c(84, 40))) > #output > (mydf <-

Hi. I am using R 2.3.1 on WIndows XP, and I am having trouble with the rank function in the presence of numerical NA data. I want the NA's all to get the same rank, but they don't. Here is an example from my session: >ct_align_rets_f2$liq[6851:6859] [1] 115396 NA 362595 NA 242986 340805 NA 692905 251533

In asp you have an Application built-in object, which works just like the Session hash, but it lets you share information among all users of a given application. which is the rails equivalent??? and if there isn''t, how would you implement such a thing ? (there would be concurrency issues to take into account, in fact asp''s application object has some lock and unlock methods

dear r-helpers, it seems the colors in an automatically generated lattice legend recycle after the 8th color, even when the user has set e.g. superpose.symbol$col to be longer than 8. the following example will illustrate what i mean: z <- data.frame(x=rep(letters[1:15], each=4), y=rnorm(60), groups=rep(LETTERS[1:3], 20)) library(nlme) library(lattice) plot(groupedData(y ~ x |

Hi, I ran into a problem where I actually need rank(, ties.method="last"). It would be great to have this feature in base and it's also simple to get (see below). Thanks & cheers, Marius rank2 <- function (x, na.last = TRUE, ties.method = c("average", "first", "last", # new "last" "random", "max",

Marius Hofert-4------------------------------ > Den 2015-10-09 kl. 12:14, skrev Martin Maechler: > I think so: the code above doesn't seem to do the right thing. Consider > the following example: > > > x <- c(1, 1, 2, 3) > > rank2(x, ties.method = "last") > [1] 1 2 4 3 > > That doesn't look right to me -- I had expected > > >

Does sort.int(c(2,NA,4), index.return=TRUE, na.last=NA, method="radix")$ix give the intended result, because I get: > sort.int(c(2,NA,4), index.return=TRUE, na.last=NA, method="radix") $x [1] 2 4 $ix [1] 1 3 With method="shell" and method="quick" in R devel, I get: > sort.int(c(2,NA,4), index.return=TRUE, na.last=NA, method="shell") $x

I've installed fail2ban, it seems to be working as it identified my failed test logins, BUT, my question is: what can I do when I see same invalid name trying to login to dovecot, different IP each time, how can I say block each IP as used by this name ? or it that a bad idea ? I can see two persistent attempts as so: I don't have such user 'ignacio' or 'julian' # grep

Does anyone have any ideas how I could do a power calculation for a log rank test. I would like to know what the suggested sample sizes would be to pick a difference when the control to active are in a ratio of 80% to 20%. Thanks Dan -- ************************************************************** Daniel Brewer, Ph.D. Institute of Cancer Research Email: daniel.brewer at icr.ac.uk

Hi, I'm trying to set up a prediction software, now i testing the performance of my method, so i need to calculate a ROC curve, specially auc, cut-off, sens and spec, i just looking at ROCH package, but it's a mass for me, i'm not a math guy and I'm getting lost Could any of you recommend me an easy-to-use package to do this task? i just have a list of positive/negative samples

I have not been able to find a way to do dense rank in R Here is an example of what I need rank() gives the following 5 rank 1 7 rank 2 7 rank 2 9 *rank 4* but I want 5 rank 1 7 rank 2 7 rank 2 9 *rank 3* * * thanks SS [[alternative HTML version deleted]]

SAS proc rank has ties options of high and low that would allow producing ranks of the type found in the sports pages, e.g., rank (c(1,1,2,2,2,2,3)) == 1 1 3 3 3 3 7 Could R support these ties.methods?

Hi I'm working in a ubuntu feisty OS, when I try to start X11() i get the following message > X11() Error in X11() : could not find any X11 fonts Check that the Font Path is correct. In addition: Warning messages: 1: locale not supported by Xlib: some X ops will operate in C locale 2: X cannot set locale modifiers > Can some body tell me what to do? -- Pau Marc Muñoz Torres

Hi, I have noticed different rank values calculated by qr() depending on LAPACK parameter. When it is FALSE (default) a true rank is estimated and returned. Unfortunately, when LAPACK is set to TRUE, the min(nrow(A), ncol(A)) is returned which is only occasionally a true rank. Would not it be more consistent to replace the rank in the latter case by something based on the following pseudo code ?

Does anyone know why the two rank functions gives different results? I need to use the rank function in a "for" loop, so the sequence to be ranked is given values in the form of part (1). How can I use assignment like in part (1) to get correct ranks as in part (2)? Thank You Part (1) i<-1.94 b<-0.95-i c<-1.73-i d<-2.62-i y<-c(0.68,0.95,b,c,d) y 0.68 0.95 -0.99

Dear R-developers, I just realized that rank() behaves inconsistent if combining one of na.last in {TRUE|FALSE} with a ties.method in {"average"|"random"|"max"|"min"}. The documentation suggests that e.g. with na.last=TRUE NAs are treated like the last (=highest) value, which obviously is not the case: > rank(c(1,2,2,NA,NA), na.last = TRUE, ties.method

What is the easiest way to calculate a percent rank “by” an index key? Foe example, I have a dataset with 3 fields: Year, State, Income , I wish to calculate the rank, by year, by state. I also wish to calculate the “percent rank”, where I define percent rank as rank/n. (n is the number of numeric data points within each date-state grouping.) This is what I am